How Many Grams Of H2 Are Needed To React With 100 Grams Of N2 To Produce 121 Grams Of Nh3
Understanding the Chemical Reaction
The chemical reaction between hydrogen gas (H2) and nitrogen gas (N2) produces ammonia (NH3). The balanced chemical equation for this reaction is:
N2 + 3H2 → 2NH3
In this reaction, 1 mole of nitrogen gas reacts with 3 moles of hydrogen gas to produce 2 moles of ammonia.
Calculating the Molar Masses
To solve this problem, we need to calculate the molar masses of the reactants and products. The molar masses of the substances are:
- Nitrogen (N2): 28.02 g/mol
- Hydrogen (H2): 2.02 g/mol
- Ammonia (NH3): 17.03 g/mol
Calculating the Number of Moles of N2
We are given that 100 grams of N2 is used in the reaction. To calculate the number of moles of N2, we can use the formula:
moles = mass / molar mass
moles of N2 = 100 g / 28.02 g/mol = 3.57 mol
Calculating the Number of Moles of NH3 Produced
We are given that 121 grams of NH3 is produced in the reaction. To calculate the number of moles of NH3, we can use the formula:
moles = mass / molar mass
moles of NH3 = 121 g / 17.03 g/mol = 7.10 mol
Calculating the Number of Moles of H2 Required
From the balanced chemical equation, we know that 3 moles of H2 are required to react with 1 mole of N2. Since we have 3.57 mol of N2, we need:
moles of H2 = 3 × moles of N2 moles of H2 = 3 × 3.57 mol = 10.71 mol
Calculating the Mass of H2 Required
To calculate the mass of H2 required, we can use the formula:
mass = moles × molar mass
mass of H2 = 10.71 mol × 2.02 g/mol = 21.64 g
Conclusion
In conclusion, to react with 100 grams of N2 to produce 121 grams of NH3, we need 21.64 grams of H2.
Limitations of the Calculation
This calculation assumes that the reaction is 100% efficient, which is not possible in reality. In a real-world scenario, there will be some losses due to factors such as heat, light, and other impurities. Therefore, the actual amount of H2 required may be slightly higher than the calculated value.
Real-World Applications
This calculation has important implications in various industries such as:
- Fertilizer production: Ammonia is a key ingredient in the production of fertilizers. Understanding the stoichiometry of the reaction is crucial in optimizing the production process.
- Power generation: Ammonia can be used as a clean-burning fuel in power generation. The calculation of the stoichiometry of the reaction is essential in designing efficient power generation systems.
- Space exploration: Ammonia is used as a fuel in some spacecraft. The calculation of the stoichiometry of the reaction is critical in ensuring the efficient use of fuel during space missions.
Future Research Directions
This calculation highlights the importance of understanding the stoichiometry of chemical reactions. Future research directions may include:
- Optimizing the reaction conditions: Researchers may investigate ways to optimize the reaction conditions to improve the efficiency of the reaction.
- Developing new catalysts: Researchers may develop new catalysts to improve the rate of the reaction and reduce the energy required.
- Scaling up the reaction: Researchers may investigate ways to scale up the reaction to produce larger quantities of ammonia.
Conclusion
Q: What is the balanced chemical equation for the H2 + N2 → 2NH3 reaction?
A: The balanced chemical equation for the H2 + N2 → 2NH3 reaction is:
N2 + 3H2 → 2NH3
Q: What is the molar mass of each substance involved in the reaction?
A: The molar masses of the substances involved in the reaction are:
- Nitrogen (N2): 28.02 g/mol
- Hydrogen (H2): 2.02 g/mol
- Ammonia (NH3): 17.03 g/mol
Q: How do I calculate the number of moles of N2 used in the reaction?
A: To calculate the number of moles of N2 used in the reaction, you can use the formula:
moles = mass / molar mass
moles of N2 = 100 g / 28.02 g/mol = 3.57 mol
Q: How do I calculate the number of moles of NH3 produced in the reaction?
A: To calculate the number of moles of NH3 produced in the reaction, you can use the formula:
moles = mass / molar mass
moles of NH3 = 121 g / 17.03 g/mol = 7.10 mol
Q: How do I calculate the number of moles of H2 required for the reaction?
A: From the balanced chemical equation, we know that 3 moles of H2 are required to react with 1 mole of N2. Since we have 3.57 mol of N2, we need:
moles of H2 = 3 × moles of N2 moles of H2 = 3 × 3.57 mol = 10.71 mol
Q: How do I calculate the mass of H2 required for the reaction?
A: To calculate the mass of H2 required, you can use the formula:
mass = moles × molar mass
mass of H2 = 10.71 mol × 2.02 g/mol = 21.64 g
Q: What are some real-world applications of the H2 + N2 → 2NH3 reaction?
A: This reaction has important implications in various industries such as:
- Fertilizer production: Ammonia is a key ingredient in the production of fertilizers. Understanding the stoichiometry of the reaction is crucial in optimizing the production process.
- Power generation: Ammonia can be used as a clean-burning fuel in power generation. The calculation of the stoichiometry of the reaction is essential in designing efficient power generation systems.
- Space exploration: Ammonia is used as a fuel in some spacecraft. The calculation of the stoichiometry of the reaction is critical in ensuring the efficient use of fuel during space missions.
Q: What are some limitations of the calculation?
A: This calculation assumes that the reaction is 100% efficient, which is not possible in reality. In a real-world scenario, there will be some losses due to factors such as heat, light, and other impurities. Therefore, the actual amount of H2 required may be slightly higher than the calculated value.
Q: What are some future research directions for this reaction?
A: Some potential future research directions for this reaction include:
- Optimizing the reaction conditions: Researchers may investigate ways to optimize the reaction conditions to improve the efficiency of the reaction.
- Developing new catalysts: Researchers may develop new catalysts to improve the rate of the reaction and reduce the energy required.
- Scaling up the reaction: Researchers may investigate ways to scale up the reaction to produce larger quantities of ammonia.
Q: How can I apply this knowledge in my own research or industry?
A: This knowledge can be applied in various ways, such as:
- Optimizing chemical reactions: Understanding the stoichiometry of chemical reactions is crucial in optimizing the reaction conditions to improve the efficiency of the reaction.
- Designing new processes: The calculation of the stoichiometry of the reaction is essential in designing new processes and systems.
- Improving energy efficiency: The calculation of the stoichiometry of the reaction can help improve energy efficiency in various industries.