$F: B_2H_6 + 3O_2 \rightarrow 2HBO_2 + 2H_2O$What Mass Of $O_2$ Will Be Needed To Burn 36.1 G Of $B_2H_6$?

Introduction

Chemical equations are a fundamental concept in chemistry, representing the interaction between reactants and products. Balancing chemical equations is crucial to understand the stoichiometry of a reaction, which is essential in various fields such as chemistry, physics, and engineering. In this article, we will explore the concept of balancing chemical equations and stoichiometry, with a focus on the given chemical equation: $B_2H_6 + 3O_2 \rightarrow 2HBO_2 + 2H_2O$. We will also calculate the mass of $O_2$ needed to burn 36.1 g of $B_2H_6$.

Understanding the Chemical Equation

The given chemical equation is:

$B_2H_6 + 3O_2 \rightarrow 2HBO_2 + 2H_2O$

This equation represents the combustion of diborane ($B_2H_6$) with oxygen ($O_2$) to produce boron dioxide ($HBO_2$) and water ($H_2O$). The equation is already balanced, meaning that the number of atoms of each element is the same on both the reactant and product sides.

Balancing Chemical Equations

Balancing chemical equations involves adjusting the coefficients of the reactants and products to ensure that the number of atoms of each element is the same on both sides of the equation. The general steps for balancing chemical equations are:

1. Write the unbalanced equation.
2. Count the number of atoms of each element on both sides of the equation.
3. Adjust the coefficients of the reactants and products to balance the equation.

However, in this case, the equation is already balanced, so we can proceed to the next step.

Stoichiometry

Stoichiometry is the study of the quantitative relationships between reactants and products in a chemical reaction. It involves calculating the amount of one substance required to react with a given amount of another substance. In this case, we want to calculate the mass of $O_2$ needed to burn 36.1 g of $B_2H_6$.

Calculating the Mass of $O_2$

To calculate the mass of $O_2$ needed, we need to follow these steps:

1. Calculate the number of moles of $B_2H_6$:
   • The molar mass of $B_2H_6$ is 27.61 g/mol.
   • The mass of $B_2H_6$ is 36.1 g.
   • The number of moles of $B_2H_6$ is calculated using the formula: moles = mass / molar mass.
   • moles = 36.1 g / 27.61 g/mol = 1.31 mol
2. Calculate the number of moles of $O_2$ required:
   • The balanced equation shows that 3 moles of $O_2$ are required to react with 1 mole of $B_2H_6$.
   • The number of moles of $O_2$ required is calculated by multiplying the number of moles of $B_2H_6$ by 3.
   • moles = 1.31 mol x 3 = 3.93 mol
3. Calculate the mass of $O_2$ required:
   • The molar mass of $O_2$ is 32 g/mol.
   • The mass of $O_2$ required is calculated using the formula: mass = moles x molar mass.
   • mass = 3.93 mol x 32 g/mol = 125.76 g

Therefore, the mass of $O_2$ needed to burn 36.1 g of $B_2H_6$ is 125.76 g.

Conclusion

In conclusion, balancing chemical equations and stoichiometry are essential concepts in chemistry. By understanding the chemical equation and balancing it, we can calculate the mass of $O_2$ needed to burn 36.1 g of $B_2H_6$. The calculated mass of $O_2$ is 125.76 g, which is a crucial value in various fields such as chemistry, physics, and engineering.

References

• Petrucci, R. H., Harwood, W. S., Herring, F. G., & Madura, J. D. (2007). General chemistry: Principles and modern applications. Pearson Prentice Hall.
• Atkins, P. W., & De Paula, J. (2010). Physical chemistry. Oxford University Press.

Further Reading

• Stoichiometry: A Comprehensive Guide
• Balancing Chemical Equations: A Step-by-Step Guide
• Chemical Equations: A Review of the Basics
  Frequently Asked Questions: Balancing Chemical Equations and Stoichiometry ====================================================================

Q: What is the purpose of balancing chemical equations?

A: The purpose of balancing chemical equations is to ensure that the number of atoms of each element is the same on both the reactant and product sides. This is crucial in understanding the stoichiometry of a reaction, which is essential in various fields such as chemistry, physics, and engineering.

Q: How do I balance a chemical equation?

A: To balance a chemical equation, follow these steps:

1. Write the unbalanced equation.
2. Count the number of atoms of each element on both sides of the equation.
3. Adjust the coefficients of the reactants and products to balance the equation.

Q: What is stoichiometry?

A: Stoichiometry is the study of the quantitative relationships between reactants and products in a chemical reaction. It involves calculating the amount of one substance required to react with a given amount of another substance.

Q: How do I calculate the mass of a substance required to react with a given amount of another substance?

A: To calculate the mass of a substance required, follow these steps:

1. Calculate the number of moles of the given substance.
2. Calculate the number of moles of the required substance using the balanced equation.
3. Calculate the mass of the required substance using the molar mass.

Q: What is the difference between a balanced equation and an unbalanced equation?

A: A balanced equation has the same number of atoms of each element on both the reactant and product sides, while an unbalanced equation does not have the same number of atoms of each element on both sides.

Q: How do I determine the limiting reactant in a chemical reaction?

A: To determine the limiting reactant, calculate the number of moles of each reactant and compare it to the number of moles required to react with the given amount of another substance. The reactant with the smaller number of moles is the limiting reactant.

Q: What is the mole ratio of reactants and products in a chemical reaction?

A: The mole ratio of reactants and products in a chemical reaction is the ratio of the number of moles of each reactant to the number of moles of each product.

Q: How do I calculate the yield of a chemical reaction?

A: To calculate the yield of a chemical reaction, calculate the number of moles of the product formed and compare it to the number of moles required to react with the given amount of another substance. The yield is the ratio of the number of moles of the product formed to the number of moles required.

Q: What is the difference between a chemical equation and a chemical reaction?

A: A chemical equation is a representation of a chemical reaction, while a chemical reaction is the actual process of reactants converting to products.

Q: How do I determine the type of chemical reaction (synthesis, decomposition, single displacement, double displacement, combustion)?

A: To determine the type of chemical reaction, examine the reactants and products and determine the type of reaction that occurred.

Q: What is the importance of balancing chemical equations and stoichiometry in chemistry?

A: Balancing chemical equations and stoichiometry are essential in understanding the quantitative relationships between reactants and products in a chemical reaction. This is crucial in various fields such as chemistry, physics, and engineering.

Q: How do I apply balancing chemical equations and stoichiometry in real-life situations?

A: Balancing chemical equations and stoichiometry are applied in various real-life situations such as:

• Calculating the amount of reactants required for a chemical reaction
• Determining the yield of a chemical reaction
• Understanding the quantitative relationships between reactants and products in a chemical reaction
• Designing chemical processes and equipment

Conclusion

In conclusion, balancing chemical equations and stoichiometry are essential concepts in chemistry. By understanding the chemical equation and balancing it, we can calculate the mass of a substance required to react with a given amount of another substance. The calculated mass of a substance is a crucial value in various fields such as chemistry, physics, and engineering.