Find The Equation Of The Parabola That Has Zeros Of X = − 2 X = -2 X = − 2 And X = 3 X = 3 X = 3 And A Y Y Y -intercept Of ( 0 , − 30 (0, -30 ( 0 , − 30 ].A) Y = 5 X 2 − 5 X − 30 Y = 5x^2 - 5x - 30 Y = 5 X 2 − 5 X − 30 B) Y = − 5 X 2 + 5 X + 30 Y = -5x^2 + 5x + 30 Y = − 5 X 2 + 5 X + 30 C) Y = 5 X 2 + 5 X − 30 Y = 5x^2 + 5x - 30 Y = 5 X 2 + 5 X − 30 D) $y =

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Understanding the Basics of a Parabola

A parabola is a type of quadratic equation that can be represented in the form of y=ax2+bx+cy = ax^2 + bx + c. The zeros of a parabola are the points where the graph intersects the x-axis, and the y-intercept is the point where the graph intersects the y-axis. In this article, we will focus on finding the equation of a parabola that has zeros of x=2x = -2 and x=3x = 3 and a yy-intercept of (0,30)(0, -30).

The Importance of Zeros and Y-Intercept in a Parabola

The zeros of a parabola are crucial in determining its equation. Since we are given the zeros of the parabola as x=2x = -2 and x=3x = 3, we can use this information to find the equation of the parabola. Additionally, the y-intercept of the parabola is also given as (0,30)(0, -30), which will help us determine the value of cc in the equation y=ax2+bx+cy = ax^2 + bx + c.

Using the Zeros to Find the Equation of the Parabola

Since the zeros of the parabola are x=2x = -2 and x=3x = 3, we can write the equation of the parabola in factored form as y=a(x+2)(x3)y = a(x + 2)(x - 3). To find the value of aa, we can use the y-intercept of the parabola, which is (0,30)(0, -30). Substituting x=0x = 0 and y=30y = -30 into the equation, we get:

30=a(0+2)(03)-30 = a(0 + 2)(0 - 3)

Simplifying the equation, we get:

30=a(2)(3)-30 = a(2)(-3)

30=6a-30 = -6a

Dividing both sides by 6-6, we get:

a=5a = 5

Finding the Equation of the Parabola

Now that we have found the value of aa, we can substitute it into the equation y=a(x+2)(x3)y = a(x + 2)(x - 3) to get the equation of the parabola:

y=5(x+2)(x3)y = 5(x + 2)(x - 3)

Expanding the equation, we get:

y=5(x2x6)y = 5(x^2 - x - 6)

y=5x25x30y = 5x^2 - 5x - 30

Conclusion

In this article, we have found the equation of a parabola that has zeros of x=2x = -2 and x=3x = 3 and a yy-intercept of (0,30)(0, -30). The equation of the parabola is y=5x25x30y = 5x^2 - 5x - 30. This equation can be used to graph the parabola and find its x-intercepts, y-intercept, and other important features.

Answer

The correct answer is A) y=5x25x30y = 5x^2 - 5x - 30.

Discussion

This problem requires the use of algebraic techniques to find the equation of a parabola. The zeros of the parabola are used to determine the equation in factored form, and the y-intercept is used to find the value of aa. The equation of the parabola is then found by expanding the factored form. This problem is a good example of how algebraic techniques can be used to solve problems in mathematics.

Related Topics

  • Quadratic Equations: Quadratic equations are a type of polynomial equation that can be represented in the form of ax2+bx+c=0ax^2 + bx + c = 0. The zeros of a quadratic equation are the points where the graph intersects the x-axis.
  • Graphing Quadratic Equations: Quadratic equations can be graphed using various techniques, including factoring, the quadratic formula, and graphing calculators.
  • Solving Systems of Equations: Systems of equations are a set of two or more equations that are solved simultaneously. Quadratic equations can be used to solve systems of equations.

Practice Problems

  • Find the equation of a parabola that has zeros of x=1x = -1 and x=4x = 4 and a yy-intercept of (0,20)(0, -20).
  • Find the equation of a parabola that has zeros of x=3x = -3 and x=2x = 2 and a yy-intercept of (0,15)(0, -15).
  • Find the equation of a parabola that has zeros of x=5x = -5 and x=1x = 1 and a yy-intercept of (0,25)(0, -25).

Conclusion

In this article, we have found the equation of a parabola that has zeros of x=2x = -2 and x=3x = 3 and a yy-intercept of (0,30)(0, -30). The equation of the parabola is y=5x25x30y = 5x^2 - 5x - 30. This equation can be used to graph the parabola and find its x-intercepts, y-intercept, and other important features.

Q: What is a parabola?

A: A parabola is a type of quadratic equation that can be represented in the form of y=ax2+bx+cy = ax^2 + bx + c. The zeros of a parabola are the points where the graph intersects the x-axis, and the y-intercept is the point where the graph intersects the y-axis.

Q: How do I find the equation of a parabola with given zeros and y-intercept?

A: To find the equation of a parabola with given zeros and y-intercept, you can use the following steps:

  1. Write the equation of the parabola in factored form as y=a(xr1)(xr2)y = a(x - r_1)(x - r_2), where r1r_1 and r2r_2 are the zeros of the parabola.
  2. Use the y-intercept to find the value of aa.
  3. Expand the factored form to get the equation of the parabola in standard form.

Q: What is the importance of zeros and y-intercept in a parabola?

A: The zeros of a parabola are crucial in determining its equation. The y-intercept is also important as it helps to find the value of aa in the equation y=ax2+bx+cy = ax^2 + bx + c.

Q: How do I find the value of aa in the equation y=ax2+bx+cy = ax^2 + bx + c?

A: To find the value of aa in the equation y=ax2+bx+cy = ax^2 + bx + c, you can use the y-intercept of the parabola. Substitute x=0x = 0 and y=cy = c into the equation, and solve for aa.

Q: What is the equation of a parabola with zeros of x=2x = -2 and x=3x = 3 and a yy-intercept of (0,30)(0, -30)?

A: The equation of a parabola with zeros of x=2x = -2 and x=3x = 3 and a yy-intercept of (0,30)(0, -30) is y=5x25x30y = 5x^2 - 5x - 30.

Q: How do I graph a parabola?

A: To graph a parabola, you can use various techniques, including factoring, the quadratic formula, and graphing calculators. You can also use the equation of the parabola to find its x-intercepts, y-intercept, and other important features.

Q: What are some related topics to finding the equation of a parabola?

A: Some related topics to finding the equation of a parabola include:

  • Quadratic Equations: Quadratic equations are a type of polynomial equation that can be represented in the form of ax2+bx+c=0ax^2 + bx + c = 0. The zeros of a quadratic equation are the points where the graph intersects the x-axis.
  • Graphing Quadratic Equations: Quadratic equations can be graphed using various techniques, including factoring, the quadratic formula, and graphing calculators.
  • Solving Systems of Equations: Systems of equations are a set of two or more equations that are solved simultaneously. Quadratic equations can be used to solve systems of equations.

Q: What are some practice problems related to finding the equation of a parabola?

A: Some practice problems related to finding the equation of a parabola include:

  • Find the equation of a parabola that has zeros of x=1x = -1 and x=4x = 4 and a yy-intercept of (0,20)(0, -20).
  • Find the equation of a parabola that has zeros of x=3x = -3 and x=2x = 2 and a yy-intercept of (0,15)(0, -15).
  • Find the equation of a parabola that has zeros of x=5x = -5 and x=1x = 1 and a yy-intercept of (0,25)(0, -25).

Conclusion

In this article, we have answered some frequently asked questions about finding the equation of a parabola. We have discussed the importance of zeros and y-intercept in a parabola, how to find the value of aa in the equation y=ax2+bx+cy = ax^2 + bx + c, and how to graph a parabola. We have also provided some related topics and practice problems to help you learn more about finding the equation of a parabola.