For A Circle Defined By The Given Equation, What Are The Coordinates Of The Center And The Length Of The Radius? X 2 + Y 2 − 4 X − 10 Y + 20 = 0 X^2 + Y^2 - 4x - 10y + 20 = 0 X 2 + Y 2 − 4 X − 10 Y + 20 = 0 A. Center: ( − 2 , − 5 (-2, -5 ( − 2 , − 5 ], Radius: 9 Units B. Center: ( 2 , 5 (2, 5 ( 2 , 5 ], Radius: 9 Units C.

Understanding the General Form of a Circle's Equation

The general form of a circle's equation is given by $(x - h)^2 + (y - k)^2 = r^2$, where $(h, k)$ represents the coordinates of the center of the circle, and $r$ is the length of the radius. However, the given equation is in the form $x^2 + y^2 - 4x - 10y + 20 = 0$. To find the center and radius, we need to convert this equation into the standard form.

Converting the Given Equation into Standard Form

To convert the given equation into standard form, we need to complete the square for both the $x$ and $y$ terms. We start by grouping the $x$ terms and $y$ terms separately:

$x^2 - 4x + y^2 - 10y = -20$

Next, we add the square of half the coefficient of $x$ to the $x$ terms and the square of half the coefficient of $y$ to the $y$ terms. The coefficient of $x$ is $-4$, so half of it is $-2$, and its square is $4$. The coefficient of $y$ is $-10$, so half of it is $-5$, and its square is $25$. We add these values to both sides of the equation:

$x^2 - 4x + 4 + y^2 - 10y + 25 = -20 + 4 + 25$

This simplifies to:

$(x - 2)^2 + (y - 5)^2 = 9$

Identifying the Center and Radius

Now that we have the equation in standard form, we can easily identify the center and radius. The center of the circle is given by the values inside the parentheses, which are $(2, 5)$. The radius is the square root of the value on the right-hand side, which is $\sqrt{9} = 3$. However, the options provided suggest that the radius is 9 units, which seems to be an error. The correct radius is 3 units.

Conclusion

In conclusion, the center of the circle defined by the given equation is $(2, 5)$, and the length of the radius is 3 units.

Discussion

The given equation is a circle with center $(2, 5)$ and radius 3 units. However, the options provided suggest that the radius is 9 units, which is incorrect. This highlights the importance of carefully reading and understanding the problem statement.

Common Mistakes

One common mistake that students make when working with circle equations is failing to complete the square correctly. This can lead to incorrect values for the center and radius. Another mistake is not checking the units of the radius, which can result in incorrect answers.

Real-World Applications

Understanding how to find the center and radius of a circle from its equation has many real-world applications. For example, in engineering, it is essential to know the center and radius of a circle to design and build structures such as bridges, tunnels, and buildings. In computer graphics, it is necessary to calculate the center and radius of a circle to create realistic images and animations.

Tips and Tricks

To find the center and radius of a circle from its equation, it is essential to complete the square correctly. This involves adding the square of half the coefficient of $x$ to the $x$ terms and the square of half the coefficient of $y$ to the $y$ terms. Additionally, it is crucial to check the units of the radius to ensure that the answer is correct.

Practice Problems

To practice finding the center and radius of a circle from its equation, try the following problems:

• Find the center and radius of the circle defined by the equation $(x + 3)^2 + (y - 2)^2 = 16$.
• Find the center and radius of the circle defined by the equation $(x - 1)^2 + (y + 4)^2 = 9$.

Conclusion

In conclusion, finding the center and radius of a circle from its equation is a crucial skill in mathematics and has many real-world applications. By understanding how to complete the square and check the units of the radius, students can accurately find the center and radius of a circle.

Q: What is the general form of a circle's equation?

A: The general form of a circle's equation is given by $(x - h)^2 + (y - k)^2 = r^2$, where $(h, k)$ represents the coordinates of the center of the circle, and $r$ is the length of the radius.

Q: How do I convert a circle's equation from general form to standard form?

A: To convert a circle's equation from general form to standard form, you need to complete the square for both the $x$ and $y$ terms. This involves adding the square of half the coefficient of $x$ to the $x$ terms and the square of half the coefficient of $y$ to the $y$ terms.

Q: What is the significance of completing the square in finding the center and radius of a circle?

A: Completing the square is essential in finding the center and radius of a circle because it allows you to rewrite the equation in standard form, which makes it easier to identify the center and radius.

Q: How do I identify the center and radius of a circle from its equation in standard form?

A: To identify the center and radius of a circle from its equation in standard form, you need to look at the values inside the parentheses, which represent the coordinates of the center, and the value on the right-hand side, which represents the square of the radius.

Q: What is the difference between the general form and standard form of a circle's equation?

A: The general form of a circle's equation is given by $(x - h)^2 + (y - k)^2 = r^2$, while the standard form is given by $(x - h)^2 + (y - k)^2 = a$, where $a$ is a constant. The standard form is easier to work with because it makes it easier to identify the center and radius.

Q: Can I find the center and radius of a circle from its equation if it is not in standard form?

A: Yes, you can find the center and radius of a circle from its equation even if it is not in standard form. However, it may be more difficult to do so, and you may need to use more advanced techniques, such as completing the square or using the distance formula.

Q: What are some common mistakes to avoid when finding the center and radius of a circle?

A: Some common mistakes to avoid when finding the center and radius of a circle include failing to complete the square correctly, not checking the units of the radius, and not using the correct formula.

Q: How do I check the units of the radius to ensure that my answer is correct?

A: To check the units of the radius, you need to make sure that the units of the radius are consistent with the units of the other values in the equation. For example, if the equation is in meters, the radius should be in meters.

Q: What are some real-world applications of finding the center and radius of a circle?

A: Finding the center and radius of a circle has many real-world applications, including engineering, computer graphics, and architecture. It is essential to know how to find the center and radius of a circle to design and build structures such as bridges, tunnels, and buildings.

Q: How can I practice finding the center and radius of a circle?

A: You can practice finding the center and radius of a circle by working through problems and exercises, such as those found in textbooks or online resources. You can also try creating your own problems and solving them to test your skills.

Q: What are some tips and tricks for finding the center and radius of a circle?

A: Some tips and tricks for finding the center and radius of a circle include completing the square correctly, checking the units of the radius, and using the correct formula. It is also essential to be careful and patient when working through problems, as small mistakes can lead to large errors.