Find The Exact Values Of $\sin 2\theta$, $\cos 2\theta$, And $\tan 2\theta$, And Determine The Quadrant In Which $2\theta$ Lies.Given: $\sin \theta = \frac{45}{53}$, With $\theta$ In Quadrant I.

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Introduction

In this article, we will explore the process of finding the exact values of sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta given the value of sinθ\sin \theta. We will also determine the quadrant in which 2θ2\theta lies. This problem is a classic example of using trigonometric identities to find the values of trigonometric functions for a given angle.

Given Information

We are given that sinθ=4553\sin \theta = \frac{45}{53}, and θ\theta lies in quadrant I. This means that θ\theta is an acute angle, and its sine value is positive.

Recall of Trigonometric Identities

To find the values of sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta, we need to recall the following trigonometric identities:

  • sin2θ=2sinθcosθ\sin 2\theta = 2\sin \theta \cos \theta
  • cos2θ=cos2θsin2θ\cos 2\theta = \cos^2 \theta - \sin^2 \theta
  • tan2θ=sin2θcos2θ\tan 2\theta = \frac{\sin 2\theta}{\cos 2\theta}

Finding cosθ\cos \theta

Since we are given the value of sinθ\sin \theta, we can use the Pythagorean identity to find the value of cosθ\cos \theta.

sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1

Substituting the given value of sinθ\sin \theta, we get:

(4553)2+cos2θ=1\left(\frac{45}{53}\right)^2 + \cos^2 \theta = 1

Simplifying the equation, we get:

cos2θ=1(4553)2\cos^2 \theta = 1 - \left(\frac{45}{53}\right)^2

cos2θ=120252809\cos^2 \theta = 1 - \frac{2025}{2809}

cos2θ=7842809\cos^2 \theta = \frac{784}{2809}

Taking the square root of both sides, we get:

cosθ=±7842809\cos \theta = \pm \sqrt{\frac{784}{2809}}

Since θ\theta lies in quadrant I, cosθ\cos \theta is positive.

cosθ=7842809\cos \theta = \sqrt{\frac{784}{2809}}

cosθ=2853\cos \theta = \frac{28}{53}

Finding sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta

Now that we have the values of sinθ\sin \theta and cosθ\cos \theta, we can find the values of sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta using the trigonometric identities mentioned earlier.

sin2θ=2sinθcosθ\sin 2\theta = 2\sin \theta \cos \theta

sin2θ=2(4553)(2853)\sin 2\theta = 2 \left(\frac{45}{53}\right) \left(\frac{28}{53}\right)

sin2θ=12602809\sin 2\theta = \frac{1260}{2809}

cos2θ=cos2θsin2θ\cos 2\theta = \cos^2 \theta - \sin^2 \theta

cos2θ=(2853)2(4553)2\cos 2\theta = \left(\frac{28}{53}\right)^2 - \left(\frac{45}{53}\right)^2

cos2θ=784280920252809\cos 2\theta = \frac{784}{2809} - \frac{2025}{2809}

cos2θ=12412809\cos 2\theta = -\frac{1241}{2809}

tan2θ=sin2θcos2θ\tan 2\theta = \frac{\sin 2\theta}{\cos 2\theta}

tan2θ=1260280912412809\tan 2\theta = \frac{\frac{1260}{2809}}{-\frac{1241}{2809}}

tan2θ=12601241\tan 2\theta = -\frac{1260}{1241}

Determination of Quadrant

To determine the quadrant in which 2θ2\theta lies, we need to analyze the signs of sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta.

Since sin2θ\sin 2\theta is positive, 2θ2\theta lies in quadrants I or II.

Since cos2θ\cos 2\theta is negative, 2θ2\theta lies in quadrants II or III.

Since tan2θ\tan 2\theta is negative, 2θ2\theta lies in quadrants II or IV.

Combining the above information, we can conclude that 2θ2\theta lies in quadrant II.

Conclusion

Q: What is the process of finding the exact values of sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta?

A: The process of finding the exact values of sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta involves using trigonometric identities and the given value of sinθ\sin \theta. We need to recall the following trigonometric identities:

  • sin2θ=2sinθcosθ\sin 2\theta = 2\sin \theta \cos \theta
  • cos2θ=cos2θsin2θ\cos 2\theta = \cos^2 \theta - \sin^2 \theta
  • tan2θ=sin2θcos2θ\tan 2\theta = \frac{\sin 2\theta}{\cos 2\theta}

We also need to find the value of cosθ\cos \theta using the Pythagorean identity.

Q: How do we find the value of cosθ\cos \theta?

A: We can find the value of cosθ\cos \theta using the Pythagorean identity:

sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1

Substituting the given value of sinθ\sin \theta, we can solve for cosθ\cos \theta.

Q: What if the value of cosθ\cos \theta is negative?

A: If the value of cosθ\cos \theta is negative, it means that θ\theta lies in quadrant II or III. In this case, we need to use the negative value of cosθ\cos \theta to find the values of sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta.

Q: How do we determine the quadrant in which 2θ2\theta lies?

A: To determine the quadrant in which 2θ2\theta lies, we need to analyze the signs of sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta. We can use the following rules:

  • If sin2θ\sin 2\theta is positive, 2θ2\theta lies in quadrants I or II.
  • If cos2θ\cos 2\theta is positive, 2θ2\theta lies in quadrants I or IV.
  • If tan2θ\tan 2\theta is positive, 2θ2\theta lies in quadrants I or III.
  • If tan2θ\tan 2\theta is negative, 2θ2\theta lies in quadrants II or IV.

Q: What if the values of sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta are all negative?

A: If the values of sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta are all negative, it means that 2θ2\theta lies in quadrant III.

Q: Can we use trigonometric identities to find the values of sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta for any given angle?

A: Yes, we can use trigonometric identities to find the values of sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta for any given angle. However, we need to make sure that we have the correct values of sinθ\sin \theta and cosθ\cos \theta.

Q: What are some common trigonometric identities that we can use to find the values of sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta?

A: Some common trigonometric identities that we can use to find the values of sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta include:

  • sin2θ=2sinθcosθ\sin 2\theta = 2\sin \theta \cos \theta
  • cos2θ=cos2θsin2θ\cos 2\theta = \cos^2 \theta - \sin^2 \theta
  • tan2θ=sin2θcos2θ\tan 2\theta = \frac{\sin 2\theta}{\cos 2\theta}
  • sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1

Q: How can we apply trigonometric identities to solve problems involving sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta?

A: We can apply trigonometric identities to solve problems involving sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta by:

  • Using the given values of sinθ\sin \theta and cosθ\cos \theta to find the values of sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta.
  • Applying trigonometric identities to simplify expressions involving sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta.
  • Analyzing the signs of sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta to determine the quadrant in which 2θ2\theta lies.

Conclusion

In this Q&A article, we have discussed the process of finding the exact values of sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta using trigonometric identities. We have also covered common trigonometric identities and how to apply them to solve problems involving sin2θ\sin 2\theta, cos2θ\cos 2\theta, and tan2θ\tan 2\theta.