Evaluate The Integral:${ \int_1^e \frac{\ln^2 X}{x} , Dx }$

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Introduction

The evaluation of definite integrals is a fundamental concept in calculus, and it plays a crucial role in various fields of mathematics and science. In this article, we will focus on evaluating the integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx. This integral is a classic example of a definite integral that requires the application of advanced techniques and formulas.

Background and Motivation

The integral in question is a special case of a more general integral, which is ∫1aln⁑2xx dx\int_1^a \frac{\ln^2 x}{x} \, dx. This integral has been studied extensively in the field of mathematics, and it has numerous applications in various areas, including physics, engineering, and economics. The evaluation of this integral is essential in understanding the behavior of certain functions and in solving problems that involve these functions.

The Integral and Its Properties

The integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx is a definite integral, which means that it has a specific upper and lower limit. In this case, the lower limit is 11 and the upper limit is ee. The integral is defined as the limit of a sum of infinitesimal areas under the curve of the function ln⁑2xx\frac{\ln^2 x}{x}.

Techniques for Evaluating the Integral

There are several techniques that can be used to evaluate the integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx. Some of the most common techniques include:

  • Integration by parts: This technique involves differentiating one function and integrating the other function.
  • Integration by substitution: This technique involves substituting a new variable into the integral to simplify it.
  • Partial fractions: This technique involves expressing a rational function as a sum of simpler fractions.

Integration by Parts

One of the most common techniques used to evaluate the integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx is integration by parts. This technique involves differentiating one function and integrating the other function. In this case, we can let u=ln⁑xu = \ln x and dv=1xdxdv = \frac{1}{x} dx. Then, we have du=1xdxdu = \frac{1}{x} dx and v=ln⁑xv = \ln x.

Integration by Substitution

Another technique that can be used to evaluate the integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx is integration by substitution. This technique involves substituting a new variable into the integral to simplify it. In this case, we can let x=etx = e^t. Then, we have dx=etdtdx = e^t dt and ln⁑x=t\ln x = t.

Partial Fractions

Partial fractions is another technique that can be used to evaluate the integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx. This technique involves expressing a rational function as a sum of simpler fractions. In this case, we can let ln⁑2xx=Ax+Bx2+Cx3\frac{\ln^2 x}{x} = \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}.

Evaluating the Integral

Now that we have discussed the techniques that can be used to evaluate the integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx, let's evaluate the integral using each of these techniques.

Integration by Parts

Using integration by parts, we have:

∫1eln⁑2xx dx=∫1eln⁑xβ‹…1x dx\int_1^e \frac{\ln^2 x}{x} \, dx = \int_1^e \ln x \cdot \frac{1}{x} \, dx

=ln⁑xβ‹…ln⁑x∣1eβˆ’βˆ«1e1xβ‹…ln⁑x dx= \ln x \cdot \ln x \bigg|_1^e - \int_1^e \frac{1}{x} \cdot \ln x \, dx

=(ln⁑e)2βˆ’(ln⁑1)2βˆ’βˆ«1e1xβ‹…ln⁑x dx= (\ln e)^2 - (\ln 1)^2 - \int_1^e \frac{1}{x} \cdot \ln x \, dx

=1βˆ’0βˆ’βˆ«1e1xβ‹…ln⁑x dx= 1 - 0 - \int_1^e \frac{1}{x} \cdot \ln x \, dx

=1βˆ’βˆ«1e1xβ‹…ln⁑x dx= 1 - \int_1^e \frac{1}{x} \cdot \ln x \, dx

Integration by Substitution

Using integration by substitution, we have:

∫1eln⁑2xx dx=∫11t2etβ‹…et dt\int_1^e \frac{\ln^2 x}{x} \, dx = \int_1^1 \frac{t^2}{e^t} \cdot e^t \, dt

=∫11t2 dt= \int_1^1 t^2 \, dt

=t33∣11= \frac{t^3}{3} \bigg|_1^1

=133βˆ’133= \frac{1^3}{3} - \frac{1^3}{3}

=0= 0

Partial Fractions

Using partial fractions, we have:

ln⁑2xx=Ax+Bx2+Cx3\frac{\ln^2 x}{x} = \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

=Ax+Bx2+Cx3= \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}

= \frac{A}{x} + \frac{B}{x^2} + \frac{<br/> # Q&A: Evaluating the Integral $\int_1^e \frac{\ln^2 x}{x} \, dx$

Introduction

In our previous article, we discussed the evaluation of the integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx. This integral is a classic example of a definite integral that requires the application of advanced techniques and formulas. In this article, we will answer some of the most frequently asked questions about this integral.

Q: What is the integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx?

A: The integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx is a definite integral that is defined as the limit of a sum of infinitesimal areas under the curve of the function ln⁑2xx\frac{\ln^2 x}{x}.

Q: What are the techniques used to evaluate the integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx?

A: There are several techniques that can be used to evaluate the integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx, including integration by parts, integration by substitution, and partial fractions.

Q: How do you use integration by parts to evaluate the integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx?

A: To use integration by parts, we let u=ln⁑xu = \ln x and dv=1xdxdv = \frac{1}{x} dx. Then, we have du=1xdxdu = \frac{1}{x} dx and v=ln⁑xv = \ln x. We can then use the formula ∫u dv=uvβˆ’βˆ«v du\int u \, dv = uv - \int v \, du to evaluate the integral.

Q: How do you use integration by substitution to evaluate the integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx?

A: To use integration by substitution, we let x=etx = e^t. Then, we have dx=etdtdx = e^t dt and ln⁑x=t\ln x = t. We can then use the formula ∫f(x) dx=F(x)+C\int f(x) \, dx = F(x) + C to evaluate the integral.

Q: How do you use partial fractions to evaluate the integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx?

A: To use partial fractions, we let ln⁑2xx=Ax+Bx2+Cx3\frac{\ln^2 x}{x} = \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3}. We can then use the formula ∫Ax dx=Aln⁑x+C\int \frac{A}{x} \, dx = A \ln x + C to evaluate the integral.

Q: What is the value of the integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx?

A: The value of the integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx is e2βˆ’1\frac{e}{2} - 1.

Q: Why is the integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx important?

A: The integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx is important because it is a classic example of a definite integral that requires the application of advanced techniques and formulas. It is also used in various fields of mathematics and science, including physics, engineering, and economics.

Q: How can I apply the techniques used to evaluate the integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx to other integrals?

A: The techniques used to evaluate the integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx can be applied to other integrals that involve similar functions and techniques. For example, you can use integration by parts to evaluate the integral ∫1eln⁑xx dx\int_1^e \frac{\ln x}{x} \, dx, and you can use integration by substitution to evaluate the integral ∫1e1x2 dx\int_1^e \frac{1}{x^2} \, dx.

Conclusion

In this article, we have answered some of the most frequently asked questions about the integral ∫1eln⁑2xx dx\int_1^e \frac{\ln^2 x}{x} \, dx. We have discussed the techniques used to evaluate the integral, including integration by parts, integration by substitution, and partial fractions. We have also provided examples of how to apply these techniques to other integrals.