Jalisa Earned $\$71.25$ Today Babysitting, Which Is $\$22.50$ More Than She Earned Babysitting Yesterday. The Equation $d + 22.50 = 71.25$ Can Be Used To Represent This Situation, Where $d$ Is The Amount Jalisa

Introduction

In this article, we will delve into the world of mathematics and explore a real-life scenario involving Jalisa's babysitting earnings. We will use algebraic equations to represent the situation and solve for the unknown variable, $d$, which represents the amount Jalisa earned babysitting yesterday.

The Problem

Jalisa earned $\$71.25$ today babysitting, which is $\$22.50$ more than she earned babysitting yesterday. We can represent this situation using the equation $d + 22.50 = 71.25$, where $d$ is the amount Jalisa earned babysitting yesterday.

Understanding the Equation

The equation $d + 22.50 = 71.25$ is a linear equation, which means it can be represented as a straight line on a coordinate plane. The equation is in the form of $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept. In this case, the equation can be rewritten as $d = 71.25 - 22.50$.

Solving for $d$

To solve for $d$, we need to isolate the variable $d$ on one side of the equation. We can do this by subtracting $22.50$ from both sides of the equation. This will give us the value of $d$, which represents the amount Jalisa earned babysitting yesterday.

d = 71.25 - 22.50
print(d)

Calculating the Value of $d$

When we run the code above, we get the value of $d$ as $\$48.75$. This means that Jalisa earned $\$48.75$ babysitting yesterday.

Conclusion

In this article, we used algebraic equations to represent a real-life scenario involving Jalisa's babysitting earnings. We solved for the unknown variable $d$, which represents the amount Jalisa earned babysitting yesterday. By using the equation $d + 22.50 = 71.25$, we were able to isolate the variable $d$ and calculate its value as $\$48.75$.

Real-World Applications

This type of problem can be applied to various real-world scenarios, such as:

• Calculating the cost of goods sold
• Determining the profit or loss of a business
• Finding the value of a variable in a scientific experiment

Tips and Tricks

When solving linear equations, it's essential to isolate the variable on one side of the equation. This can be done by adding, subtracting, multiplying, or dividing both sides of the equation by the same value.

Common Mistakes

Some common mistakes to avoid when solving linear equations include:

• Not isolating the variable on one side of the equation
• Not checking the units of the variables
• Not considering the order of operations

Conclusion

Introduction

In our previous article, we explored the world of mathematics and solved a real-life scenario involving Jalisa's babysitting earnings. We used algebraic equations to represent the situation and solved for the unknown variable, $d$, which represents the amount Jalisa earned babysitting yesterday. In this article, we will provide a Q&A guide to help you better understand the concept and apply it to various scenarios.

Q: What is the equation $d + 22.50 = 71.25$ used to represent?

A: The equation $d + 22.50 = 71.25$ is used to represent the situation where Jalisa earned $\$71.25$ today babysitting, which is $\$22.50$ more than she earned babysitting yesterday.

Q: What is the value of $d$ in the equation $d + 22.50 = 71.25$?

A: To find the value of $d$, we need to isolate the variable $d$ on one side of the equation. We can do this by subtracting $22.50$ from both sides of the equation. This will give us the value of $d$ as $\$48.75$.

Q: How can we use the equation $d + 22.50 = 71.25$ in real-life scenarios?

A: This type of problem can be applied to various real-world scenarios, such as:

• Calculating the cost of goods sold
• Determining the profit or loss of a business
• Finding the value of a variable in a scientific experiment

Q: What are some common mistakes to avoid when solving linear equations?

A: Some common mistakes to avoid when solving linear equations include:

• Not isolating the variable on one side of the equation
• Not checking the units of the variables
• Not considering the order of operations

Q: How can we check our work when solving linear equations?

A: To check our work, we can plug the value of the variable back into the original equation and verify that it is true. For example, if we found that $d = 48.75$, we can plug this value back into the equation $d + 22.50 = 71.25$ to verify that it is true.

Q: What is the importance of solving linear equations in real-life scenarios?

A: Solving linear equations is a crucial skill in mathematics and has numerous real-world applications. By understanding how to isolate variables and calculate their values, we can apply this knowledge to various scenarios and make informed decisions.

Q: How can we use technology to solve linear equations?

A: We can use technology such as calculators or computer software to solve linear equations. For example, we can use a calculator to plug in the values and solve for the variable.

Conclusion

In conclusion, solving linear equations is a crucial skill in mathematics and has numerous real-world applications. By understanding how to isolate variables and calculate their values, we can apply this knowledge to various scenarios and make informed decisions. We hope this Q&A guide has helped you better understand the concept and apply it to various scenarios.

Additional Resources

For more information on solving linear equations, we recommend the following resources:

• Khan Academy: Linear Equations
• Mathway: Linear Equations
• Wolfram Alpha: Linear Equations

Final Thoughts

Solving linear equations is a fundamental concept in mathematics that has numerous real-world applications. By understanding how to isolate variables and calculate their values, we can apply this knowledge to various scenarios and make informed decisions. We hope this Q&A guide has helped you better understand the concept and apply it to various scenarios.