Is The Point \[$(-1,-5)\$\] A Solution To The System? Show All Work.$\[ \begin{cases} y \ \textless \ X - 1 \\ y \ \textgreater \ -x + 2 \end{cases} \\]

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Is the Point (-1,-5) a Solution to the System?

In mathematics, a system of linear inequalities is a set of two or more inequalities that involve two or more variables. To determine if a point is a solution to a system of linear inequalities, we need to check if the point satisfies all the inequalities in the system. In this article, we will discuss how to determine if the point (-1,-5) is a solution to the system of linear inequalities given below.

The System of Linear Inequalities

The system of linear inequalities is given by:

{y<xβˆ’1y>βˆ’x+2\begin{cases} y < x - 1 \\ y > -x + 2 \end{cases}

Understanding the Inequalities

To determine if the point (-1,-5) is a solution to the system, we need to understand the two inequalities in the system. The first inequality is y<xβˆ’1y < x - 1, which means that the y-coordinate of any point that satisfies this inequality is less than the x-coordinate minus 1. The second inequality is y>βˆ’x+2y > -x + 2, which means that the y-coordinate of any point that satisfies this inequality is greater than the negative of the x-coordinate plus 2.

Checking the First Inequality

To check if the point (-1,-5) satisfies the first inequality, we need to substitute the x and y values of the point into the inequality. The x-value of the point is -1 and the y-value is -5. Substituting these values into the inequality, we get:

βˆ’5<βˆ’1βˆ’1-5 < -1 - 1

Simplifying the inequality, we get:

βˆ’5<βˆ’2-5 < -2

This inequality is false, since -5 is not less than -2. Therefore, the point (-1,-5) does not satisfy the first inequality.

Checking the Second Inequality

To check if the point (-1,-5) satisfies the second inequality, we need to substitute the x and y values of the point into the inequality. The x-value of the point is -1 and the y-value is -5. Substituting these values into the inequality, we get:

βˆ’5>βˆ’(βˆ’1)+2-5 > -(-1) + 2

Simplifying the inequality, we get:

βˆ’5>1-5 > 1

This inequality is false, since -5 is not greater than 1. Therefore, the point (-1,-5) does not satisfy the second inequality.

Since the point (-1,-5) does not satisfy both inequalities in the system, it is not a solution to the system. Therefore, the point (-1,-5) is not a solution to the system of linear inequalities given above.

Why is it Important to Check Both Inequalities?

It is essential to check both inequalities in the system to determine if a point is a solution. If we only check one inequality and the point satisfies it, we cannot conclude that the point is a solution to the system. We need to check both inequalities to ensure that the point satisfies both of them.

Real-World Applications

Systems of linear inequalities have many real-world applications. For example, in economics, a system of linear inequalities can be used to model the constraints of a production process. In engineering, a system of linear inequalities can be used to model the constraints of a design problem. In computer science, a system of linear inequalities can be used to model the constraints of a scheduling problem.

Tips for Solving Systems of Linear Inequalities

Here are some tips for solving systems of linear inequalities:

  • Read the inequalities carefully: Make sure you understand what each inequality is saying.
  • Substitute the values: Substitute the x and y values of the point into each inequality.
  • Simplify the inequalities: Simplify the inequalities to make it easier to determine if the point satisfies them.
  • Check both inequalities: Check both inequalities to ensure that the point satisfies both of them.

In conclusion, the point (-1,-5) is not a solution to the system of linear inequalities given above. We need to check both inequalities in the system to determine if a point is a solution. Systems of linear inequalities have many real-world applications, and understanding how to solve them is essential in many fields. By following the tips outlined above, you can solve systems of linear inequalities with ease.
Frequently Asked Questions (FAQs) about Systems of Linear Inequalities

Q: What is a system of linear inequalities?

A: A system of linear inequalities is a set of two or more inequalities that involve two or more variables. Each inequality in the system is a linear inequality, which means that it can be written in the form ax + by < c, where a, b, and c are constants.

Q: How do I determine if a point is a solution to a system of linear inequalities?

A: To determine if a point is a solution to a system of linear inequalities, you need to check if the point satisfies all the inequalities in the system. You can do this by substituting the x and y values of the point into each inequality and checking if the inequality is true.

Q: What is the difference between a system of linear inequalities and a system of linear equations?

A: A system of linear equations is a set of two or more equations that involve two or more variables. Each equation in the system is a linear equation, which means that it can be written in the form ax + by = c, where a, b, and c are constants. A system of linear inequalities, on the other hand, is a set of two or more inequalities that involve two or more variables.

Q: How do I graph a system of linear inequalities?

A: To graph a system of linear inequalities, you need to graph each inequality in the system on a coordinate plane. You can do this by finding the boundary line for each inequality and then shading the region that satisfies the inequality.

Q: What is the boundary line of an inequality?

A: The boundary line of an inequality is the line that separates the region that satisfies the inequality from the region that does not satisfy the inequality. For example, if the inequality is y < x - 1, the boundary line is the line y = x - 1.

Q: How do I find the boundary line of an inequality?

A: To find the boundary line of an inequality, you need to rewrite the inequality in the form y = mx + b, where m is the slope of the line and b is the y-intercept. For example, if the inequality is y < x - 1, you can rewrite it as y = x - 1, which is the boundary line.

Q: What is the region that satisfies an inequality?

A: The region that satisfies an inequality is the region on the coordinate plane that contains all the points that satisfy the inequality. For example, if the inequality is y < x - 1, the region that satisfies the inequality is the region below the line y = x - 1.

Q: How do I determine if a region satisfies an inequality?

A: To determine if a region satisfies an inequality, you need to check if all the points in the region satisfy the inequality. You can do this by substituting the x and y values of a point in the region into the inequality and checking if the inequality is true.

Q: What is the importance of systems of linear inequalities in real-world applications?

A: Systems of linear inequalities have many real-world applications, including economics, engineering, and computer science. They can be used to model the constraints of a production process, the constraints of a design problem, and the constraints of a scheduling problem.

Q: How do I solve a system of linear inequalities?

A: To solve a system of linear inequalities, you need to find the region that satisfies all the inequalities in the system. You can do this by graphing each inequality in the system on a coordinate plane and then finding the intersection of the regions that satisfy each inequality.

Q: What are some common mistakes to avoid when solving systems of linear inequalities?

A: Some common mistakes to avoid when solving systems of linear inequalities include:

  • Not checking both inequalities in the system
  • Not substituting the x and y values of the point into each inequality
  • Not simplifying the inequalities
  • Not checking if the point satisfies both inequalities

In conclusion, systems of linear inequalities are an important topic in mathematics and have many real-world applications. By understanding how to solve systems of linear inequalities, you can model the constraints of a production process, the constraints of a design problem, and the constraints of a scheduling problem. Remember to check both inequalities in the system, substitute the x and y values of the point into each inequality, simplify the inequalities, and check if the point satisfies both inequalities.