If P ⃗ + Q ⃗ + R ⃗ = 0 \vec{p} + \vec{q} + \vec{r} = 0 P ​ + Q ​ + R = 0 , ∣ P ⃗ ∣ = 6 |\vec{p}| = 6 ∣ P ​ ∣ = 6 , ∣ Q ⃗ ∣ = 10 |\vec{q}| = 10 ∣ Q ​ ∣ = 10 , And P ⃗ ⋅ Q ⃗ = 30 \vec{p} \cdot \vec{q} = 30 P ​ ⋅ Q ​ = 30 , Then Find ∣ R ⃗ ∣ |\vec{r}| ∣ R ∣ .

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Introduction

In this article, we will explore the concept of vectors and their properties. We will use the given information to find the magnitude of vector r\vec{r}, which is a crucial concept in mathematics and physics. The given information includes the sum of three vectors, the magnitudes of two vectors, and the dot product of two vectors. We will use these properties to find the magnitude of vector r\vec{r}.

Properties of Vectors

Vectors are mathematical objects that have both magnitude and direction. They can be represented graphically as arrows in a coordinate system. The magnitude of a vector is its length, while the direction is the angle it makes with the positive x-axis. The dot product of two vectors is a scalar value that represents the amount of "similarity" between the two vectors.

The Given Information

We are given that p+q+r=0\vec{p} + \vec{q} + \vec{r} = 0. This means that the sum of the three vectors is equal to the zero vector. We are also given that p=6|\vec{p}| = 6 and q=10|\vec{q}| = 10. This means that the magnitude of vector p\vec{p} is 6 units, and the magnitude of vector q\vec{q} is 10 units. Finally, we are given that pq=30\vec{p} \cdot \vec{q} = 30. This means that the dot product of vectors p\vec{p} and q\vec{q} is 30.

Using the Properties of Vectors to Find r|\vec{r}|

We can use the properties of vectors to find the magnitude of vector r\vec{r}. Since p+q+r=0\vec{p} + \vec{q} + \vec{r} = 0, we can write:

r=(p+q)\vec{r} = -(\vec{p} + \vec{q})

We can use the property of the dot product to find the magnitude of vector r\vec{r}. The dot product of a vector with itself is equal to the square of its magnitude. Therefore, we can write:

r2=rr=(pq)(pq)|\vec{r}|^2 = \vec{r} \cdot \vec{r} = (-\vec{p} - \vec{q}) \cdot (-\vec{p} - \vec{q})

Expanding the dot product, we get:

r2=pp+2pq+qq|\vec{r}|^2 = \vec{p} \cdot \vec{p} + 2\vec{p} \cdot \vec{q} + \vec{q} \cdot \vec{q}

We know that pp=p2=62=36\vec{p} \cdot \vec{p} = |\vec{p}|^2 = 6^2 = 36 and qq=q2=102=100\vec{q} \cdot \vec{q} = |\vec{q}|^2 = 10^2 = 100. We are also given that pq=30\vec{p} \cdot \vec{q} = 30. Therefore, we can substitute these values into the equation:

r2=36+2(30)+100|\vec{r}|^2 = 36 + 2(30) + 100

Simplifying the equation, we get:

r2=36+60+100|\vec{r}|^2 = 36 + 60 + 100

r2=196|\vec{r}|^2 = 196

Taking the square root of both sides, we get:

r=196|\vec{r}| = \sqrt{196}

r=14|\vec{r}| = 14

Therefore, the magnitude of vector r\vec{r} is 14 units.

Conclusion

In this article, we used the properties of vectors to find the magnitude of vector r\vec{r}. We were given that p+q+r=0\vec{p} + \vec{q} + \vec{r} = 0, p=6|\vec{p}| = 6, q=10|\vec{q}| = 10, and pq=30\vec{p} \cdot \vec{q} = 30. We used the dot product and the properties of vectors to find the magnitude of vector r\vec{r}. The magnitude of vector r\vec{r} is 14 units.

References

  • [1] "Vector Algebra" by Wikipedia
  • [2] "Vector Calculus" by MIT OpenCourseWare
  • [3] "Linear Algebra and Its Applications" by Gilbert Strang

Further Reading

  • [1] "Vector Analysis" by Murray R. Spiegel
  • [2] "Calculus on Manifolds" by Michael Spivak
  • [3] "Linear Algebra and Its Applications" by Gilbert Strang

Note: The references and further reading section are not included in the word count.

Q&A: If p+q+r=0\vec{p} + \vec{q} + \vec{r} = 0, p=6|\vec{p}| = 6, q=10|\vec{q}| = 10, and pq=30\vec{p} \cdot \vec{q} = 30, then find r|\vec{r}|

Q: What is the relationship between the vectors p\vec{p}, q\vec{q}, and r\vec{r}?

A: The vectors p\vec{p}, q\vec{q}, and r\vec{r} are related by the equation p+q+r=0\vec{p} + \vec{q} + \vec{r} = 0. This means that the sum of the three vectors is equal to the zero vector.

Q: What is the magnitude of vector p\vec{p}?

A: The magnitude of vector p\vec{p} is 6 units.

Q: What is the magnitude of vector q\vec{q}?

A: The magnitude of vector q\vec{q} is 10 units.

Q: What is the dot product of vectors p\vec{p} and q\vec{q}?

A: The dot product of vectors p\vec{p} and q\vec{q} is 30.

Q: How can we use the properties of vectors to find the magnitude of vector r\vec{r}?

A: We can use the properties of vectors to find the magnitude of vector r\vec{r} by using the equation r=(p+q)\vec{r} = -(\vec{p} + \vec{q}). We can then use the dot product to find the magnitude of vector r\vec{r}.

Q: What is the magnitude of vector r\vec{r}?

A: The magnitude of vector r\vec{r} is 14 units.

Q: Can we use the same method to find the magnitude of vector r\vec{r} if the dot product of vectors p\vec{p} and q\vec{q} is not given?

A: No, we cannot use the same method to find the magnitude of vector r\vec{r} if the dot product of vectors p\vec{p} and q\vec{q} is not given. The dot product is a crucial piece of information that is needed to find the magnitude of vector r\vec{r}.

Q: Can we use the same method to find the magnitude of vector r\vec{r} if the magnitudes of vectors p\vec{p} and q\vec{q} are not given?

A: No, we cannot use the same method to find the magnitude of vector r\vec{r} if the magnitudes of vectors p\vec{p} and q\vec{q} are not given. The magnitudes of vectors p\vec{p} and q\vec{q} are crucial pieces of information that are needed to find the magnitude of vector r\vec{r}.

Q: Can we use the same method to find the magnitude of vector r\vec{r} if the vectors p\vec{p}, q\vec{q}, and r\vec{r} are not related by the equation p+q+r=0\vec{p} + \vec{q} + \vec{r} = 0?

A: No, we cannot use the same method to find the magnitude of vector r\vec{r} if the vectors p\vec{p}, q\vec{q}, and r\vec{r} are not related by the equation p+q+r=0\vec{p} + \vec{q} + \vec{r} = 0. The equation p+q+r=0\vec{p} + \vec{q} + \vec{r} = 0 is a crucial piece of information that is needed to find the magnitude of vector r\vec{r}.

Conclusion

In this article, we used the properties of vectors to find the magnitude of vector r\vec{r}. We were given that p+q+r=0\vec{p} + \vec{q} + \vec{r} = 0, p=6|\vec{p}| = 6, q=10|\vec{q}| = 10, and pq=30\vec{p} \cdot \vec{q} = 30. We used the dot product and the properties of vectors to find the magnitude of vector r\vec{r}. The magnitude of vector r\vec{r} is 14 units.

References

  • [1] "Vector Algebra" by Wikipedia
  • [2] "Vector Calculus" by MIT OpenCourseWare
  • [3] "Linear Algebra and Its Applications" by Gilbert Strang

Further Reading

  • [1] "Vector Analysis" by Murray R. Spiegel
  • [2] "Calculus on Manifolds" by Michael Spivak
  • [3] "Linear Algebra and Its Applications" by Gilbert Strang