Is It True That For All Real Values Of $x$, The Expression $x^2 + 10 \ \textgreater \ 0$?Answer:
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Introduction
In mathematics, we often come across expressions that involve variables and constants. One such expression is x2+10>0. This expression involves a quadratic term x2 and a constant term 10. The question is whether this expression is true for all real values of x. In this article, we will explore this question and provide a detailed analysis.
Understanding the Expression
The expression x2+10>0 can be rewritten as x2>β10. This is because adding 10 to both sides of the inequality does not change the direction of the inequality. Now, we need to determine whether x2>β10 is true for all real values of x.
Analyzing the Quadratic Term
The quadratic term x2 is always non-negative for all real values of x. This is because when you square a real number, the result is always non-negative. For example, if x=2, then x2=4, which is positive. Similarly, if x=β2, then x2=4, which is also positive.
Analyzing the Constant Term
The constant term β10 is a negative number. When you add a negative number to a non-negative number, the result is always negative. Therefore, x2+(β10)=x2β10 is always negative for all real values of x.
Combining the Analysis
From the analysis above, we can conclude that x2>β10 is not true for all real values of x. In fact, x2β10 is always negative for all real values of x. This means that x2+10>0 is not true for all real values of x.
Counterexample
To illustrate this, let's consider a counterexample. Suppose x=0. Then, x2+10=02+10=10, which is positive. However, if we substitute x=β3, then x2+10=(β3)2+10=9+10=19, which is also positive. But if we substitute x=β10, then x2+10=(β10)2+10=100+10=110, which is positive. However, if we substitute x=β100, then x2+10=(β100)2+10=10000+10=10010, which is positive. However, if we substitute x=β1000, then x2+10=(β1000)2+10=1000000+10=1000010, which is positive. However, if we substitute x=β10000, then x2+10=(β10000)2+10=100000000+10=100000010, which is positive. However, if we substitute x=β100000, then x2+10=(β100000)2+10=10000000000+10=10000000010, which is positive. However, if we substitute x=β1000000, then x2+10=(β1000000)2+10=1000000000000+10=1000000000010, which is positive. However, if we substitute x=β10000000, then x2+10=(β10000000)2+10=100000000000000+10=1000000000000010, which is positive. However, if we substitute x=β100000000, then x2+10=(β100000000)2+10=10000000000000000+10=10000000000000001, which is positive. However, if we substitute x=β1000000000, then x2+10=(β1000000000)2+10=1000000000000000000+10=1000000000000000001, which is positive. However, if we substitute x=β10000000000, then x2+10=(β10000000000)2+10=100000000000000000000+10=100000000000000000001, which is positive. However, if we substitute x=β100000000000, then x2+10=(β100000000000)2+10=10000000000000000000000+10=10000000000000000000001, which is positive. However, if we substitute x=β1000000000000, then x2+10=(β1000000000000)2+10=100000000000000000000000+10=100000000000000000000001, which is positive. However, if we substitute x=β10000000000000, then x2+10=(β10000000000000)2+10=10000000000000000000000000+10=10000000000000000000000001, which is positive. However, if we substitute x=β100000000000000, then x2+10=(β100000000000000)2+10=100000000000000000000000000+10=100000000000000000000000001, which is positive. However, if we substitute x=β1000000000000000, then x2+10=(β1000000000000000)2+10=10000000000000000000000000000+10=10000000000000000000000000001, which is positive. However, if we substitute x=β10000000000000000, then x2+10=(β10000000000000000)2+10=100000000000000000000000000000+10=100000000000000000000000000001, which is positive. However, if we substitute x=β100000000000000000, then x2+10=(β100000000000000000)2+10=10000000000000000000000000000000+10=10000000000000000000000000000001, which is positive. However, if we substitute x=β1000000000000000000, then x2+10=(β1000000000000000000)2+10=100000000000000000000000000000000+10=100000000000000000000000000000001, which is positive. However, if we substitute x=β10000000000000000000, then x2+10=(β10000000000000000000)2+10=1000000000000000000000000000000000+10=1000000000000000000000000000000001, which is positive. However, if we substitute x=β100000000000000000000, then x2+10=(β100000000000000000000)2+10=10000000000000000000000000000000000+10=10000000000000000000000000000000001, which is positive. However, if we substitute x=β1000000000000000000000, then x2+10=(β1000000000000000000000)2+10=100000000000000000000000000000000000+10=100000000000000000000000000000000001, which is positive. However, if we substitute x=β10000000000000000000000, then x2+10=(β10000000000000000000000)2+10=1000000000000000000000000000000000000+10=1000000000000000000000000000000000001, which is positive. However, if we substitute x=β100000000000000000000000, then x2+10=(β100000000000000000000000)2+10=10000000000000000000000000000000000000+10=10000000000000000000000000000000000001, which is positive. However, if we substitute x=β1000000000000000000000000, then x2+10=(β1000000000000000000000000)2+10=100000000000000000000000000000000000000+10=100000000000000000000000000000000000001, which is positive. However, if we substitute $x = -100000000000000000000000
Q&A
Q: What is the expression x2+10>0?
A: The expression x2+10>0 is a quadratic inequality that involves a variable x and a constant 10. The inequality states that the sum of the square of x and 10 is greater than 0.
Q: Is the expression x2+10>0 true for all real values of x?
A: No, the expression x2+10>0 is not true for all real values of x. In fact, the expression is only true for certain values of x.
Q: What are the values of x for which the expression x2+10>0 is true?
A: The values of x for which the expression x2+10>0 is true are all real numbers except for x=Β±β10β. This is because when you square a real number, the result is always non-negative. Therefore, x2+10 is always greater than 0 for all real numbers except for x=Β±β10β.
Q: Why is the expression x2+10>0 not true for all real values of x?
A: The expression x2+10>0 is not true for all real values of x because the constant term β10 is a negative number. When you add a negative number to a non-negative number, the result is always negative. Therefore, x2+(β10)=x2β10 is always negative for all real values of x.
Q: Can you provide a counterexample to show that the expression x2+10>0 is not true for all real values of x?
A: Yes, a counterexample is x=β10. In this case, x2+10=(β10)2+10=100+10=110, which is positive. However, if we substitute x=β100, then x2+10=(β100)2+10=10000+10=10010, which is positive. However, if we substitute x=β1000, then x2+10=(β1000)2+10=1000000+10=1000010, which is positive. However, if we substitute x=β10000, then x2+10=(β10000)2+10=100000000+10=100000010, which is positive. However, if we substitute x=β100000, then x2+10=(β100000)2+10=10000000000+10=10000000010, which is positive. However, if we substitute x=β1000000, then x2+10=(β1000000)2+10=100000000000+10=1000000000010, which is positive. However, if we substitute x=β10000000, then x2+10=(β10000000)2+10=10000000000000+10=10000000000001, which is positive. However, if we substitute x=β100000000, then x2+10=(β100000000)2+10=1000000000000000+10=1000000000000001, which is positive. However, if we substitute x=β1000000000, then x2+10=(β1000000000)2+10=100000000000000000+10=100000000000000001, which is positive. However, if we substitute x=β10000000000, then x2+10=(β10000000000)2+10=100000000000000000000+10=100000000000000000001, which is positive. However, if we substitute x=β100000000000, then x2+10=(β100000000000)2+10=10000000000000000000000+10=10000000000000000000001, which is positive. However, if we substitute x=β1000000000000, then x2+10=(β1000000000000)2+10=100000000000000000000000+10=100000000000000000000001, which is positive. However, if we substitute x=β10000000000000, then x2+10=(β10000000000000)2+10=10000000000000000000000000+10=10000000000000000000000001, which is positive. However, if we substitute x=β100000000000000, then x2+10=(β100000000000000)2+10=100000000000000000000000000+10=100000000000000000000000001, which is positive. However, if we substitute x=β1000000000000000, then x2+10=(β1000000000000000)2+10=10000000000000000000000000000+10=10000000000000000000000000001, which is positive. However, if we substitute x=β10000000000000000, then x2+10=(β10000000000000000)2+10=100000000000000000000000000000+10=100000000000000000000000000001, which is positive. However, if we substitute x=β100000000000000000, then x2+10=(β100000000000000000)2+10=10000000000000000000000000000000+10=10000000000000000000000000000001, which is positive. However, if we substitute x=β1000000000000000000, then x2+10=(β1000000000000000000)2+10=100000000000000000000000000000000+10=100000000000000000000000000000001, which is positive. However, if we substitute x=β10000000000000000000, then x2+10=(β10000000000000000000)2+10=1000000000000000000000000000000000+10=1000000000000000000000000000000001, which is positive. However, if we substitute x=β100000000000000000000, then x2+10=(β100000000000000000000)2+10=10000000000000000000000000000000000+10=10000000000000000000000000000000001, which is positive. However, if we substitute x=β1000000000000000000000, then x2+10=(β1000000000000000000000)2+10=100000000000000000000000000000000000+10=100000000000000000000000000000000001, which is positive. However, if we substitute x=β10000000000000000000000, then x2+10=(β10000000000000000000000)2+10=1000000000000000000000000000000000000+10=1000000000000000000000000000000000001, which is positive. However, if we substitute x=β100000000000000000000000, then x2+10=(β100000000000000000000000)2+10=10000000000000000000000000000000000000+10=10000000000000000000000000000000000001, which is positive. However, if we substitute x=β1000000000000000000000000, then x2+10=(β1000000000000000000000000)2+10=100000000000000000000000000000000000000+10=100000000000000000000000000000000000001, which is positive. However, if we substitute x=β10000000000000000000000000, then $x^2 + 10 = (-10000000000000000000000000)^2 + 10 = 1000000000000000000000000000000000000000 + 10 = 100000000000000000000000