Graph The Following Function:$\[ F(x) = (x-4)^2 - 3 \\]Consider The Shape Of The Graph To Determine Whether It Is A:A. Parabola B. Line C. Circle Utilize Graphing Tools As Needed To Visualize The Function.

by ADMIN 209 views

Introduction

In this article, we will explore the graph of the function f(x)=(xβˆ’4)2βˆ’3f(x) = (x-4)^2 - 3 and analyze its shape to determine whether it is a parabola, line, or circle. We will utilize graphing tools to visualize the function and gain a deeper understanding of its properties.

Understanding the Function

The given function is a quadratic function in the form of f(x)=a(xβˆ’h)2+kf(x) = a(x-h)^2 + k, where aa, hh, and kk are constants. In this case, a=1a = 1, h=4h = 4, and k=βˆ’3k = -3. This function represents a parabola that has been shifted horizontally by 44 units to the right and vertically by 33 units down.

Graphing the Function

To graph the function, we can start by plotting the vertex of the parabola, which is located at (h,k)=(4,βˆ’3)(h, k) = (4, -3). We can then use the fact that the parabola is symmetric about the vertical line x=hx = h to plot additional points.

import numpy as np
import matplotlib.pyplot as plt

# Define the function
def f(x):
    return (x-4)**2 - 3

# Generate x values
x = np.linspace(-10, 10, 400)

# Calculate y values
y = f(x)

# Create the plot
plt.plot(x, y)
plt.title('Graph of $f(x) = (x-4)^2 - 3{{content}}#39;)
plt.xlabel('x')
plt.ylabel('y')
plt.grid(True)
plt.axhline(0, color='black')
plt.axvline(0, color='black')
plt.show()

Analyzing the Shape of the Graph

From the graph, we can see that the function represents a parabola that opens upwards. The vertex of the parabola is located at (4,βˆ’3)(4, -3), and the parabola is symmetric about the vertical line x=4x = 4. This indicates that the function has a minimum value at x=4x = 4, and the value of the function decreases as we move away from the vertex.

Conclusion

In conclusion, the graph of the function f(x)=(xβˆ’4)2βˆ’3f(x) = (x-4)^2 - 3 represents a parabola that opens upwards. The vertex of the parabola is located at (4,βˆ’3)(4, -3), and the parabola is symmetric about the vertical line x=4x = 4. This indicates that the function has a minimum value at x=4x = 4, and the value of the function decreases as we move away from the vertex.

Comparison with Other Options

To determine whether the graph is a parabola, line, or circle, we can compare it with the characteristics of each option.

  • Parabola: A parabola is a U-shaped curve that opens upwards or downwards. The graph of the function f(x)=(xβˆ’4)2βˆ’3f(x) = (x-4)^2 - 3 represents a parabola that opens upwards, which matches the definition of a parabola.
  • Line: A line is a straight curve that extends infinitely in both directions. The graph of the function f(x)=(xβˆ’4)2βˆ’3f(x) = (x-4)^2 - 3 does not represent a line, as it has a U-shaped curve.
  • Circle: A circle is a closed curve that is symmetric about its center. The graph of the function f(x)=(xβˆ’4)2βˆ’3f(x) = (x-4)^2 - 3 does not represent a circle, as it has a U-shaped curve and is not symmetric about a center point.

Conclusion

In conclusion, the graph of the function f(x)=(xβˆ’4)2βˆ’3f(x) = (x-4)^2 - 3 represents a parabola that opens upwards. The vertex of the parabola is located at (4,βˆ’3)(4, -3), and the parabola is symmetric about the vertical line x=4x = 4. This indicates that the function has a minimum value at x=4x = 4, and the value of the function decreases as we move away from the vertex.

References

Discussion

What do you think about the graph of the function f(x)=(xβˆ’4)2βˆ’3f(x) = (x-4)^2 - 3? Do you think it represents a parabola, line, or circle? Why or why not? Share your thoughts in the comments below!

Related Topics

Final Thoughts

Introduction

In our previous article, we explored the graph of the function f(x)=(xβˆ’4)2βˆ’3f(x) = (x-4)^2 - 3 and analyzed its shape to determine whether it is a parabola, line, or circle. We also provided a Python code snippet to visualize the function using matplotlib. In this article, we will answer some frequently asked questions related to graphing and analyzing the function.

Q: What is the vertex of the parabola?

A: The vertex of the parabola is located at (4,βˆ’3)(4, -3). This is the point where the parabola changes direction and starts to open upwards.

Q: Is the parabola symmetric about the vertical line x=4x = 4?

A: Yes, the parabola is symmetric about the vertical line x=4x = 4. This means that if we reflect the parabola about the line x=4x = 4, we will get the same parabola.

Q: What is the minimum value of the function?

A: The minimum value of the function is βˆ’3-3, which occurs at x=4x = 4.

Q: Is the function a parabola, line, or circle?

A: The function is a parabola that opens upwards. It does not represent a line or circle.

Q: How can I graph the function using Python?

A: You can graph the function using the following Python code snippet:

import numpy as np
import matplotlib.pyplot as plt

# Define the function
def f(x):
    return (x-4)**2 - 3

# Generate x values
x = np.linspace(-10, 10, 400)

# Calculate y values
y = f(x)

# Create the plot
plt.plot(x, y)
plt.title('Graph of $f(x) = (x-4)^2 - 3{{content}}#39;)
plt.xlabel('x')
plt.ylabel('y')
plt.grid(True)
plt.axhline(0, color='black')
plt.axvline(0, color='black')
plt.show()

Q: Can I use other graphing tools to visualize the function?

A: Yes, you can use other graphing tools such as Desmos, GeoGebra, or Graphing Calculator to visualize the function.

Q: How can I analyze the shape of the graph?

A: You can analyze the shape of the graph by looking at the following characteristics:

  • The vertex of the parabola
  • The symmetry of the parabola about the vertical line x=4x = 4
  • The minimum value of the function
  • The direction of the parabola (upwards or downwards)

Conclusion

In conclusion, the graph of the function f(x)=(xβˆ’4)2βˆ’3f(x) = (x-4)^2 - 3 represents a parabola that opens upwards. The vertex of the parabola is located at (4,βˆ’3)(4, -3), and the parabola is symmetric about the vertical line x=4x = 4. This indicates that the function has a minimum value at x=4x = 4, and the value of the function decreases as we move away from the vertex.

References

Discussion

What do you think about the graph of the function f(x)=(xβˆ’4)2βˆ’3f(x) = (x-4)^2 - 3? Do you have any questions or comments about the article? Share your thoughts in the comments below!

Related Topics

Final Thoughts

In conclusion, the graph of the function f(x)=(xβˆ’4)2βˆ’3f(x) = (x-4)^2 - 3 represents a parabola that opens upwards. The vertex of the parabola is located at (4,βˆ’3)(4, -3), and the parabola is symmetric about the vertical line x=4x = 4. This indicates that the function has a minimum value at x=4x = 4, and the value of the function decreases as we move away from the vertex.