ExercisesSolve Each Equation By Completing The Square. Round To The Nearest Tenth If Necessary.1. $x^2 - 4x + 3 = 0$2. $x^2 + 10x = -9$3. $x^2 - 8x - 9 = 0$4. $x^2 - 6x = 16$5. $x^2 - 4x - 5 = 0$6. $x^2

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What is Completing the Square?

Completing the square is a method used to solve quadratic equations of the form ax2+bx+c=0ax^2 + bx + c = 0. This method involves manipulating the equation to express it in the form (x+d)2=e(x + d)^2 = e, where dd and ee are constants. By doing so, we can easily find the solutions to the equation.

Step-by-Step Guide to Completing the Square

To complete the square, follow these steps:

  1. Write the equation in the form ax2+bx+c=0ax^2 + bx + c = 0: Make sure the equation is in the standard form of a quadratic equation.
  2. Move the constant term to the right-hand side: Subtract cc from both sides of the equation to isolate the quadratic term.
  3. Divide the coefficient of the xx term by 2: Divide bb by 2 to get b2\frac{b}{2}.
  4. Square the result: Square b2\frac{b}{2} to get (b2)2\left(\frac{b}{2}\right)^2.
  5. Add the squared result to both sides: Add (b2)2\left(\frac{b}{2}\right)^2 to both sides of the equation.
  6. Write the left-hand side as a perfect square: The left-hand side of the equation should now be a perfect square, in the form (x+d)2(x + d)^2.

Solving Each Equation by Completing the Square

1. x2βˆ’4x+3=0x^2 - 4x + 3 = 0

To solve this equation, we will follow the steps outlined above.

  • Write the equation in the form ax2+bx+c=0ax^2 + bx + c = 0: The equation is already in the standard form.
  • Move the constant term to the right-hand side: Subtract 3 from both sides of the equation to get x2βˆ’4x=βˆ’3x^2 - 4x = -3.
  • Divide the coefficient of the xx term by 2: Divide -4 by 2 to get -2.
  • Square the result: Square -2 to get 4.
  • Add the squared result to both sides: Add 4 to both sides of the equation to get x2βˆ’4x+4=1x^2 - 4x + 4 = 1.
  • Write the left-hand side as a perfect square: The left-hand side of the equation is now a perfect square, in the form (xβˆ’2)2(x - 2)^2.

The equation can now be written as (xβˆ’2)2=1(x - 2)^2 = 1. To solve for xx, take the square root of both sides of the equation.

xβˆ’2=Β±1x - 2 = \pm \sqrt{1}

Simplifying the equation, we get:

xβˆ’2=Β±1x - 2 = \pm 1

Adding 2 to both sides of the equation, we get:

x=3Β orΒ x=1x = 3 \text{ or } x = 1

2. x2+10x=βˆ’9x^2 + 10x = -9

To solve this equation, we will follow the steps outlined above.

  • Write the equation in the form ax2+bx+c=0ax^2 + bx + c = 0: Add 9 to both sides of the equation to get x2+10x+9=0x^2 + 10x + 9 = 0.
  • Move the constant term to the right-hand side: The equation is already in the standard form.
  • Divide the coefficient of the xx term by 2: Divide 10 by 2 to get 5.
  • Square the result: Square 5 to get 25.
  • Add the squared result to both sides: Add 25 to both sides of the equation to get x2+10x+25=16x^2 + 10x + 25 = 16.
  • Write the left-hand side as a perfect square: The left-hand side of the equation is now a perfect square, in the form (x+5)2(x + 5)^2.

The equation can now be written as (x+5)2=16(x + 5)^2 = 16. To solve for xx, take the square root of both sides of the equation.

x+5=Β±16x + 5 = \pm \sqrt{16}

Simplifying the equation, we get:

x+5=Β±4x + 5 = \pm 4

Subtracting 5 from both sides of the equation, we get:

x=βˆ’1Β orΒ x=βˆ’9x = -1 \text{ or } x = -9

3. x2βˆ’8xβˆ’9=0x^2 - 8x - 9 = 0

To solve this equation, we will follow the steps outlined above.

  • Write the equation in the form ax2+bx+c=0ax^2 + bx + c = 0: The equation is already in the standard form.
  • Move the constant term to the right-hand side: Add 9 to both sides of the equation to get x2βˆ’8x=9x^2 - 8x = 9.
  • Divide the coefficient of the xx term by 2: Divide -8 by 2 to get -4.
  • Square the result: Square -4 to get 16.
  • Add the squared result to both sides: Add 16 to both sides of the equation to get x2βˆ’8x+16=25x^2 - 8x + 16 = 25.
  • Write the left-hand side as a perfect square: The left-hand side of the equation is now a perfect square, in the form (xβˆ’4)2(x - 4)^2.

The equation can now be written as (xβˆ’4)2=25(x - 4)^2 = 25. To solve for xx, take the square root of both sides of the equation.

xβˆ’4=Β±25x - 4 = \pm \sqrt{25}

Simplifying the equation, we get:

xβˆ’4=Β±5x - 4 = \pm 5

Adding 4 to both sides of the equation, we get:

x=9Β orΒ x=βˆ’1x = 9 \text{ or } x = -1

4. x2βˆ’6x=16x^2 - 6x = 16

To solve this equation, we will follow the steps outlined above.

  • Write the equation in the form ax2+bx+c=0ax^2 + bx + c = 0: Add 16 to both sides of the equation to get x2βˆ’6x+16=0x^2 - 6x + 16 = 0.
  • Move the constant term to the right-hand side: The equation is already in the standard form.
  • Divide the coefficient of the xx term by 2: Divide -6 by 2 to get -3.
  • Square the result: Square -3 to get 9.
  • Add the squared result to both sides: Add 9 to both sides of the equation to get x2βˆ’6x+9=25x^2 - 6x + 9 = 25.
  • Write the left-hand side as a perfect square: The left-hand side of the equation is now a perfect square, in the form (xβˆ’3)2(x - 3)^2.

The equation can now be written as (xβˆ’3)2=25(x - 3)^2 = 25. To solve for xx, take the square root of both sides of the equation.

xβˆ’3=Β±25x - 3 = \pm \sqrt{25}

Simplifying the equation, we get:

xβˆ’3=Β±5x - 3 = \pm 5

Adding 3 to both sides of the equation, we get:

x=8Β orΒ x=βˆ’2x = 8 \text{ or } x = -2

5. x2βˆ’4xβˆ’5=0x^2 - 4x - 5 = 0

To solve this equation, we will follow the steps outlined above.

  • Write the equation in the form ax2+bx+c=0ax^2 + bx + c = 0: The equation is already in the standard form.
  • Move the constant term to the right-hand side: Add 5 to both sides of the equation to get x2βˆ’4x=5x^2 - 4x = 5.
  • Divide the coefficient of the xx term by 2: Divide -4 by 2 to get -2.
  • Square the result: Square -2 to get 4.
  • Add the squared result to both sides: Add 4 to both sides of the equation to get x2βˆ’4x+4=9x^2 - 4x + 4 = 9.
  • Write the left-hand side as a perfect square: The left-hand side of the equation is now a perfect square, in the form (xβˆ’2)2(x - 2)^2.

The equation can now be written as (xβˆ’2)2=9(x - 2)^2 = 9. To solve for xx, take the square root of both sides of the equation.

xβˆ’2=Β±9x - 2 = \pm \sqrt{9}

Simplifying the equation, we get:

xβˆ’2=Β±3x - 2 = \pm 3

Adding 2 to both sides of the equation, we get:

x=5Β orΒ x=βˆ’1x = 5 \text{ or } x = -1

6. x2+2x+1=0x^2 + 2x + 1 = 0

To solve this equation, we will follow the steps outlined above.

  • Write the equation in the form ax2+bx+c=0ax^2 + bx + c = 0: The equation is already in the standard form.
  • Move the constant term to the right-hand side: Subtract 1 from both sides of the equation to get x2+2x=βˆ’1x^2 + 2x = -1.
  • **Divide the coefficient
    Frequently Asked Questions (FAQs) about Solving Quadratic Equations by Completing the Square =============================================================================================

Q: What is completing the square?

A: Completing the square is a method used to solve quadratic equations of the form ax2+bx+c=0ax^2 + bx + c = 0. This method involves manipulating the equation to express it in the form (x+d)2=e(x + d)^2 = e, where dd and ee are constants.

Q: How do I know if an equation can be solved by completing the square?

A: An equation can be solved by completing the square if it is in the form ax2+bx+c=0ax^2 + bx + c = 0, where aa, bb, and cc are constants. If the equation is not in this form, you may need to use a different method to solve it.

Q: What are the steps to complete the square?

A: The steps to complete the square are:

  1. Write the equation in the form ax2+bx+c=0ax^2 + bx + c = 0: Make sure the equation is in the standard form of a quadratic equation.
  2. Move the constant term to the right-hand side: Subtract cc from both sides of the equation to isolate the quadratic term.
  3. Divide the coefficient of the xx term by 2: Divide bb by 2 to get b2\frac{b}{2}.
  4. Square the result: Square b2\frac{b}{2} to get (b2)2\left(\frac{b}{2}\right)^2.
  5. Add the squared result to both sides: Add (b2)2\left(\frac{b}{2}\right)^2 to both sides of the equation.
  6. Write the left-hand side as a perfect square: The left-hand side of the equation should now be a perfect square, in the form (x+d)2(x + d)^2.

Q: How do I solve the equation once I have completed the square?

A: Once you have completed the square, you can solve the equation by taking the square root of both sides of the equation. This will give you two possible solutions for xx.

Q: What if the equation has no real solutions?

A: If the equation has no real solutions, it means that the equation has complex solutions. In this case, you can use the quadratic formula to find the complex solutions.

Q: Can I use completing the square to solve all types of quadratic equations?

A: Yes, you can use completing the square to solve all types of quadratic equations, including those with complex solutions.

Q: What are some common mistakes to avoid when completing the square?

A: Some common mistakes to avoid when completing the square include:

  • Not moving the constant term to the right-hand side: Make sure to subtract cc from both sides of the equation to isolate the quadratic term.
  • Not dividing the coefficient of the xx term by 2: Make sure to divide bb by 2 to get b2\frac{b}{2}.
  • Not squaring the result: Make sure to square b2\frac{b}{2} to get (b2)2\left(\frac{b}{2}\right)^2.
  • Not adding the squared result to both sides: Make sure to add (b2)2\left(\frac{b}{2}\right)^2 to both sides of the equation.

Q: How do I know if I have completed the square correctly?

A: You can check if you have completed the square correctly by looking at the left-hand side of the equation. If it is in the form (x+d)2(x + d)^2, then you have completed the square correctly.

Q: What are some real-world applications of completing the square?

A: Completing the square has many real-world applications, including:

  • Physics: Completing the square is used to solve equations of motion and to find the position and velocity of an object.
  • Engineering: Completing the square is used to solve equations of electrical circuits and to find the current and voltage of a circuit.
  • Computer Science: Completing the square is used to solve equations of algorithms and to find the time and space complexity of an algorithm.

Q: Can I use completing the square to solve systems of equations?

A: Yes, you can use completing the square to solve systems of equations. This involves completing the square for each equation in the system and then solving the resulting equations.

Q: What are some tips for mastering completing the square?

A: Some tips for mastering completing the square include:

  • Practice, practice, practice: The more you practice completing the square, the more comfortable you will become with the method.
  • Start with simple equations: Begin with simple equations and gradually move on to more complex ones.
  • Use visual aids: Use visual aids such as graphs and charts to help you understand the concept of completing the square.
  • Check your work: Make sure to check your work carefully to avoid making mistakes.