Evaluate The Limit Using L'Hôpital's Rule If Necessary: Lim ⁡ X → ∞ ( 9 X 9 X + 2 ) 8 X \lim _{x \rightarrow \infty}\left(\frac{9x}{9x+2}\right)^{8x} Lim X → ∞ ​ ( 9 X + 2 9 X ​ ) 8 X

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Introduction


In this article, we will evaluate the limit of the expression (9x9x+2)8x\left(\frac{9x}{9x+2}\right)^{8x} as xx approaches infinity. We will use L'Hôpital's rule if necessary to find the limit.

The Limit Expression


The given limit expression is limx(9x9x+2)8x\lim _{x \rightarrow \infty}\left(\frac{9x}{9x+2}\right)^{8x}. This expression involves a power function and a rational function. To evaluate this limit, we need to simplify the expression and then apply the appropriate limit rules.

Simplifying the Expression


We can simplify the expression by rewriting it as (9x9x+2)8x=(11+29x)8x\left(\frac{9x}{9x+2}\right)^{8x} = \left(\frac{1}{1+\frac{2}{9x}}\right)^{8x}.

Applying L'Hôpital's Rule


To evaluate the limit of the expression (11+29x)8x\left(\frac{1}{1+\frac{2}{9x}}\right)^{8x}, we can apply L'Hôpital's rule. L'Hôpital's rule states that if the limit of a function is of the form 00\frac{0}{0} or \frac{\infty}{\infty}, then we can differentiate the numerator and denominator separately and take the limit of the resulting expression.

Differentiating the Numerator and Denominator


Let's differentiate the numerator and denominator of the expression (11+29x)8x\left(\frac{1}{1+\frac{2}{9x}}\right)^{8x}.

The numerator is 11, so its derivative is 00.

The denominator is 1+29x1+\frac{2}{9x}, so its derivative is 29x2-\frac{2}{9x^2}.

Applying L'Hôpital's Rule


Now that we have differentiated the numerator and denominator, we can apply L'Hôpital's rule. The limit of the expression (11+29x)8x\left(\frac{1}{1+\frac{2}{9x}}\right)^{8x} is equal to the limit of the expression 029x2\frac{0}{-\frac{2}{9x^2}}.

Evaluating the Limit


The limit of the expression 029x2\frac{0}{-\frac{2}{9x^2}} is equal to 00.

Conclusion


In this article, we evaluated the limit of the expression (9x9x+2)8x\left(\frac{9x}{9x+2}\right)^{8x} as xx approaches infinity. We simplified the expression and then applied L'Hôpital's rule to find the limit. The final answer is e29e^{-\frac{2}{9}}.

The Final Answer


The final answer is e29\boxed{e^{-\frac{2}{9}}}.

Step-by-Step Solution


Here are the step-by-step solutions to the problem:

  1. Simplify the expression (9x9x+2)8x\left(\frac{9x}{9x+2}\right)^{8x}.
  2. Apply L'Hôpital's rule to the expression (11+29x)8x\left(\frac{1}{1+\frac{2}{9x}}\right)^{8x}.
  3. Differentiate the numerator and denominator of the expression (11+29x)8x\left(\frac{1}{1+\frac{2}{9x}}\right)^{8x}.
  4. Apply L'Hôpital's rule to the expression 029x2\frac{0}{-\frac{2}{9x^2}}.
  5. Evaluate the limit of the expression 029x2\frac{0}{-\frac{2}{9x^2}}.

Frequently Asked Questions


Here are some frequently asked questions about the problem:

  • What is the limit of the expression (9x9x+2)8x\left(\frac{9x}{9x+2}\right)^{8x} as xx approaches infinity?
  • How do we simplify the expression (9x9x+2)8x\left(\frac{9x}{9x+2}\right)^{8x}?
  • What is L'Hôpital's rule, and how do we apply it to the expression (11+29x)8x\left(\frac{1}{1+\frac{2}{9x}}\right)^{8x}?
  • How do we differentiate the numerator and denominator of the expression (11+29x)8x\left(\frac{1}{1+\frac{2}{9x}}\right)^{8x}?
  • What is the final answer to the problem?

Conclusion


In this article, we evaluated the limit of the expression (9x9x+2)8x\left(\frac{9x}{9x+2}\right)^{8x} as xx approaches infinity. We simplified the expression and then applied L'Hôpital's rule to find the limit. The final answer is e29e^{-\frac{2}{9}}.

References


Here are some references that we used to write this article:

  • L'Hôpital's rule
  • Differentiation
  • Limits
  • Exponents
  • Rational functions

Further Reading


Here are some further reading resources that you can use to learn more about the topic:

  • Calculus
  • Mathematics
  • Limits
  • Exponents
  • Rational functions

Final Answer


The final answer is e29\boxed{e^{-\frac{2}{9}}}.

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Introduction


In our previous article, we evaluated the limit of the expression (9x9x+2)8x\left(\frac{9x}{9x+2}\right)^{8x} as xx approaches infinity using L'Hôpital's rule. In this article, we will answer some frequently asked questions about evaluating limits using L'Hôpital's rule.

Q&A


Q: What is L'Hôpital's rule, and how do we apply it to evaluate limits?

A: L'Hôpital's rule is a mathematical technique used to evaluate limits of the form 00\frac{0}{0} or \frac{\infty}{\infty}. To apply L'Hôpital's rule, we differentiate the numerator and denominator of the expression separately and then take the limit of the resulting expression.

Q: When can we use L'Hôpital's rule to evaluate limits?

A: We can use L'Hôpital's rule to evaluate limits when the limit is of the form 00\frac{0}{0} or \frac{\infty}{\infty}. This means that the numerator and denominator must both approach zero or infinity as the variable approaches a certain value.

Q: How do we differentiate the numerator and denominator of an expression?

A: To differentiate the numerator and denominator of an expression, we apply the power rule and the sum rule of differentiation. For example, if we have the expression x2+3xx^2 + 3x, we can differentiate it using the power rule and the sum rule.

Q: What are some common mistakes to avoid when using L'Hôpital's rule?

A: Some common mistakes to avoid when using L'Hôpital's rule include:

  • Not checking if the limit is of the form 00\frac{0}{0} or \frac{\infty}{\infty} before applying L'Hôpital's rule.
  • Not differentiating the numerator and denominator correctly.
  • Not taking the limit of the resulting expression after differentiating the numerator and denominator.

Q: Can we use L'Hôpital's rule to evaluate limits of trigonometric functions?

A: Yes, we can use L'Hôpital's rule to evaluate limits of trigonometric functions. For example, we can use L'Hôpital's rule to evaluate the limit of sinx\sin x as xx approaches infinity.

Q: Can we use L'Hôpital's rule to evaluate limits of exponential functions?

A: Yes, we can use L'Hôpital's rule to evaluate limits of exponential functions. For example, we can use L'Hôpital's rule to evaluate the limit of exe^x as xx approaches infinity.

Conclusion


In this article, we answered some frequently asked questions about evaluating limits using L'Hôpital's rule. We discussed when to use L'Hôpital's rule, how to differentiate the numerator and denominator of an expression, and some common mistakes to avoid when using L'Hôpital's rule.

Further Reading


Here are some further reading resources that you can use to learn more about the topic:

  • Calculus
  • Mathematics
  • Limits
  • Exponents
  • Rational functions

Final Answer


The final answer is e29\boxed{e^{-\frac{2}{9}}}.