Given The Matrices $A$ And $B$ Shown Below, Find $-4A - 6B$.$\[ A = \begin{bmatrix} -4 & 6 & -4 \end{bmatrix} \quad B = \begin{bmatrix} -1 & -1 & 2 \end{bmatrix} \\](Note: The Problem Refers To Operations On 1x3

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Matrix Operations: Finding −4A−6B-4A - 6B

In linear algebra, matrices are used to represent systems of equations and perform various operations. Given two matrices AA and BB, we can perform scalar multiplication and addition/subtraction to obtain new matrices. In this article, we will explore how to find the matrix −4A−6B-4A - 6B using the given matrices AA and BB.

The given matrices are:

A=[−46−4]{ A = \begin{bmatrix} -4 & 6 & -4 \end{bmatrix} }

B=[−1−12]{ B = \begin{bmatrix} -1 & -1 & 2 \end{bmatrix} }

To find −4A-4A and −6B-6B, we need to perform scalar multiplication. Scalar multiplication involves multiplying each element of a matrix by a scalar.

−4A=−4[−46−4]=[16−2416]{ -4A = -4 \begin{bmatrix} -4 & 6 & -4 \end{bmatrix} = \begin{bmatrix} 16 & -24 & 16 \end{bmatrix} }

−6B=−6[−1−12]=[66−12]{ -6B = -6 \begin{bmatrix} -1 & -1 & 2 \end{bmatrix} = \begin{bmatrix} 6 & 6 & -12 \end{bmatrix} }

Now that we have −4A-4A and −6B-6B, we can find −4A−6B-4A - 6B by adding/subtracting the corresponding elements of the two matrices.

−4A−6B=[16−2416]−[66−12]{ -4A - 6B = \begin{bmatrix} 16 & -24 & 16 \end{bmatrix} - \begin{bmatrix} 6 & 6 & -12 \end{bmatrix} }

=[16−6−24−616−(−12)]{ = \begin{bmatrix} 16 - 6 & -24 - 6 & 16 - (-12) \end{bmatrix} }

=[10−3028]{ = \begin{bmatrix} 10 & -30 & 28 \end{bmatrix} }

In this article, we found the matrix −4A−6B-4A - 6B using the given matrices AA and BB. We performed scalar multiplication to find −4A-4A and −6B-6B, and then added/subtracted the corresponding elements to find the final matrix. This demonstrates the importance of understanding matrix operations in linear algebra.

  • Scalar multiplication involves multiplying each element of a matrix by a scalar.
  • Matrix addition/subtraction involves adding/subtracting the corresponding elements of two matrices.
  • Matrix operations can be used to solve systems of equations and perform various calculations.

Matrix operations have numerous real-world applications, including:

  • Computer Graphics: Matrix operations are used to perform transformations on 2D and 3D objects.
  • Machine Learning: Matrix operations are used to perform linear algebra operations on large datasets.
  • Data Analysis: Matrix operations are used to perform statistical analysis and data visualization.

In our previous article, we explored how to find the matrix −4A−6B-4A - 6B using the given matrices AA and BB. In this article, we will answer some frequently asked questions about matrix operations.

Q: What is scalar multiplication?

A: Scalar multiplication involves multiplying each element of a matrix by a scalar. For example, if we have a matrix A=[234]A = \begin{bmatrix} 2 & 3 & 4 \end{bmatrix} and a scalar k=3k = 3, then the scalar multiplication of AA and kk is given by:

kA=3[234]=[6912]{ kA = 3 \begin{bmatrix} 2 & 3 & 4 \end{bmatrix} = \begin{bmatrix} 6 & 9 & 12 \end{bmatrix} }

Q: What is matrix addition/subtraction?

A: Matrix addition/subtraction involves adding/subtracting the corresponding elements of two matrices. For example, if we have two matrices A=[234]A = \begin{bmatrix} 2 & 3 & 4 \end{bmatrix} and B=[567]B = \begin{bmatrix} 5 & 6 & 7 \end{bmatrix}, then the matrix addition of AA and BB is given by:

A+B=[234]+[567]=[7911]{ A + B = \begin{bmatrix} 2 & 3 & 4 \end{bmatrix} + \begin{bmatrix} 5 & 6 & 7 \end{bmatrix} = \begin{bmatrix} 7 & 9 & 11 \end{bmatrix} }

Q: Can I add/subtract matrices of different sizes?

A: No, you cannot add/subtract matrices of different sizes. The matrices must have the same number of rows and columns in order to perform addition/subtraction.

Q: Can I multiply matrices of different sizes?

A: No, you cannot multiply matrices of different sizes. The number of columns in the first matrix must be equal to the number of rows in the second matrix.

Q: What is the difference between matrix multiplication and scalar multiplication?

A: Matrix multiplication involves multiplying the elements of two matrices, while scalar multiplication involves multiplying each element of a matrix by a scalar.

Q: Can I use matrix operations to solve systems of equations?

A: Yes, matrix operations can be used to solve systems of equations. For example, if we have a system of equations:

2x+3y+4z=10{ 2x + 3y + 4z = 10 } 5x+6y+7z=20{ 5x + 6y + 7z = 20 }

We can represent this system as a matrix equation:

[234567][xyz]=[1020]{ \begin{bmatrix} 2 & 3 & 4 \\ 5 & 6 & 7 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} 10 \\ 20 \end{bmatrix} }

We can then use matrix operations to solve for xx, yy, and zz.

In this article, we answered some frequently asked questions about matrix operations. We covered topics such as scalar multiplication, matrix addition/subtraction, and matrix multiplication. We also discussed the importance of matrix operations in solving systems of equations.