For The Following Exercise, Given The Function F F F , Evaluate F ( − 1 F(-1 F ( − 1 ], F ( 0 F(0 F ( 0 ], F ( 2 F(2 F ( 2 ], And F ( 4 F(4 F ( 4 ].$[ f(x) = \begin{cases} 2x & \text{for } X \ \textless \ 0 \ 3 & \text{for } 0 \leq X \leq 3 \ x^2

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In this exercise, we are given a function f(x)f(x) and asked to evaluate it at specific values of xx. The function f(x)f(x) is defined as:

f(x)={2xfor x<03for 0x3x2for x>3f(x) = \begin{cases} 2x & \text{for } x < 0 \\ 3 & \text{for } 0 \leq x \leq 3 \\ x^2 & \text{for } x > 3 \end{cases}

To evaluate the function at specific values of xx, we need to determine which part of the piecewise function applies to each value of xx. We will then substitute the value of xx into the corresponding part of the function to find the value of f(x)f(x).

Evaluating f(-1)

To evaluate f(1)f(-1), we need to determine which part of the piecewise function applies to x=1x = -1. Since x=1x = -1 is less than 0, we use the first part of the function, which is f(x)=2xf(x) = 2x. Substituting x=1x = -1 into this part of the function, we get:

f(1)=2(1)=2f(-1) = 2(-1) = -2

Therefore, f(1)=2f(-1) = -2.

Evaluating f(0)

To evaluate f(0)f(0), we need to determine which part of the piecewise function applies to x=0x = 0. Since x=0x = 0 is between 0 and 3 (inclusive), we use the second part of the function, which is f(x)=3f(x) = 3. Substituting x=0x = 0 into this part of the function, we get:

f(0)=3f(0) = 3

Therefore, f(0)=3f(0) = 3.

Evaluating f(2)

To evaluate f(2)f(2), we need to determine which part of the piecewise function applies to x=2x = 2. Since x=2x = 2 is between 0 and 3 (inclusive), we use the second part of the function, which is f(x)=3f(x) = 3. Substituting x=2x = 2 into this part of the function, we get:

f(2)=3f(2) = 3

Therefore, f(2)=3f(2) = 3.

Evaluating f(4)

To evaluate f(4)f(4), we need to determine which part of the piecewise function applies to x=4x = 4. Since x=4x = 4 is greater than 3, we use the third part of the function, which is f(x)=x2f(x) = x^2. Substituting x=4x = 4 into this part of the function, we get:

f(4)=42=16f(4) = 4^2 = 16

Therefore, f(4)=16f(4) = 16.

Conclusion

In this exercise, we evaluated the function f(x)f(x) at specific values of xx. We determined which part of the piecewise function applied to each value of xx and substituted the value of xx into the corresponding part of the function to find the value of f(x)f(x). The values of f(x)f(x) at x=1x = -1, x=0x = 0, x=2x = 2, and x=4x = 4 are 2-2, 33, 33, and 1616, respectively.

Key Takeaways

  • To evaluate a piecewise function at a specific value of xx, we need to determine which part of the function applies to that value of xx.
  • We can substitute the value of xx into the corresponding part of the function to find the value of the function at that value of xx.
  • The function f(x)f(x) is defined as a piecewise function, which means it has different definitions for different intervals of xx.

Further Exploration

  • What happens to the function f(x)f(x) as xx approaches 0 from the left and from the right?
  • How does the function f(x)f(x) behave as xx increases without bound?
  • Can we find a pattern in the values of f(x)f(x) as xx increases without bound?

References

In this article, we evaluated the function f(x)f(x) at specific values of xx. We determined which part of the piecewise function applied to each value of xx and substituted the value of xx into the corresponding part of the function to find the value of f(x)f(x). In this Q&A section, we will answer some common questions related to the function f(x)f(x).

Q: What is a piecewise function?

A: A piecewise function is a function that is defined by multiple sub-functions, each of which is applied to a specific interval of the input variable. In the case of the function f(x)f(x), it is defined as:

f(x)={2xfor x<03for 0x3x2for x>3f(x) = \begin{cases} 2x & \text{for } x < 0 \\ 3 & \text{for } 0 \leq x \leq 3 \\ x^2 & \text{for } x > 3 \end{cases}

Q: How do I determine which part of the piecewise function applies to a given value of x?

A: To determine which part of the piecewise function applies to a given value of xx, you need to compare the value of xx to the intervals defined in the function. For example, if x=2x = 2, you would compare xx to the intervals x<0x < 0, 0x30 \leq x \leq 3, and x>3x > 3. Since x=2x = 2 is between 0 and 3 (inclusive), you would use the second part of the function, which is f(x)=3f(x) = 3.

Q: What happens if x is equal to one of the endpoints of an interval?

A: If xx is equal to one of the endpoints of an interval, you need to use the corresponding part of the function. For example, if x=0x = 0, you would use the second part of the function, which is f(x)=3f(x) = 3. Similarly, if x=3x = 3, you would also use the second part of the function, which is f(x)=3f(x) = 3.

Q: Can I use the same part of the function for multiple intervals?

A: No, you cannot use the same part of the function for multiple intervals. Each part of the function is defined for a specific interval, and you need to use the corresponding part of the function for each interval.

Q: How do I evaluate the function f(x) at a value of x that is not in any of the intervals?

A: If xx is not in any of the intervals, you need to check if it is less than 0, between 0 and 3 (inclusive), or greater than 3. If it is less than 0, you would use the first part of the function, which is f(x)=2xf(x) = 2x. If it is between 0 and 3 (inclusive), you would use the second part of the function, which is f(x)=3f(x) = 3. If it is greater than 3, you would use the third part of the function, which is f(x)=x2f(x) = x^2.

Q: Can I simplify the function f(x) by combining the different parts?

A: Yes, you can simplify the function f(x)f(x) by combining the different parts. For example, you can rewrite the function as:

f(x)={2xfor x<03for 0x3x2for x>3={2xfor x<03for 0x3x2for x>3f(x) = \begin{cases} 2x & \text{for } x < 0 \\ 3 & \text{for } 0 \leq x \leq 3 \\ x^2 & \text{for } x > 3 \end{cases} = \begin{cases} 2x & \text{for } x < 0 \\ 3 & \text{for } 0 \leq x \leq 3 \\ x^2 & \text{for } x > 3 \end{cases}

However, this simplification does not change the fact that the function is defined by multiple sub-functions, each of which is applied to a specific interval of the input variable.

Q: What are some common applications of piecewise functions?

A: Piecewise functions have many common applications in mathematics, science, and engineering. Some examples include:

  • Modeling real-world phenomena that have different behaviors in different intervals, such as the cost of a product that changes depending on the quantity ordered.
  • Representing data that has different patterns in different intervals, such as the population growth of a species that changes depending on the availability of resources.
  • Solving problems that involve different equations in different intervals, such as the motion of an object that changes depending on the force applied.

Conclusion

In this Q&A section, we answered some common questions related to the function f(x)f(x). We discussed how to determine which part of the piecewise function applies to a given value of xx, how to evaluate the function at a value of xx that is not in any of the intervals, and how to simplify the function by combining the different parts. We also discussed some common applications of piecewise functions.

Key Takeaways

  • To evaluate a piecewise function at a specific value of xx, you need to determine which part of the function applies to that value of xx.
  • You can use the corresponding part of the function for each interval.
  • Piecewise functions have many common applications in mathematics, science, and engineering.

Further Exploration

  • What are some other examples of piecewise functions?
  • How can you use piecewise functions to model real-world phenomena?
  • What are some common challenges when working with piecewise functions?