Find The Equation For The Parabola That Has Its Focus At \left(-\frac{53}{4}, -9\right ] And Has A Directrix At X = 37 4 X = \frac{37}{4} X = 4 37 ​ . Equation: □ \square □

by ADMIN 173 views

Introduction

In mathematics, a parabola is a type of quadratic curve that has a specific focus and directrix. The focus is a fixed point that is equidistant from the directrix and the curve, while the directrix is a fixed line that the curve approaches but never touches. In this article, we will explore how to find the equation of a parabola given its focus and directrix.

Understanding the Focus and Directrix

The focus of a parabola is a point that is equidistant from the directrix and the curve. This means that if we draw a line from the focus to the curve, it will be perpendicular to the directrix. The directrix is a fixed line that the curve approaches but never touches. In this case, the focus is located at (534,9)\left(-\frac{53}{4}, -9\right), and the directrix is located at x=374x = \frac{37}{4}.

The Standard Equation of a Parabola

The standard equation of a parabola is given by:

y=14p(xh)2+ky = \frac{1}{4p}(x - h)^2 + k

where (h,k)(h, k) is the vertex of the parabola, and pp is the distance from the vertex to the focus.

Finding the Equation of the Parabola

To find the equation of the parabola, we need to determine the values of hh, kk, and pp. Since the focus is located at (534,9)\left(-\frac{53}{4}, -9\right), we know that the vertex is located at the midpoint of the focus and the directrix. The midpoint of the focus and the directrix is given by:

(534+3742,9)=(84,9)=(2,9)\left(\frac{-\frac{53}{4} + \frac{37}{4}}{2}, -9\right) = \left(-\frac{8}{4}, -9\right) = (-2, -9)

Therefore, the vertex of the parabola is located at (2,9)(-2, -9).

Determining the Value of pp

The value of pp is the distance from the vertex to the focus. Since the vertex is located at (2,9)(-2, -9) and the focus is located at (534,9)\left(-\frac{53}{4}, -9\right), we can calculate the distance between the two points using the distance formula:

p=(534+2)2+(0)2=(454)2=454p = \sqrt{\left(-\frac{53}{4} + 2\right)^2 + (0)^2} = \sqrt{\left(-\frac{45}{4}\right)^2} = \frac{45}{4}

Writing the Equation of the Parabola

Now that we have determined the values of hh, kk, and pp, we can write the equation of the parabola using the standard equation:

y=14p(xh)2+ky = \frac{1}{4p}(x - h)^2 + k

Substituting the values of hh, kk, and pp, we get:

y=14(454)(x+2)29y = \frac{1}{4\left(\frac{45}{4}\right)}(x + 2)^2 - 9

Simplifying the equation, we get:

y=145(x+2)29y = \frac{1}{45}(x + 2)^2 - 9

Conclusion

In this article, we have explored how to find the equation of a parabola given its focus and directrix. We have determined the values of hh, kk, and pp using the given information, and have written the equation of the parabola using the standard equation. The equation of the parabola is given by:

y=145(x+2)29y = \frac{1}{45}(x + 2)^2 - 9

This equation represents the parabola with a focus at (534,9)\left(-\frac{53}{4}, -9\right) and a directrix at x=374x = \frac{37}{4}.

References

Discussion

  • What is the vertex of the parabola?
  • How do you determine the value of pp?
  • What is the standard equation of a parabola?
  • How do you write the equation of a parabola given its focus and directrix?

Related Topics

Tags

  • Parabola
  • Focus
  • Directrix
  • Vertex
  • Equation
  • Mathematics