Find The Limit. Use L'Hospital's Rule Where Appropriate. If There Is A More Elementary Method, Consider Using It. Lim ⁡ X → 0 + ( Tan ⁡ ( 3 X ) ) X \lim _{x \rightarrow 0^{+}}(\tan (3x))^x Lim X → 0 + ​ ( Tan ( 3 X ) ) X

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Introduction

Limits are a fundamental concept in calculus, and understanding how to evaluate them is crucial for solving various mathematical problems. In this article, we will explore the limit of the expression (tan(3x))x(\tan (3x))^x as xx approaches 00 from the right. We will use L'Hospital's Rule where necessary and consider more elementary methods if available.

Understanding the Problem

The given limit is limx0+(tan(3x))x\lim _{x \rightarrow 0^{+}}(\tan (3x))^x. This expression involves the tangent function and exponentiation. To evaluate this limit, we need to consider the behavior of the tangent function as xx approaches 00 from the right.

Elementary Method: Direct Substitution

Let's start by attempting to evaluate the limit using direct substitution. We substitute x=0x = 0 into the expression:

(tan(3(0)))0=(tan(0))0=10=1(\tan (3(0)))^0 = (\tan (0))^0 = 1^0 = 1

However, this result is not helpful, as we are interested in the behavior of the expression as xx approaches 00 from the right. Direct substitution does not provide any insight into the limit.

Using L'Hospital's Rule

L'Hospital's Rule states that if a limit is in the form limxaf(x)g(x)\lim _{x \rightarrow a} \frac{f(x)}{g(x)} and f(x)f(x) and g(x)g(x) are both differentiable at x=ax = a, then the limit can be evaluated as:

limxaf(x)g(x)=limxaf(x)g(x)\lim _{x \rightarrow a} \frac{f(x)}{g(x)} = \lim _{x \rightarrow a} \frac{f'(x)}{g'(x)}

In our case, we can rewrite the expression as:

limx0+(tan(3x))x=limx0+eln((tan(3x))x)\lim _{x \rightarrow 0^{+}}(\tan (3x))^x = \lim _{x \rightarrow 0^{+}} e^{\ln((\tan (3x))^x)}

Using the property of logarithms, we can simplify the expression:

ln((tan(3x))x)=xln(tan(3x))\ln((\tan (3x))^x) = x \ln(\tan (3x))

Now, we can apply L'Hospital's Rule:

limx0+xln(tan(3x))=limx0+ln(tan(3x))1x\lim _{x \rightarrow 0^{+}} x \ln(\tan (3x)) = \lim _{x \rightarrow 0^{+}} \frac{\ln(\tan (3x))}{\frac{1}{x}}

This limit is in the form limxaf(x)g(x)\lim _{x \rightarrow a} \frac{f(x)}{g(x)}, where f(x)=ln(tan(3x))f(x) = \ln(\tan (3x)) and g(x)=1xg(x) = \frac{1}{x}. We can apply L'Hospital's Rule again:

limx0+ln(tan(3x))1x=limx0+1tan(3x)31x2\lim _{x \rightarrow 0^{+}} \frac{\ln(\tan (3x))}{\frac{1}{x}} = \lim _{x \rightarrow 0^{+}} \frac{\frac{1}{\tan (3x)} \cdot 3}{-\frac{1}{x^2}}

Simplifying the expression, we get:

limx0+1tan(3x)31x2=limx0+x231tan(3x)\lim _{x \rightarrow 0^{+}} \frac{\frac{1}{\tan (3x)} \cdot 3}{-\frac{1}{x^2}} = \lim _{x \rightarrow 0^{+}} -\frac{x^2}{3} \cdot \frac{1}{\tan (3x)}

Now, we can evaluate the limit:

limx0+x231tan(3x)=0231tan(0)=0\lim _{x \rightarrow 0^{+}} -\frac{x^2}{3} \cdot \frac{1}{\tan (3x)} = -\frac{0^2}{3} \cdot \frac{1}{\tan (0)} = 0

Evaluating the Original Limit

Now that we have evaluated the limit of the expression inside the exponential function, we can evaluate the original limit:

limx0+(tan(3x))x=elimx0+xln(tan(3x))=e0=1\lim _{x \rightarrow 0^{+}}(\tan (3x))^x = e^{\lim _{x \rightarrow 0^{+}} x \ln(\tan (3x))} = e^0 = 1

Conclusion

In this article, we evaluated the limit of the expression (tan(3x))x(\tan (3x))^x as xx approaches 00 from the right. We used L'Hospital's Rule to evaluate the limit of the expression inside the exponential function and then evaluated the original limit. The result is 1\boxed{1}.

Additional Examples

  • limx0+(sin(2x))x\lim _{x \rightarrow 0^{+}}(\sin (2x))^x
  • limx0+(cos(x))x\lim _{x \rightarrow 0^{+}}(\cos (x))^x
  • limx0+(tan(x))x\lim _{x \rightarrow 0^{+}}(\tan (x))^x

These examples can be evaluated using similar techniques as the one presented in this article.

References

  • L'Hospital, G. F. A. (1696). Methodus differentialis.
  • Spivak, M. (1965). Calculus on manifolds. W.A. Benjamin.
  • Rudin, W. (1976). Principles of mathematical analysis. McGraw-Hill.

Q: What is the limit of the expression (tan(3x))x(\tan (3x))^x as xx approaches 00 from the right?

A: The limit of the expression (tan(3x))x(\tan (3x))^x as xx approaches 00 from the right is 1\boxed{1}.

Q: Why did we use L'Hospital's Rule to evaluate the limit?

A: We used L'Hospital's Rule to evaluate the limit because the expression inside the exponential function was in the form limxaf(x)g(x)\lim _{x \rightarrow a} \frac{f(x)}{g(x)}, where f(x)f(x) and g(x)g(x) are both differentiable at x=ax = a. L'Hospital's Rule states that in this case, the limit can be evaluated as limxaf(x)g(x)\lim _{x \rightarrow a} \frac{f'(x)}{g'(x)}.

Q: What is the significance of the result 1\boxed{1}?

A: The result 1\boxed{1} indicates that the expression (tan(3x))x(\tan (3x))^x approaches 11 as xx approaches 00 from the right. This means that the expression is bounded between 00 and 11 as xx approaches 00 from the right.

Q: Can we use other methods to evaluate the limit?

A: Yes, we can use other methods to evaluate the limit. For example, we can use the property of logarithms to rewrite the expression as eln((tan(3x))x)=exln(tan(3x))e^{\ln((\tan (3x))^x)} = e^{x \ln(\tan (3x))}. Then, we can use L'Hospital's Rule to evaluate the limit of the expression inside the exponential function.

Q: What are some other examples of limits that can be evaluated using L'Hospital's Rule?

A: Some other examples of limits that can be evaluated using L'Hospital's Rule include:

  • limx0+(sin(2x))x\lim _{x \rightarrow 0^{+}}(\sin (2x))^x
  • limx0+(cos(x))x\lim _{x \rightarrow 0^{+}}(\cos (x))^x
  • limx0+(tan(x))x\lim _{x \rightarrow 0^{+}}(\tan (x))^x

These examples can be evaluated using similar techniques as the one presented in this article.

Q: What are some common mistakes to avoid when evaluating limits?

A: Some common mistakes to avoid when evaluating limits include:

  • Not checking if the expression is in the form limxaf(x)g(x)\lim _{x \rightarrow a} \frac{f(x)}{g(x)}, where f(x)f(x) and g(x)g(x) are both differentiable at x=ax = a.
  • Not using L'Hospital's Rule when necessary.
  • Not checking if the limit is in the form limxaef(x)\lim _{x \rightarrow a} e^{f(x)}, where f(x)f(x) is a differentiable function.

Q: How can we apply the concepts learned in this article to real-world problems?

A: The concepts learned in this article can be applied to real-world problems in various fields, such as:

  • Physics: To evaluate the limit of an expression that represents the behavior of a physical system as a parameter approaches a certain value.
  • Engineering: To evaluate the limit of an expression that represents the behavior of a mechanical system as a parameter approaches a certain value.
  • Economics: To evaluate the limit of an expression that represents the behavior of an economic system as a parameter approaches a certain value.

By applying the concepts learned in this article, we can gain a deeper understanding of the behavior of complex systems and make more informed decisions.

Q: What are some additional resources that can help us learn more about limits and L'Hospital's Rule?

A: Some additional resources that can help us learn more about limits and L'Hospital's Rule include:

  • Textbooks on calculus, such as Spivak's Calculus on Manifolds and Rudin's Principles of Mathematical Analysis.
  • Online resources, such as Khan Academy's Calculus course and MIT OpenCourseWare's Calculus course.
  • Research papers on limits and L'Hospital's Rule, such as L'Hospital's original paper Methodus differentialis.

By exploring these resources, we can gain a deeper understanding of the concepts and techniques presented in this article.