Find The Exact Value Of The Expression:$\cos \left[\tan ^{-1} \frac{24}{7} - \cos ^{-1} \frac{3}{5}\right\]

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Introduction

In this article, we will delve into the world of trigonometry and explore the concept of inverse trigonometric functions. We will examine the given expression, cos⁑[tanβ‘βˆ’1247βˆ’cosβ‘βˆ’135]\cos \left[\tan ^{-1} \frac{24}{7} - \cos ^{-1} \frac{3}{5}\right], and find its exact value. This involves understanding the properties of inverse trigonometric functions, specifically the tangent and cosine inverse functions.

Understanding Inverse Trigonometric Functions

Inverse trigonometric functions are used to find the angle whose trigonometric function is a given value. For example, the tangent inverse function, denoted as tanβ‘βˆ’1x\tan^{-1}x, gives the angle whose tangent is xx. Similarly, the cosine inverse function, denoted as cosβ‘βˆ’1x\cos^{-1}x, gives the angle whose cosine is xx.

The Tangent Inverse Function

The tangent inverse function, tanβ‘βˆ’1x\tan^{-1}x, is defined as the angle ΞΈ\theta such that tan⁑θ=x\tan\theta = x. This function is also known as the arctangent function. The range of the tangent inverse function is (βˆ’Ο€2,Ο€2)(-\frac{\pi}{2}, \frac{\pi}{2}).

The Cosine Inverse Function

The cosine inverse function, cosβ‘βˆ’1x\cos^{-1}x, is defined as the angle ΞΈ\theta such that cos⁑θ=x\cos\theta = x. This function is also known as the arccosine function. The range of the cosine inverse function is [0,Ο€][0, \pi].

The Given Expression

The given expression is cos⁑[tanβ‘βˆ’1247βˆ’cosβ‘βˆ’135]\cos \left[\tan ^{-1} \frac{24}{7} - \cos ^{-1} \frac{3}{5}\right]. To find the exact value of this expression, we need to evaluate the expression inside the brackets first.

Evaluating the Expression Inside the Brackets

Let's start by evaluating the expression tanβ‘βˆ’1247\tan^{-1} \frac{24}{7}. We can do this by drawing a right triangle with legs 24 and 7, and hypotenuse hh. Using the Pythagorean theorem, we can find the value of hh.

Calculating the Hypotenuse

Using the Pythagorean theorem, we have:

h2=242+72h^2 = 24^2 + 7^2

h2=576+49h^2 = 576 + 49

h2=625h^2 = 625

h=625h = \sqrt{625}

h=25h = 25

Finding the Angle

Now that we have the value of the hypotenuse, we can find the angle ΞΈ\theta using the tangent function:

tan⁑θ=247\tan\theta = \frac{24}{7}

ΞΈ=tanβ‘βˆ’1247\theta = \tan^{-1} \frac{24}{7}

Evaluating the Cosine Inverse Function

Next, let's evaluate the expression cosβ‘βˆ’135\cos^{-1} \frac{3}{5}. We can do this by drawing a right triangle with legs 3 and 4, and hypotenuse 5. Using the Pythagorean theorem, we can verify that this is a valid right triangle.

Verifying the Right Triangle

Using the Pythagorean theorem, we have:

52=32+425^2 = 3^2 + 4^2

25=9+1625 = 9 + 16

25=2525 = 25

This confirms that the triangle is a valid right triangle.

Finding the Angle

Now that we have the value of the hypotenuse, we can find the angle Ο•\phi using the cosine function:

cos⁑ϕ=35\cos\phi = \frac{3}{5}

Ο•=cosβ‘βˆ’135\phi = \cos^{-1} \frac{3}{5}

Evaluating the Expression Inside the Brackets

Now that we have evaluated the expressions tanβ‘βˆ’1247\tan^{-1} \frac{24}{7} and cosβ‘βˆ’135\cos^{-1} \frac{3}{5}, we can substitute these values into the original expression:

cos⁑[tanβ‘βˆ’1247βˆ’cosβ‘βˆ’135]\cos \left[\tan ^{-1} \frac{24}{7} - \cos ^{-1} \frac{3}{5}\right]

cos⁑[ΞΈβˆ’Ο•]\cos \left[\theta - \phi\right]

Using the Cosine Angle Addition Formula

We can use the cosine angle addition formula to simplify the expression:

cos⁑[ΞΈβˆ’Ο•]=cos⁑θcos⁑ϕ+sin⁑θsin⁑ϕ\cos \left[\theta - \phi\right] = \cos\theta\cos\phi + \sin\theta\sin\phi

Substituting the Values

Now that we have the values of ΞΈ\theta and Ο•\phi, we can substitute them into the expression:

cos⁑θcos⁑ϕ+sin⁑θsin⁑ϕ\cos\theta\cos\phi + \sin\theta\sin\phi

(2425)(35)+(725)(45)\left(\frac{24}{25}\right)\left(\frac{3}{5}\right) + \left(\frac{7}{25}\right)\left(\frac{4}{5}\right)

Simplifying the Expression

Now that we have the expression simplified, we can evaluate it:

(2425)(35)+(725)(45)\left(\frac{24}{25}\right)\left(\frac{3}{5}\right) + \left(\frac{7}{25}\right)\left(\frac{4}{5}\right)

72125+28125\frac{72}{125} + \frac{28}{125}

100125\frac{100}{125}

45\frac{4}{5}

Conclusion

In this article, we have found the exact value of the expression cos⁑[tanβ‘βˆ’1247βˆ’cosβ‘βˆ’135]\cos \left[\tan ^{-1} \frac{24}{7} - \cos ^{-1} \frac{3}{5}\right]. We have used the properties of inverse trigonometric functions, specifically the tangent and cosine inverse functions, to evaluate the expression. The final answer is 45\boxed{\frac{4}{5}}.

Final Answer

The final answer is 45\boxed{\frac{4}{5}}.

Introduction

In our previous article, we explored the concept of inverse trigonometric functions and used them to find the exact value of the expression cos⁑[tanβ‘βˆ’1247βˆ’cosβ‘βˆ’135]\cos \left[\tan ^{-1} \frac{24}{7} - \cos ^{-1} \frac{3}{5}\right]. In this article, we will answer some of the most frequently asked questions related to this topic.

Q: What is the tangent inverse function?

A: The tangent inverse function, denoted as tanβ‘βˆ’1x\tan^{-1}x, is defined as the angle ΞΈ\theta such that tan⁑θ=x\tan\theta = x. This function is also known as the arctangent function.

Q: What is the range of the tangent inverse function?

A: The range of the tangent inverse function is (βˆ’Ο€2,Ο€2)(-\frac{\pi}{2}, \frac{\pi}{2}).

Q: What is the cosine inverse function?

A: The cosine inverse function, denoted as cosβ‘βˆ’1x\cos^{-1}x, is defined as the angle ΞΈ\theta such that cos⁑θ=x\cos\theta = x. This function is also known as the arccosine function.

Q: What is the range of the cosine inverse function?

A: The range of the cosine inverse function is [0,Ο€][0, \pi].

Q: How do I evaluate the expression tanβ‘βˆ’1247\tan^{-1} \frac{24}{7}?

A: To evaluate the expression tanβ‘βˆ’1247\tan^{-1} \frac{24}{7}, you can draw a right triangle with legs 24 and 7, and hypotenuse hh. Using the Pythagorean theorem, you can find the value of hh.

Q: How do I find the angle ΞΈ\theta using the tangent function?

A: To find the angle θ\theta using the tangent function, you can use the formula tan⁑θ=247\tan\theta = \frac{24}{7}.

Q: How do I evaluate the expression cosβ‘βˆ’135\cos^{-1} \frac{3}{5}?

A: To evaluate the expression cosβ‘βˆ’135\cos^{-1} \frac{3}{5}, you can draw a right triangle with legs 3 and 4, and hypotenuse 5. Using the Pythagorean theorem, you can verify that this is a valid right triangle.

Q: How do I find the angle Ο•\phi using the cosine function?

A: To find the angle Ο•\phi using the cosine function, you can use the formula cos⁑ϕ=35\cos\phi = \frac{3}{5}.

Q: How do I use the cosine angle addition formula to simplify the expression?

A: To use the cosine angle addition formula to simplify the expression, you can use the formula cos⁑[ΞΈβˆ’Ο•]=cos⁑θcos⁑ϕ+sin⁑θsin⁑ϕ\cos \left[\theta - \phi\right] = \cos\theta\cos\phi + \sin\theta\sin\phi.

Q: What is the final answer to the expression cos⁑[tanβ‘βˆ’1247βˆ’cosβ‘βˆ’135]\cos \left[\tan ^{-1} \frac{24}{7} - \cos ^{-1} \frac{3}{5}\right]?

A: The final answer to the expression cos⁑[tanβ‘βˆ’1247βˆ’cosβ‘βˆ’135]\cos \left[\tan ^{-1} \frac{24}{7} - \cos ^{-1} \frac{3}{5}\right] is 45\boxed{\frac{4}{5}}.

Conclusion

In this article, we have answered some of the most frequently asked questions related to finding the exact value of the expression cos⁑[tanβ‘βˆ’1247βˆ’cosβ‘βˆ’135]\cos \left[\tan ^{-1} \frac{24}{7} - \cos ^{-1} \frac{3}{5}\right]. We hope that this article has been helpful in clarifying any confusion and providing a better understanding of the topic.

Final Answer

The final answer is 45\boxed{\frac{4}{5}}.