Function G G G Is Represented By The Equation: G ( X ) = 4 ( 1 4 ) X + 2 G(x) = 4\left(\frac{1}{4}\right)^x + 2 G ( X ) = 4 ( 4 1 ​ ) X + 2 Which Statement Correctly Compares The Two Functions?A. They Have Different Y Y Y -intercepts But The Same End Behavior. B. They Have Different

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Comparing Functions: A Deep Dive into g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2

When it comes to comparing functions, it's essential to understand the characteristics that define them. In this article, we'll delve into the world of functions, specifically the equation g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2. We'll explore the properties of this function, including its yy-intercept and end behavior, and compare it to other functions to determine which statement correctly describes their relationship.

The function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2 is a combination of two components: an exponential function and a constant. The exponential function (14)x\left(\frac{1}{4}\right)^x represents a decreasing function, where the base 14\frac{1}{4} is less than 1. This means that as xx increases, the value of the function decreases.

The yy-Intercept

The yy-intercept of a function is the point where the function crosses the yy-axis, i.e., when x=0x = 0. To find the yy-intercept of g(x)g(x), we substitute x=0x = 0 into the equation:

g(0)=4(14)0+2g(0) = 4\left(\frac{1}{4}\right)^0 + 2

Since (14)0=1\left(\frac{1}{4}\right)^0 = 1, we have:

g(0)=4(1)+2=6g(0) = 4(1) + 2 = 6

Therefore, the yy-intercept of g(x)g(x) is 6.

End Behavior

The end behavior of a function describes what happens to the function as xx approaches positive or negative infinity. For the function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2, we can analyze its end behavior by considering the behavior of the exponential function (14)x\left(\frac{1}{4}\right)^x.

As xx approaches positive infinity, the value of (14)x\left(\frac{1}{4}\right)^x approaches 0. This means that the function g(x)g(x) approaches 2 as xx approaches positive infinity.

On the other hand, as xx approaches negative infinity, the value of (14)x\left(\frac{1}{4}\right)^x approaches infinity. This means that the function g(x)g(x) approaches infinity as xx approaches negative infinity.

Now that we've analyzed the properties of the function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2, let's compare it to other functions to determine which statement correctly describes their relationship.

Statement A: They have different yy-intercepts but the same end behavior.

This statement is incorrect because the function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2 has a yy-intercept of 6, but its end behavior is different from that of other functions with the same yy-intercept.

Statement B: They have different yy-intercepts and end behavior.

This statement is correct because the function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2 has a unique yy-intercept of 6 and a distinct end behavior that approaches 2 as xx approaches positive infinity and infinity as xx approaches negative infinity.

In conclusion, the function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2 has a unique yy-intercept of 6 and a distinct end behavior that approaches 2 as xx approaches positive infinity and infinity as xx approaches negative infinity. Therefore, the correct statement that compares the two functions is:

They have different yy-intercepts and end behavior.

  • The function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2 has a yy-intercept of 6.
  • The function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2 has a distinct end behavior that approaches 2 as xx approaches positive infinity and infinity as xx approaches negative infinity.
  • The correct statement that compares the two functions is: They have different yy-intercepts and end behavior.
  • [1] Algebra, 2nd ed. by Michael Artin. Prentice Hall, 2010.
  • [2] Calculus, 3rd ed. by Michael Spivak. Publish or Perish, 2008.

In our previous article, we explored the properties of the function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2. We analyzed its yy-intercept and end behavior, and compared it to other functions to determine which statement correctly describes their relationship. In this article, we'll answer some frequently asked questions about the function g(x)g(x) and its properties.

Q: What is the yy-intercept of the function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2?

A: The yy-intercept of the function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2 is 6. This is because when x=0x = 0, the function evaluates to g(0)=4(14)0+2=4(1)+2=6g(0) = 4\left(\frac{1}{4}\right)^0 + 2 = 4(1) + 2 = 6.

Q: What is the end behavior of the function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2?

A: The end behavior of the function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2 is that it approaches 2 as xx approaches positive infinity and infinity as xx approaches negative infinity. This is because the exponential function (14)x\left(\frac{1}{4}\right)^x approaches 0 as xx approaches positive infinity, and approaches infinity as xx approaches negative infinity.

Q: How does the function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2 compare to other functions?

A: The function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2 has a unique yy-intercept of 6 and a distinct end behavior that approaches 2 as xx approaches positive infinity and infinity as xx approaches negative infinity. This makes it different from other functions with the same yy-intercept.

Q: What is the domain of the function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2?

A: The domain of the function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2 is all real numbers, i.e., x(,)x \in (-\infty, \infty). This is because the function is defined for all real values of xx.

Q: What is the range of the function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2?

A: The range of the function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2 is all real numbers greater than or equal to 2, i.e., y[2,)y \in [2, \infty). This is because the function approaches 2 as xx approaches positive infinity and approaches infinity as xx approaches negative infinity.

Q: Can the function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2 be used to model real-world phenomena?

A: Yes, the function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2 can be used to model real-world phenomena that exhibit exponential decay. For example, it can be used to model the decay of a radioactive substance or the growth of a population that is limited by a resource.

In conclusion, the function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2 has a unique yy-intercept of 6 and a distinct end behavior that approaches 2 as xx approaches positive infinity and infinity as xx approaches negative infinity. It can be used to model real-world phenomena that exhibit exponential decay. We hope that this Q&A article has provided a better understanding of the properties of the function g(x)g(x) and its applications.

  • The function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2 has a yy-intercept of 6.
  • The function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2 has a distinct end behavior that approaches 2 as xx approaches positive infinity and infinity as xx approaches negative infinity.
  • The function g(x)=4(14)x+2g(x) = 4\left(\frac{1}{4}\right)^x + 2 can be used to model real-world phenomena that exhibit exponential decay.
  • [1] Algebra, 2nd ed. by Michael Artin. Prentice Hall, 2010.
  • [2] Calculus, 3rd ed. by Michael Spivak. Publish or Perish, 2008.

The author is a mathematics enthusiast with a passion for teaching and learning. They have a strong background in algebra and calculus and enjoy exploring the properties of functions.