Factor Completely $16x^8 - 1$.A. $ (4x^4 - 1)(4x^4 + 1) $ B. $ (2x^2 - 1)(2x^2 + 1)(4x^4 + 1) $ C. $ (2x^2 - 1)(2x^2 + 1)(2x^2 + 1)(2x^2 + 1) $ D. $ (2x^2 - 1)(2x^2 + 1)(4x^4 - 1) $

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Introduction

Factoring algebraic expressions is a fundamental concept in mathematics, and it plays a crucial role in solving equations and inequalities. In this article, we will focus on factoring the expression $16x^8 - 1$ completely. We will explore the different methods and techniques used to factor this expression and provide a step-by-step guide to help you understand the process.

What is Factoring?

Factoring is the process of expressing an algebraic expression as a product of simpler expressions, called factors. Factoring involves finding the common factors of the terms in an expression and expressing it as a product of these factors. Factoring is an essential skill in mathematics, and it is used to solve equations, inequalities, and systems of equations.

The Expression to be Factored

The expression we will be factoring is $16x^8 - 1$. This expression can be factored using the difference of squares formula, which states that $a^2 - b^2 = (a + b)(a - b)$. We will use this formula to factor the expression.

Step 1: Factor the Expression Using the Difference of Squares Formula

To factor the expression $16x^8 - 1$, we can use the difference of squares formula. We can rewrite the expression as $(4x4)2 - 1^2$, which is in the form of $a^2 - b^2$. Using the difference of squares formula, we can factor the expression as follows:

(4x4)2−12=(4x4+1)(4x4−1)(4x^4)^2 - 1^2 = (4x^4 + 1)(4x^4 - 1)

Step 2: Factor the Expression Further

We can factor the expression $(4x^4 - 1)$ further using the difference of squares formula. We can rewrite the expression as $(2x2)2 - 1^2$, which is in the form of $a^2 - b^2$. Using the difference of squares formula, we can factor the expression as follows:

(2x2)2−12=(2x2+1)(2x2−1)(2x^2)^2 - 1^2 = (2x^2 + 1)(2x^2 - 1)

Step 3: Combine the Factors

We can now combine the factors we have obtained so far to factor the expression $16x^8 - 1$ completely. We have factored the expression as follows:

(4x4+1)(4x4−1)=(4x4+1)(2x2+1)(2x2−1)(4x^4 + 1)(4x^4 - 1) = (4x^4 + 1)(2x^2 + 1)(2x^2 - 1)

Conclusion

In this article, we have factored the expression $16x^8 - 1$ completely using the difference of squares formula. We have obtained the final factorization as $(4x^4 + 1)(2x^2 + 1)(2x^2 - 1)$. This factorization is the correct answer to the problem.

Comparison of Options

Let's compare the options provided to see which one matches our final factorization.

  • Option A: $(4x^4 - 1)(4x^4 + 1)$
  • Option B: $(2x^2 - 1)(2x^2 + 1)(4x^4 + 1)$
  • Option C: $(2x^2 - 1)(2x^2 + 1)(2x^2 + 1)(2x^2 + 1)$
  • Option D: $(2x^2 - 1)(2x^2 + 1)(4x^4 - 1)$

Our final factorization matches option D, which is $(2x^2 - 1)(2x^2 + 1)(4x^4 - 1)$. Therefore, the correct answer is option D.

Final Answer

Introduction

In our previous article, we explored the concept of factoring algebraic expressions and applied it to the expression $16x^8 - 1$. We obtained the final factorization as $(4x^4 + 1)(2x^2 + 1)(2x^2 - 1)$. However, we also compared the options provided and found that the correct answer is option D: $(2x^2 - 1)(2x^2 + 1)(4x^4 - 1)$. In this article, we will answer some frequently asked questions related to factoring algebraic expressions.

Q: What is factoring?

A: Factoring is the process of expressing an algebraic expression as a product of simpler expressions, called factors. Factoring involves finding the common factors of the terms in an expression and expressing it as a product of these factors.

Q: What are the different methods of factoring?

A: There are several methods of factoring, including:

  • Difference of squares: This method is used to factor expressions of the form $a^2 - b^2$.
  • Sum of squares: This method is used to factor expressions of the form $a^2 + b^2$.
  • Grouping: This method is used to factor expressions by grouping terms together.
  • Factoring out the greatest common factor: This method is used to factor out the greatest common factor from a group of terms.

Q: How do I factor an expression using the difference of squares formula?

A: To factor an expression using the difference of squares formula, you need to identify the expression as a difference of squares. The difference of squares formula is $a^2 - b^2 = (a + b)(a - b)$. You can then apply this formula to factor the expression.

Q: What is the difference of squares formula?

A: The difference of squares formula is $a^2 - b^2 = (a + b)(a - b)$. This formula is used to factor expressions of the form $a^2 - b^2$.

Q: How do I factor an expression using the sum of squares formula?

A: To factor an expression using the sum of squares formula, you need to identify the expression as a sum of squares. The sum of squares formula is $a^2 + b^2 = (a + bi)(a - bi)$. You can then apply this formula to factor the expression.

Q: What is the sum of squares formula?

A: The sum of squares formula is $a^2 + b^2 = (a + bi)(a - bi)$. This formula is used to factor expressions of the form $a^2 + b^2$.

Q: How do I factor an expression using the grouping method?

A: To factor an expression using the grouping method, you need to group the terms in the expression together. You can then look for common factors within each group and factor them out.

Q: What is the greatest common factor (GCF)?

A: The greatest common factor (GCF) is the largest factor that divides all the terms in a group of terms. You can factor out the GCF from a group of terms to simplify the expression.

Q: How do I factor an expression using the GCF method?

A: To factor an expression using the GCF method, you need to identify the GCF of the terms in the expression. You can then factor out the GCF from each term to simplify the expression.

Conclusion

In this article, we have answered some frequently asked questions related to factoring algebraic expressions. We have covered the different methods of factoring, including the difference of squares, sum of squares, grouping, and greatest common factor methods. We have also provided examples and explanations to help you understand the concepts.