Find All Angles, $0^{\circ} \leq \theta \ \textless \ 360^{\circ}$, That Solve The Following Equation:$\tan \theta = -\frac{\sqrt{3}}{3}$

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Introduction

In trigonometry, the tangent function is a fundamental concept used to relate the angles of a right-angled triangle to the ratios of the lengths of its sides. The tangent function is defined as the ratio of the length of the side opposite the angle to the length of the side adjacent to the angle. In this article, we will explore the angles that satisfy the equation tan⁑θ=βˆ’33\tan \theta = -\frac{\sqrt{3}}{3}, where 0βˆ˜β‰€ΞΈΒ \textlessΒ 360∘0^{\circ} \leq \theta \ \textless \ 360^{\circ}.

Understanding the Tangent Function

The tangent function is a periodic function, meaning that it repeats its values at regular intervals. The period of the tangent function is 180∘180^{\circ}, which means that the function repeats its values every 180∘180^{\circ}. This is because the tangent function is defined as the ratio of the sine and cosine functions, which are periodic with a period of 360∘360^{\circ}.

Solving the Equation

To solve the equation tan⁑θ=βˆ’33\tan \theta = -\frac{\sqrt{3}}{3}, we need to find the angles that satisfy this equation. We can start by using the inverse tangent function, denoted as tanβ‘βˆ’1\tan^{-1}, to find the angle that satisfies the equation. However, we need to be careful when using the inverse tangent function, as it is only defined for angles in the range (βˆ’90∘,90∘)(-90^{\circ}, 90^{\circ}).

Using the Inverse Tangent Function

Using the inverse tangent function, we can find the angle that satisfies the equation tan⁑θ=βˆ’33\tan \theta = -\frac{\sqrt{3}}{3}. We have:

ΞΈ=tanβ‘βˆ’1(βˆ’33)\theta = \tan^{-1} \left( -\frac{\sqrt{3}}{3} \right)

However, we need to be careful when using the inverse tangent function, as it is only defined for angles in the range (βˆ’90∘,90∘)(-90^{\circ}, 90^{\circ}). To find the angles that satisfy the equation, we need to use the properties of the tangent function.

Properties of the Tangent Function

The tangent function has several important properties that we can use to find the angles that satisfy the equation. One of the most important properties is that the tangent function is an odd function, meaning that tan⁑(βˆ’ΞΈ)=βˆ’tan⁑θ\tan (-\theta) = -\tan \theta. This means that if ΞΈ\theta is an angle that satisfies the equation, then βˆ’ΞΈ-\theta is also an angle that satisfies the equation.

Finding the Angles

Using the properties of the tangent function, we can find the angles that satisfy the equation tan⁑θ=βˆ’33\tan \theta = -\frac{\sqrt{3}}{3}. We have:

tan⁑θ=βˆ’33\tan \theta = -\frac{\sqrt{3}}{3}

Using the property that the tangent function is an odd function, we can write:

tan⁑(βˆ’ΞΈ)=βˆ’tan⁑θ=33\tan (-\theta) = -\tan \theta = \frac{\sqrt{3}}{3}

This means that βˆ’ΞΈ-\theta is an angle that satisfies the equation tan⁑θ=33\tan \theta = \frac{\sqrt{3}}{3}. We know that the angle that satisfies this equation is 60∘60^{\circ}, so we have:

βˆ’ΞΈ=60∘-\theta = 60^{\circ}

Solving for ΞΈ\theta, we get:

ΞΈ=βˆ’60∘\theta = -60^{\circ}

However, we need to find the angles that satisfy the equation in the range 0βˆ˜β‰€ΞΈΒ \textlessΒ 360∘0^{\circ} \leq \theta \ \textless \ 360^{\circ}. To do this, we can add 180∘180^{\circ} to the angle, which gives us:

ΞΈ=βˆ’60∘+180∘=120∘\theta = -60^{\circ} + 180^{\circ} = 120^{\circ}

This means that the angle that satisfies the equation is 120∘120^{\circ}.

Finding the Second Angle

We have found one angle that satisfies the equation, but we need to find the second angle. To do this, we can use the property that the tangent function is periodic with a period of 180∘180^{\circ}. This means that if θ\theta is an angle that satisfies the equation, then θ+180∘\theta + 180^{\circ} is also an angle that satisfies the equation.

Using the Periodic Property

Using the periodic property, we can write:

tan⁑(ΞΈ+180∘)=tan⁑θ=βˆ’33\tan (\theta + 180^{\circ}) = \tan \theta = -\frac{\sqrt{3}}{3}

This means that θ+180∘\theta + 180^{\circ} is an angle that satisfies the equation. We know that the angle that satisfies this equation is 120∘120^{\circ}, so we have:

θ+180∘=120∘\theta + 180^{\circ} = 120^{\circ}

Solving for ΞΈ\theta, we get:

ΞΈ=βˆ’60∘\theta = -60^{\circ}

However, we need to find the second angle that satisfies the equation in the range 0βˆ˜β‰€ΞΈΒ \textlessΒ 360∘0^{\circ} \leq \theta \ \textless \ 360^{\circ}. To do this, we can add 360∘360^{\circ} to the angle, which gives us:

ΞΈ=βˆ’60∘+360∘=300∘\theta = -60^{\circ} + 360^{\circ} = 300^{\circ}

This means that the second angle that satisfies the equation is 300∘300^{\circ}.

Conclusion

In this article, we have found the angles that satisfy the equation tan⁑θ=βˆ’33\tan \theta = -\frac{\sqrt{3}}{3}, where 0βˆ˜β‰€ΞΈΒ \textlessΒ 360∘0^{\circ} \leq \theta \ \textless \ 360^{\circ}. We have used the properties of the tangent function, including the fact that it is an odd function and periodic with a period of 180∘180^{\circ}. We have found two angles that satisfy the equation, which are 120∘120^{\circ} and 300∘300^{\circ}.

Final Answer

The final answer is 120∘,300∘\boxed{120^{\circ}, 300^{\circ}}.

Introduction

In our previous article, we explored the angles that satisfy the equation tan⁑θ=βˆ’33\tan \theta = -\frac{\sqrt{3}}{3}, where 0βˆ˜β‰€ΞΈΒ \textlessΒ 360∘0^{\circ} \leq \theta \ \textless \ 360^{\circ}. In this article, we will answer some of the most frequently asked questions related to this topic.

Q: What is the tangent function?

A: The tangent function is a fundamental concept in trigonometry that relates the angles of a right-angled triangle to the ratios of the lengths of its sides. It is defined as the ratio of the length of the side opposite the angle to the length of the side adjacent to the angle.

Q: What is the period of the tangent function?

A: The period of the tangent function is 180∘180^{\circ}, meaning that the function repeats its values every 180∘180^{\circ}.

Q: How do I find the angles that satisfy the equation tan⁑θ=βˆ’33\tan \theta = -\frac{\sqrt{3}}{3}?

A: To find the angles that satisfy the equation, you can use the properties of the tangent function, including the fact that it is an odd function and periodic with a period of 180∘180^{\circ}. You can also use the inverse tangent function, denoted as tanβ‘βˆ’1\tan^{-1}, to find the angle that satisfies the equation.

Q: What are the two angles that satisfy the equation tan⁑θ=βˆ’33\tan \theta = -\frac{\sqrt{3}}{3}?

A: The two angles that satisfy the equation are 120∘120^{\circ} and 300∘300^{\circ}.

Q: Why do we need to add 180∘180^{\circ} to the angle to find the second angle?

A: We need to add 180∘180^{\circ} to the angle to find the second angle because the tangent function is periodic with a period of 180∘180^{\circ}. This means that if θ\theta is an angle that satisfies the equation, then θ+180∘\theta + 180^{\circ} is also an angle that satisfies the equation.

Q: Can I use the inverse tangent function to find the angles that satisfy the equation?

A: Yes, you can use the inverse tangent function to find the angles that satisfy the equation. However, you need to be careful when using the inverse tangent function, as it is only defined for angles in the range (βˆ’90∘,90∘)(-90^{\circ}, 90^{\circ}).

Q: What is the significance of the angle 60∘60^{\circ} in this problem?

A: The angle 60∘60^{\circ} is significant in this problem because it is the angle that satisfies the equation tan⁑θ=33\tan \theta = \frac{\sqrt{3}}{3}. We can use this angle to find the second angle that satisfies the equation by adding 180∘180^{\circ} to it.

Q: Can I use the tangent function to find the angles that satisfy the equation in other ranges?

A: Yes, you can use the tangent function to find the angles that satisfy the equation in other ranges. However, you need to be careful when using the tangent function, as it is periodic with a period of 180∘180^{\circ}.

Conclusion

In this article, we have answered some of the most frequently asked questions related to the angles that satisfy the equation tan⁑θ=βˆ’33\tan \theta = -\frac{\sqrt{3}}{3}. We hope that this article has been helpful in clarifying any doubts that you may have had.

Final Answer

The final answer is 120∘,300∘\boxed{120^{\circ}, 300^{\circ}}.