How Many Moles Of Water Form When $183.5 \, \text{g} \, \text{Ba(OH)}_2$ Reacts With Excess HBr?$\[ \begin{array}{c} 2 \, \text{HBr} + \text{Ba(OH)}_2 \rightarrow \text{BaBr}_2 + 2 \, \text{H}_2\text{O} \\ \text{[?] Mol

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Understanding the Chemical Reaction

In this article, we will delve into the world of chemistry and explore the concept of balancing chemical equations and stoichiometry. We will use the given chemical reaction between barium hydroxide (Ba(OH)2) and hydrobromic acid (HBr) to determine the number of moles of water formed when a specific amount of Ba(OH)2 reacts with excess HBr.

The Chemical Equation

The given chemical equation is:

2 HBr+Ba(OH)2→BaBr2+2 H2O2 \, \text{HBr} + \text{Ba(OH)}_2 \rightarrow \text{BaBr}_2 + 2 \, \text{H}_2\text{O}

This equation shows that 2 moles of HBr react with 1 mole of Ba(OH)2 to produce 1 mole of BaBr2 and 2 moles of H2O.

Calculating the Number of Moles of Ba(OH)2

We are given that $183.5 , \text{g} , \text{Ba(OH)}_2$ reacts with excess HBr. To calculate the number of moles of Ba(OH)2, we need to know its molar mass. The molar mass of Ba(OH)2 is:

Ba=137.33 g/mol\text{Ba} = 137.33 \, \text{g/mol}

O=16.00 g/mol\text{O} = 16.00 \, \text{g/mol}

H=1.01 g/mol\text{H} = 1.01 \, \text{g/mol}

The molar mass of Ba(OH)2 is:

Molar mass of Ba(OH)2=137.33+2(16.00)+2(1.01)=171.35 g/mol\text{Molar mass of Ba(OH)}_2 = 137.33 + 2(16.00) + 2(1.01) = 171.35 \, \text{g/mol}

Now, we can calculate the number of moles of Ba(OH)2:

Number of moles of Ba(OH)2=Mass of Ba(OH)2Molar mass of Ba(OH)2\text{Number of moles of Ba(OH)}_2 = \frac{\text{Mass of Ba(OH)}_2}{\text{Molar mass of Ba(OH)}_2}

Number of moles of Ba(OH)2=183.5 g171.35 g/mol=1.072 mol\text{Number of moles of Ba(OH)}_2 = \frac{183.5 \, \text{g}}{171.35 \, \text{g/mol}} = 1.072 \, \text{mol}

Determining the Number of Moles of Water Formed

Now that we know the number of moles of Ba(OH)2, we can use the balanced chemical equation to determine the number of moles of water formed. According to the equation, 1 mole of Ba(OH)2 produces 2 moles of H2O. Therefore, the number of moles of water formed is:

Number of moles of H2O=2×Number of moles of Ba(OH)2\text{Number of moles of H}_2\text{O} = 2 \times \text{Number of moles of Ba(OH)}_2

Number of moles of H2O=2×1.072 mol=2.144 mol\text{Number of moles of H}_2\text{O} = 2 \times 1.072 \, \text{mol} = 2.144 \, \text{mol}

Conclusion

In this article, we used the concept of balancing chemical equations and stoichiometry to determine the number of moles of water formed when a specific amount of Ba(OH)2 reacts with excess HBr. We calculated the number of moles of Ba(OH)2 and then used the balanced chemical equation to determine the number of moles of water formed. The result shows that 2.144 moles of water are formed when 1.072 moles of Ba(OH)2 react with excess HBr.

References

  • CRC Handbook of Chemistry and Physics, 97th ed. (2016)
  • Chemical Equations and Stoichiometry, 2nd ed. (2018)

Additional Resources

  • Chemical Equations and Stoichiometry by OpenStax
  • Balancing Chemical Equations by Khan Academy
    Frequently Asked Questions: Balancing Chemical Equations and Stoichiometry ====================================================================

Q: What is the difference between a balanced chemical equation and an unbalanced chemical equation?

A: A balanced chemical equation is an equation in which the number of atoms of each element is the same on both the reactant and product sides. An unbalanced chemical equation is an equation in which the number of atoms of each element is not the same on both the reactant and product sides.

Q: How do I balance a chemical equation?

A: To balance a chemical equation, you need to add coefficients in front of the formulas of the reactants and products to make the number of atoms of each element the same on both sides. You can start by balancing the elements that appear only once on each side, and then work your way up to the elements that appear multiple times.

Q: What is stoichiometry?

A: Stoichiometry is the branch of chemistry that deals with the quantitative relationships between the reactants and products in a chemical reaction. It involves calculating the amounts of reactants and products in a reaction, and is essential for understanding the chemical properties and behavior of substances.

Q: How do I calculate the number of moles of a substance?

A: To calculate the number of moles of a substance, you need to know its molar mass and its mass. The molar mass is the mass of one mole of the substance, and the mass is the amount of the substance you have. You can calculate the number of moles using the formula:

Number of moles = Mass of substance / Molar mass of substance

Q: What is the mole ratio of reactants and products in a chemical reaction?

A: The mole ratio of reactants and products in a chemical reaction is the ratio of the number of moles of each reactant and product. It is calculated by dividing the number of moles of each product by the number of moles of each reactant.

Q: How do I use the mole ratio to calculate the amount of a substance?

A: To use the mole ratio to calculate the amount of a substance, you need to know the number of moles of the substance you want to calculate, and the mole ratio of the substance to the other substances in the reaction. You can calculate the amount of the substance using the formula:

Amount of substance = Number of moles of substance x Mole ratio

Q: What is the significance of the mole ratio in a chemical reaction?

A: The mole ratio is significant in a chemical reaction because it determines the amount of each substance that will be produced or consumed in the reaction. It is essential for understanding the chemical properties and behavior of substances, and for designing and optimizing chemical processes.

Q: How do I apply the mole ratio in real-world applications?

A: The mole ratio is applied in real-world applications such as:

  • Calculating the amount of reactants and products in a chemical reaction
  • Designing and optimizing chemical processes
  • Understanding the chemical properties and behavior of substances
  • Developing new products and technologies

Conclusion

In this article, we have answered some of the most frequently asked questions about balancing chemical equations and stoichiometry. We have discussed the importance of balancing chemical equations, the concept of stoichiometry, and how to calculate the number of moles of a substance. We have also explained the significance of the mole ratio in a chemical reaction and how to apply it in real-world applications.

References

  • CRC Handbook of Chemistry and Physics, 97th ed. (2016)
  • Chemical Equations and Stoichiometry, 2nd ed. (2018)

Additional Resources

  • Chemical Equations and Stoichiometry by OpenStax
  • Balancing Chemical Equations by Khan Academy