If $x-9$ Is A Factor Of $x^2-5x-36$, What Is The Other Factor?A. $ X − 4 X-4 X − 4 [/tex]B. $x+4$C. $x-6$D. $ X + 6 X+6 X + 6 [/tex]

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Introduction

In algebra, polynomial equations are used to model various real-world situations. One of the fundamental concepts in polynomial equations is factoring, which involves expressing a polynomial as a product of simpler polynomials. In this article, we will explore how to find the other factor of a polynomial when one factor is given.

Understanding the Problem

The problem states that $x-9$ is a factor of $x^2-5x-36$. This means that when we divide $x^2-5x-36$ by $x-9$, we should get a remainder of zero. Our goal is to find the other factor of $x^2-5x-36$.

Factoring Quadratic Equations

To solve this problem, we need to factor the quadratic equation $x^2-5x-36$. A quadratic equation is a polynomial of degree two, which can be written in the form $ax^2+bx+c$. In this case, $a=1$, $b=-5$, and $c=-36$.

We can factor a quadratic equation by finding two numbers whose product is equal to the constant term ($c$) and whose sum is equal to the coefficient of the linear term ($b$). In this case, we need to find two numbers whose product is $-36$ and whose sum is $-5$.

Using the Factor Theorem

The factor theorem states that if $x-a$ is a factor of a polynomial $f(x)$, then $f(a)=0$. In this case, we know that $x-9$ is a factor of $x^2-5x-36$. Therefore, we can use the factor theorem to find the other factor.

Let's substitute $x=9$ into the polynomial $x^2-5x-36$:

925(9)36=814536=09^2-5(9)-36=81-45-36=0

Since the result is zero, we know that $x-9$ is indeed a factor of $x^2-5x-36$.

Finding the Other Factor

Now that we have confirmed that $x-9$ is a factor of $x^2-5x-36$, we can use polynomial division or synthetic division to find the other factor.

Let's use polynomial division to divide $x^2-5x-36$ by $x-9$:

x+4x9\encloselongdivx25x36x2+9x14x36(14x+36)0\begin{array}{r} x+4 \\ x-9 \enclose{longdiv}{x^2-5x-36} \\ \underline{-x^2+9x} \\ -14x-36 \\ \underline{-(-14x+36)} \\ 0 \end{array}

The result of the division is $x+4$, which is the other factor of $x^2-5x-36$.

Conclusion

In this article, we have shown how to find the other factor of a polynomial when one factor is given. We used the factor theorem to confirm that $x-9$ is a factor of $x^2-5x-36$, and then used polynomial division to find the other factor, which is $x+4$.

Answer

The other factor of $x^2-5x-36$ is $x+4$.

Final Thoughts

Introduction

In our previous article, we explored how to find the other factor of a polynomial when one factor is given. In this article, we will answer some frequently asked questions about solving polynomial equations.

Q: What is the difference between a factor and a root?

A: A factor of a polynomial is a polynomial that divides the original polynomial without leaving a remainder. A root of a polynomial, on the other hand, is a value of x that makes the polynomial equal to zero. For example, if we have the polynomial x^2 - 5x - 36, the factor x - 9 is a factor, but the root x = 9 is a value of x that makes the polynomial equal to zero.

Q: How do I know if a polynomial is factorable?

A: A polynomial is factorable if it can be expressed as a product of simpler polynomials. To determine if a polynomial is factorable, we can try to find two numbers whose product is equal to the constant term and whose sum is equal to the coefficient of the linear term. If we can find such numbers, we can factor the polynomial.

Q: What is the difference between polynomial division and synthetic division?

A: Polynomial division and synthetic division are both methods for dividing polynomials. Polynomial division involves dividing one polynomial by another using long division, while synthetic division involves using a shortcut method to divide polynomials. Synthetic division is often faster and easier to use than polynomial division, but it requires a specific format for the dividend and divisor.

Q: Can I use synthetic division to divide polynomials with complex coefficients?

A: Yes, you can use synthetic division to divide polynomials with complex coefficients. However, you will need to use complex numbers and follow the same steps as you would with real numbers.

Q: How do I know if a polynomial has a rational root?

A: A polynomial has a rational root if the root is a rational number, which means it can be expressed as a fraction of two integers. To determine if a polynomial has a rational root, we can use the rational root theorem, which states that any rational root of a polynomial must be of the form p/q, where p is a factor of the constant term and q is a factor of the leading coefficient.

Q: Can I use the rational root theorem to find all the roots of a polynomial?

A: No, the rational root theorem only tells us that if a polynomial has a rational root, it must be of a certain form. It does not guarantee that the polynomial has any rational roots at all. To find all the roots of a polynomial, we may need to use other methods, such as factoring or using the quadratic formula.

Q: How do I know if a polynomial is irreducible?

A: A polynomial is irreducible if it cannot be factored into simpler polynomials. To determine if a polynomial is irreducible, we can try to factor it using various methods, such as factoring by grouping or using the rational root theorem. If we cannot factor the polynomial, it is likely irreducible.

Conclusion

In this article, we have answered some frequently asked questions about solving polynomial equations. We hope that this knowledge will be useful to you in your future studies.

Final Thoughts

Solving polynomial equations is an essential skill in algebra, and it has many real-world applications. By understanding how to solve polynomial equations, we can solve a wide range of problems in mathematics and science. We hope that this article has been helpful in your understanding of polynomial equations.