If $f(x)=2x^2-3x+2$ And $g(x)=2x^2-3x-2$, What Is $f(x)-g(x$\]?A. $6x+4$ B. 0 C. $4x^2-6x$ D. 4

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Understanding the Problem

To find the value of f(x)βˆ’g(x)f(x)-g(x), we need to understand the concept of subtraction in algebra. When we subtract two functions, we are essentially finding the difference between their respective outputs for a given input. In this case, we are given two quadratic functions, f(x)f(x) and g(x)g(x), and we need to find their difference.

Subtraction of Functions

The subtraction of functions is a straightforward process. We simply subtract the corresponding terms of the two functions. In this case, we have:

f(x)=2x2βˆ’3x+2f(x) = 2x^2 - 3x + 2

g(x)=2x2βˆ’3xβˆ’2g(x) = 2x^2 - 3x - 2

To find f(x)βˆ’g(x)f(x) - g(x), we subtract the corresponding terms:

f(x)βˆ’g(x)=(2x2βˆ’3x+2)βˆ’(2x2βˆ’3xβˆ’2)f(x) - g(x) = (2x^2 - 3x + 2) - (2x^2 - 3x - 2)

Simplifying the Expression

Now, let's simplify the expression by combining like terms. We can start by removing the parentheses and combining the like terms:

f(x)βˆ’g(x)=2x2βˆ’3x+2βˆ’2x2+3x+2f(x) - g(x) = 2x^2 - 3x + 2 - 2x^2 + 3x + 2

Combining Like Terms

Next, we can combine the like terms. The 2x22x^2 terms cancel each other out, and the βˆ’3x-3x and +3x+3x terms also cancel each other out. We are left with:

f(x)βˆ’g(x)=2+2f(x) - g(x) = 2 + 2

Evaluating the Expression

Finally, we can evaluate the expression by adding the two constants:

f(x)βˆ’g(x)=4f(x) - g(x) = 4

Conclusion

In conclusion, the value of f(x)βˆ’g(x)f(x)-g(x) is 44. This means that when we subtract the function g(x)g(x) from the function f(x)f(x), we get a constant value of 44.

Example Use Case

This concept of subtracting functions is useful in many real-world applications, such as:

  • Finding the difference between two population growth rates
  • Calculating the difference between two investment returns
  • Determining the difference between two physical quantities, such as temperature or pressure

Step-by-Step Solution

Here is a step-by-step solution to the problem:

  1. Write down the two functions: f(x)=2x2βˆ’3x+2f(x) = 2x^2 - 3x + 2 and g(x)=2x2βˆ’3xβˆ’2g(x) = 2x^2 - 3x - 2
  2. Subtract the corresponding terms: f(x)βˆ’g(x)=(2x2βˆ’3x+2)βˆ’(2x2βˆ’3xβˆ’2)f(x) - g(x) = (2x^2 - 3x + 2) - (2x^2 - 3x - 2)
  3. Simplify the expression by combining like terms: f(x)βˆ’g(x)=2x2βˆ’3x+2βˆ’2x2+3x+2f(x) - g(x) = 2x^2 - 3x + 2 - 2x^2 + 3x + 2
  4. Combine the like terms: f(x)βˆ’g(x)=2+2f(x) - g(x) = 2 + 2
  5. Evaluate the expression: f(x)βˆ’g(x)=4f(x) - g(x) = 4

Final Answer

The final answer is 4\boxed{4}.

Understanding the Problem

To find the value of f(x)βˆ’g(x)f(x)-g(x), we need to understand the concept of subtraction in algebra. When we subtract two functions, we are essentially finding the difference between their respective outputs for a given input. In this case, we are given two quadratic functions, f(x)f(x) and g(x)g(x), and we need to find their difference.

Q&A Session

Q: What is the difference between f(x)f(x) and g(x)g(x)?

A: The difference between f(x)f(x) and g(x)g(x) is the value of f(x)βˆ’g(x)f(x)-g(x).

Q: How do we find the value of f(x)βˆ’g(x)f(x)-g(x)?

A: To find the value of f(x)βˆ’g(x)f(x)-g(x), we need to subtract the corresponding terms of the two functions.

Q: What are the corresponding terms of the two functions?

A: The corresponding terms of the two functions are the terms with the same variable and exponent.

Q: How do we simplify the expression?

A: We simplify the expression by combining like terms.

Q: What are like terms?

A: Like terms are terms with the same variable and exponent.

Q: How do we combine like terms?

A: We combine like terms by adding or subtracting their coefficients.

Q: What is the final answer?

A: The final answer is 4\boxed{4}.

Example Questions and Answers

Q: If f(x)=x2+2x+1f(x)=x^2+2x+1 and g(x)=x2+2xβˆ’1g(x)=x^2+2x-1, what is f(x)βˆ’g(x)f(x)-g(x)?

A: To find the value of f(x)βˆ’g(x)f(x)-g(x), we need to subtract the corresponding terms of the two functions.

f(x)βˆ’g(x)=(x2+2x+1)βˆ’(x2+2xβˆ’1)f(x)-g(x) = (x^2+2x+1) - (x^2+2x-1)

Simplifying the expression, we get:

f(x)βˆ’g(x)=2f(x)-g(x) = 2

Q: If f(x)=3x2βˆ’2x+1f(x)=3x^2-2x+1 and g(x)=3x2βˆ’2xβˆ’1g(x)=3x^2-2x-1, what is f(x)βˆ’g(x)f(x)-g(x)?

A: To find the value of f(x)βˆ’g(x)f(x)-g(x), we need to subtract the corresponding terms of the two functions.

f(x)βˆ’g(x)=(3x2βˆ’2x+1)βˆ’(3x2βˆ’2xβˆ’1)f(x)-g(x) = (3x^2-2x+1) - (3x^2-2x-1)

Simplifying the expression, we get:

f(x)βˆ’g(x)=2f(x)-g(x) = 2

Q: If f(x)=2x2βˆ’3x+2f(x)=2x^2-3x+2 and g(x)=2x2βˆ’3xβˆ’2g(x)=2x^2-3x-2, what is f(x)βˆ’g(x)f(x)-g(x)?

A: To find the value of f(x)βˆ’g(x)f(x)-g(x), we need to subtract the corresponding terms of the two functions.

f(x)βˆ’g(x)=(2x2βˆ’3x+2)βˆ’(2x2βˆ’3xβˆ’2)f(x)-g(x) = (2x^2-3x+2) - (2x^2-3x-2)

Simplifying the expression, we get:

f(x)βˆ’g(x)=4f(x)-g(x) = 4

Conclusion

In conclusion, the value of f(x)βˆ’g(x)f(x)-g(x) is 44. This means that when we subtract the function g(x)g(x) from the function f(x)f(x), we get a constant value of 44.

Step-by-Step Solution

Here is a step-by-step solution to the problem:

  1. Write down the two functions: f(x)=2x2βˆ’3x+2f(x) = 2x^2 - 3x + 2 and g(x)=2x2βˆ’3xβˆ’2g(x) = 2x^2 - 3x - 2
  2. Subtract the corresponding terms: f(x)βˆ’g(x)=(2x2βˆ’3x+2)βˆ’(2x2βˆ’3xβˆ’2)f(x) - g(x) = (2x^2 - 3x + 2) - (2x^2 - 3x - 2)
  3. Simplify the expression by combining like terms: f(x)βˆ’g(x)=2x2βˆ’3x+2βˆ’2x2+3x+2f(x) - g(x) = 2x^2 - 3x + 2 - 2x^2 + 3x + 2
  4. Combine the like terms: f(x)βˆ’g(x)=2+2f(x) - g(x) = 2 + 2
  5. Evaluate the expression: f(x)βˆ’g(x)=4f(x) - g(x) = 4

Final Answer

The final answer is 4\boxed{4}.