Graph The Function F ( X ) = X 2 + 8 X + 12 F(x) = X^2 + 8x + 12 F ( X ) = X 2 + 8 X + 12 .1. Plot The Vertex.2. Plot Another Point On The Parabola. (Note: If You Make A Mistake, You Can Erase Your Parabola By Selecting The Second Point And Placing It On Top Of The First.)

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Graphing the Function f(x)=x2+8x+12f(x) = x^2 + 8x + 12

Understanding the Function

The given function is a quadratic function in the form of f(x)=ax2+bx+cf(x) = ax^2 + bx + c, where a=1a = 1, b=8b = 8, and c=12c = 12. This type of function represents a parabola, which is a U-shaped curve that opens upwards or downwards. In this case, since the coefficient of x2x^2 is positive, the parabola opens upwards.

Finding the Vertex

To graph the function, we need to find the vertex of the parabola. The vertex is the lowest or highest point on the parabola, depending on whether it opens upwards or downwards. The x-coordinate of the vertex can be found using the formula x=βˆ’b2ax = -\frac{b}{2a}. Plugging in the values of aa and bb, we get:

x=βˆ’82(1)=βˆ’4x = -\frac{8}{2(1)} = -4

Now that we have the x-coordinate of the vertex, we can find the y-coordinate by plugging this value into the function:

f(βˆ’4)=(βˆ’4)2+8(βˆ’4)+12=16βˆ’32+12=βˆ’4f(-4) = (-4)^2 + 8(-4) + 12 = 16 - 32 + 12 = -4

So, the vertex of the parabola is at the point (βˆ’4,βˆ’4)(-4, -4).

Plotting the Vertex

To plot the vertex, we need to locate the point (βˆ’4,βˆ’4)(-4, -4) on the coordinate plane. We can do this by drawing a vertical line at x=βˆ’4x = -4 and a horizontal line at y=βˆ’4y = -4. The point where these two lines intersect is the vertex of the parabola.

Plotting Another Point on the Parabola

To plot another point on the parabola, we need to choose a value of xx and plug it into the function to find the corresponding value of yy. Let's choose x=0x = 0 as our new value. Plugging this into the function, we get:

f(0)=(0)2+8(0)+12=12f(0) = (0)^2 + 8(0) + 12 = 12

So, the point (0,12)(0, 12) is on the parabola.

Plotting the Parabola

To plot the parabola, we need to connect the vertex and the other point we just plotted. We can do this by drawing a smooth curve that passes through both points. The resulting curve is the parabola represented by the function f(x)=x2+8x+12f(x) = x^2 + 8x + 12.

Graphing the Function

Here is a step-by-step guide to graphing the function:

  1. Plot the vertex: Draw a vertical line at x=βˆ’4x = -4 and a horizontal line at y=βˆ’4y = -4. The point where these two lines intersect is the vertex of the parabola.
  2. Plot another point on the parabola: Choose a value of xx and plug it into the function to find the corresponding value of yy. Let's choose x=0x = 0 as our new value. Plugging this into the function, we get f(0)=12f(0) = 12. So, the point (0,12)(0, 12) is on the parabola.
  3. Plot the parabola: Draw a smooth curve that passes through both points. The resulting curve is the parabola represented by the function f(x)=x2+8x+12f(x) = x^2 + 8x + 12.

Conclusion

In this article, we graphed the function f(x)=x2+8x+12f(x) = x^2 + 8x + 12 by finding the vertex and plotting another point on the parabola. We also provided a step-by-step guide to graphing the function. By following these steps, you can graph the function and visualize the parabola represented by the function.

Graphing the Function: A Step-by-Step Guide

Step 1: Plot the Vertex

To plot the vertex, we need to locate the point (βˆ’4,βˆ’4)(-4, -4) on the coordinate plane. We can do this by drawing a vertical line at x=βˆ’4x = -4 and a horizontal line at y=βˆ’4y = -4. The point where these two lines intersect is the vertex of the parabola.

Step 2: Plot Another Point on the Parabola

To plot another point on the parabola, we need to choose a value of xx and plug it into the function to find the corresponding value of yy. Let's choose x=0x = 0 as our new value. Plugging this into the function, we get f(0)=12f(0) = 12. So, the point (0,12)(0, 12) is on the parabola.

Step 3: Plot the Parabola

To plot the parabola, we need to connect the vertex and the other point we just plotted. We can do this by drawing a smooth curve that passes through both points. The resulting curve is the parabola represented by the function f(x)=x2+8x+12f(x) = x^2 + 8x + 12.

Step 4: Graph the Function

To graph the function, we need to plot the vertex and another point on the parabola, and then connect these two points with a smooth curve. The resulting curve is the parabola represented by the function f(x)=x2+8x+12f(x) = x^2 + 8x + 12.

Graphing the Function: Tips and Tricks

  • Use a ruler: When plotting the vertex and another point on the parabola, use a ruler to draw a straight line.
  • Use a pencil: When plotting the parabola, use a pencil to draw a smooth curve.
  • Check your work: Before graphing the function, check your work to make sure that the vertex and another point on the parabola are correct.

Conclusion

In this article, we graphed the function f(x)=x2+8x+12f(x) = x^2 + 8x + 12 by finding the vertex and plotting another point on the parabola. We also provided a step-by-step guide to graphing the function and some tips and tricks to help you graph the function correctly. By following these steps and tips, you can graph the function and visualize the parabola represented by the function.
Graphing the Function f(x)=x2+8x+12f(x) = x^2 + 8x + 12: Q&A

Q: What is the vertex of the parabola represented by the function f(x)=x2+8x+12f(x) = x^2 + 8x + 12?

A: The vertex of the parabola is the point (βˆ’4,βˆ’4)(-4, -4).

Q: How do I find the vertex of the parabola?

A: To find the vertex of the parabola, you can use the formula x=βˆ’b2ax = -\frac{b}{2a}, where aa and bb are the coefficients of the quadratic function. In this case, a=1a = 1 and b=8b = 8, so the x-coordinate of the vertex is x=βˆ’82(1)=βˆ’4x = -\frac{8}{2(1)} = -4. To find the y-coordinate of the vertex, plug this value into the function: f(βˆ’4)=(βˆ’4)2+8(βˆ’4)+12=βˆ’4f(-4) = (-4)^2 + 8(-4) + 12 = -4.

Q: How do I plot another point on the parabola?

A: To plot another point on the parabola, choose a value of xx and plug it into the function to find the corresponding value of yy. For example, let's choose x=0x = 0 as our new value. Plugging this into the function, we get f(0)=(0)2+8(0)+12=12f(0) = (0)^2 + 8(0) + 12 = 12. So, the point (0,12)(0, 12) is on the parabola.

Q: How do I plot the parabola?

A: To plot the parabola, connect the vertex and the other point you plotted with a smooth curve. The resulting curve is the parabola represented by the function f(x)=x2+8x+12f(x) = x^2 + 8x + 12.

Q: What are some tips and tricks for graphing the function?

A: Here are some tips and tricks for graphing the function:

  • Use a ruler: When plotting the vertex and another point on the parabola, use a ruler to draw a straight line.
  • Use a pencil: When plotting the parabola, use a pencil to draw a smooth curve.
  • Check your work: Before graphing the function, check your work to make sure that the vertex and another point on the parabola are correct.

Q: What are some common mistakes to avoid when graphing the function?

A: Here are some common mistakes to avoid when graphing the function:

  • Not using a ruler: Failing to use a ruler when plotting the vertex and another point on the parabola can result in an inaccurate graph.
  • Not using a pencil: Failing to use a pencil when plotting the parabola can result in a graph that is not smooth.
  • Not checking your work: Failing to check your work before graphing the function can result in an inaccurate graph.

Q: How can I use graphing to solve problems involving the function?

A: Graphing can be a useful tool for solving problems involving the function. For example, you can use graphing to:

  • Find the x-intercepts: The x-intercepts of the parabola are the points where the parabola intersects the x-axis. You can use graphing to find the x-intercepts of the parabola.
  • Find the y-intercept: The y-intercept of the parabola is the point where the parabola intersects the y-axis. You can use graphing to find the y-intercept of the parabola.
  • Find the vertex: The vertex of the parabola is the point where the parabola is at its maximum or minimum value. You can use graphing to find the vertex of the parabola.

Q: What are some real-world applications of graphing the function?

A: Graphing the function has many real-world applications, including:

  • Physics: Graphing the function can be used to model the motion of objects in physics.
  • Engineering: Graphing the function can be used to model the behavior of systems in engineering.
  • Economics: Graphing the function can be used to model the behavior of economic systems.

Conclusion

In this article, we answered some common questions about graphing the function f(x)=x2+8x+12f(x) = x^2 + 8x + 12. We also provided some tips and tricks for graphing the function and some common mistakes to avoid. By following these tips and tricks, you can graph the function and visualize the parabola represented by the function.