Find, Using Algebra, All Real Solutions To The Equation:$\[ B^4 + 7b^2 - 18 = 0 \\]\[$ B = \square \$\]or\[$ B = \$\]

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Introduction

In this article, we will delve into the world of algebra and explore the process of solving a quartic equation. A quartic equation is a polynomial equation of degree four, which means that the highest power of the variable is four. In this case, we are given the equation b4+7b2βˆ’18=0b^4 + 7b^2 - 18 = 0, and we need to find all real solutions to this equation.

Understanding the Equation

Before we begin solving the equation, let's take a closer look at its structure. The equation is a quartic equation in the variable bb, and it can be written in the form ax4+bx2+c=0ax^4 + bx^2 + c = 0, where aa, bb, and cc are constants. In this case, a=1a = 1, b=7b = 7, and c=βˆ’18c = -18.

Substitution Method

One way to solve this equation is to use the substitution method. We can substitute x=b2x = b^2 into the equation, which gives us x2+7xβˆ’18=0x^2 + 7x - 18 = 0. This is a quadratic equation in the variable xx, and we can solve it using the quadratic formula.

Quadratic Formula

The quadratic formula is given by x=βˆ’bΒ±b2βˆ’4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}. In this case, a=1a = 1, b=7b = 7, and c=βˆ’18c = -18. Plugging these values into the formula, we get:

x=βˆ’7Β±72βˆ’4(1)(βˆ’18)2(1)x = \frac{-7 \pm \sqrt{7^2 - 4(1)(-18)}}{2(1)}

Simplifying the Expression

Simplifying the expression under the square root, we get:

x=βˆ’7Β±49+722x = \frac{-7 \pm \sqrt{49 + 72}}{2}

x=βˆ’7Β±1212x = \frac{-7 \pm \sqrt{121}}{2}

x=βˆ’7Β±112x = \frac{-7 \pm 11}{2}

Solving for x

Now we have two possible values for xx:

x=βˆ’7+112=2x = \frac{-7 + 11}{2} = 2

x=βˆ’7βˆ’112=βˆ’9x = \frac{-7 - 11}{2} = -9

Substituting Back

Now that we have found the values of xx, we can substitute back to find the values of bb. Remember that x=b2x = b^2, so we can take the square root of both sides to get:

b=Β±xb = \pm \sqrt{x}

Finding the Values of b

Substituting the values of xx into this equation, we get:

b=Β±2b = \pm \sqrt{2}

b=Β±βˆ’9b = \pm \sqrt{-9}

Simplifying the Square Roots

Simplifying the square roots, we get:

b=Β±2b = \pm \sqrt{2}

b=Β±3ib = \pm 3i

Conclusion

In this article, we have solved the quartic equation b4+7b2βˆ’18=0b^4 + 7b^2 - 18 = 0 using the substitution method and the quadratic formula. We have found that the real solutions to this equation are b=Β±2b = \pm \sqrt{2}, and the complex solutions are b=Β±3ib = \pm 3i.

Final Answer

The final answer is b=Β±2,b=Β±3i\boxed{b = \pm \sqrt{2}, b = \pm 3i}.

Additional Information

It's worth noting that the equation b4+7b2βˆ’18=0b^4 + 7b^2 - 18 = 0 can also be solved using other methods, such as factoring or using a graphing calculator. However, the substitution method and the quadratic formula are two of the most common and effective methods for solving quartic equations.

Real-World Applications

Quartic equations have many real-world applications, such as modeling population growth, chemical reactions, and electrical circuits. In these applications, the solutions to the equation can provide valuable insights into the behavior of the system being modeled.

Future Research

There are many areas of research that involve quartic equations, such as algebraic geometry, number theory, and computer science. Researchers in these fields are constantly developing new methods and techniques for solving quartic equations, and exploring their applications in various fields.

Conclusion

In conclusion, solving the quartic equation b4+7b2βˆ’18=0b^4 + 7b^2 - 18 = 0 using the substitution method and the quadratic formula has provided us with a deeper understanding of the structure and behavior of this type of equation. The real solutions to this equation are b=Β±2b = \pm \sqrt{2}, and the complex solutions are b=Β±3ib = \pm 3i. This knowledge can be applied to various fields, such as algebraic geometry, number theory, and computer science.

Introduction

In our previous article, we explored the process of solving a quartic equation using the substitution method and the quadratic formula. In this article, we will answer some of the most frequently asked questions about quartic equations and provide additional insights into this fascinating topic.

Q: What is a quartic equation?

A: A quartic equation is a polynomial equation of degree four, which means that the highest power of the variable is four. It can be written in the form ax4+bx2+c=0ax^4 + bx^2 + c = 0, where aa, bb, and cc are constants.

Q: How do I solve a quartic equation?

A: There are several methods for solving quartic equations, including the substitution method, the quadratic formula, factoring, and using a graphing calculator. The method you choose will depend on the specific equation and your level of expertise.

Q: What are the real solutions to a quartic equation?

A: The real solutions to a quartic equation are the values of the variable that make the equation true. These solutions can be found using various methods, including the substitution method and the quadratic formula.

Q: What are the complex solutions to a quartic equation?

A: The complex solutions to a quartic equation are the values of the variable that make the equation true, but involve imaginary numbers. These solutions can be found using various methods, including the substitution method and the quadratic formula.

Q: Can I use a graphing calculator to solve a quartic equation?

A: Yes, you can use a graphing calculator to solve a quartic equation. Simply enter the equation into the calculator and use the "solve" function to find the solutions.

Q: What are some real-world applications of quartic equations?

A: Quartic equations have many real-world applications, such as modeling population growth, chemical reactions, and electrical circuits. In these applications, the solutions to the equation can provide valuable insights into the behavior of the system being modeled.

Q: Can I use quartic equations to model real-world phenomena?

A: Yes, you can use quartic equations to model real-world phenomena. For example, you can use a quartic equation to model the growth of a population over time, or the behavior of a chemical reaction.

Q: What are some common mistakes to avoid when solving quartic equations?

A: Some common mistakes to avoid when solving quartic equations include:

  • Not checking the solutions to see if they are real or complex
  • Not using the correct method for solving the equation
  • Not checking the solutions to see if they satisfy the original equation
  • Not using a graphing calculator to check the solutions

Q: Can I use quartic equations to solve other types of equations?

A: Yes, you can use quartic equations to solve other types of equations. For example, you can use a quartic equation to solve a quadratic equation, or a cubic equation.

Q: What are some advanced topics in quartic equations?

A: Some advanced topics in quartic equations include:

  • Algebraic geometry: This is the study of the geometric properties of algebraic varieties, including quartic equations.
  • Number theory: This is the study of the properties of integers and other whole numbers, including the solutions to quartic equations.
  • Computer science: This is the study of the use of computers to solve problems, including the use of quartic equations to model real-world phenomena.

Conclusion

In conclusion, quartic equations are a fascinating topic that has many real-world applications. By understanding how to solve quartic equations, you can gain insights into the behavior of complex systems and make predictions about future events. Whether you are a student, a researcher, or a professional, quartic equations are an essential tool for anyone interested in mathematics and science.

Final Answer

The final answer is b=Β±2,b=Β±3i\boxed{b = \pm \sqrt{2}, b = \pm 3i}.

Additional Resources

For more information on quartic equations, including tutorials, examples, and exercises, please visit our website at [insert website URL].