Evaluate The Function \[$ F(x) \$\] Given By:$\[ f(x) = \begin{cases} -\frac{3}{4} X + 2, & \text{if } X \ \textless \ 4 \\ \frac{3}{2} X - 1, & \text{if } X \geq 4 \end{cases} \\]a. For \[$ X = 4 \$\], Find \[$ F(4)

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Introduction

In mathematics, a piecewise function is a function that is defined by multiple sub-functions, each applied to a specific interval of the domain. These functions are commonly used to model real-world phenomena that exhibit different behaviors in different regions. In this article, we will evaluate the function f(x){ f(x) } given by:

f(x)={−34x+2,if x \textless 432x−1,if x≥4{ f(x) = \begin{cases} -\frac{3}{4} x + 2, & \text{if } x \ \textless \ 4 \\ \frac{3}{2} x - 1, & \text{if } x \geq 4 \end{cases} }

Understanding Piecewise Functions

A piecewise function is a function that is defined by multiple sub-functions, each applied to a specific interval of the domain. The function is typically defined as:

f(x)={f1(x),if x∈D1f2(x),if x∈D2⋮if x∈Dn{ f(x) = \begin{cases} f_1(x), & \text{if } x \in D_1 \\ f_2(x), & \text{if } x \in D_2 \\ \vdots & \text{if } x \in D_n \end{cases} }

where f1(x),f2(x),…,fn(x)f_1(x), f_2(x), \ldots, f_n(x) are the sub-functions, and D1,D2,…,DnD_1, D_2, \ldots, D_n are the intervals of the domain.

Evaluating the Function at x = 4

To evaluate the function at x=4x = 4, we need to determine which sub-function is applicable. Since x=4x = 4 is greater than or equal to 4, we use the second sub-function:

f(4)=32(4)−1{ f(4) = \frac{3}{2} (4) - 1 }

Step-by-Step Solution

  1. Identify the sub-function applicable to x=4x = 4: Since x=4x = 4 is greater than or equal to 4, we use the second sub-function.
  2. Substitute x=4x = 4 into the second sub-function: f(4)=32(4)−1{ f(4) = \frac{3}{2} (4) - 1 }
  3. Simplify the expression: f(4)=6−1=5{ f(4) = 6 - 1 = 5 }

Conclusion

In this article, we evaluated the function f(x){ f(x) } given by:

f(x)={−34x+2,if x \textless 432x−1,if x≥4{ f(x) = \begin{cases} -\frac{3}{4} x + 2, & \text{if } x \ \textless \ 4 \\ \frac{3}{2} x - 1, & \text{if } x \geq 4 \end{cases} }

at x=4x = 4. We determined that the second sub-function is applicable, and we evaluated the function at x=4x = 4 using the second sub-function.

Key Takeaways

  • A piecewise function is a function that is defined by multiple sub-functions, each applied to a specific interval of the domain.
  • To evaluate a piecewise function, we need to determine which sub-function is applicable based on the value of xx.
  • We can use the second sub-function to evaluate the function at x=4x = 4.

Further Reading

For more information on piecewise functions, we recommend the following resources:

  • Khan Academy: Piecewise Functions
  • Mathway: Piecewise Functions
  • Wolfram MathWorld: Piecewise Functions

Practice Problems

  1. Evaluate the function f(x)={2x+1,if x \textless 3x2−1,if x≥3{ f(x) = \begin{cases} 2x + 1, & \text{if } x \ \textless \ 3 \\ x^2 - 1, & \text{if } x \geq 3 \end{cases} } at x=3x = 3.
  2. Evaluate the function f(x)={x2+1,if x \textless 22x−1,if x≥2{ f(x) = \begin{cases} x^2 + 1, & \text{if } x \ \textless \ 2 \\ 2x - 1, & \text{if } x \geq 2 \end{cases} } at x=2x = 2.

Solutions

  1. To evaluate the function at x=3x = 3, we need to determine which sub-function is applicable. Since x=3x = 3 is less than 3, we use the first sub-function:

f(3)=2(3)+1=7{ f(3) = 2(3) + 1 = 7 }

  1. To evaluate the function at x=2x = 2, we need to determine which sub-function is applicable. Since x=2x = 2 is greater than or equal to 2, we use the second sub-function:

Introduction

In our previous article, we evaluated the function f(x){ f(x) } given by:

f(x)={−34x+2,if x \textless 432x−1,if x≥4{ f(x) = \begin{cases} -\frac{3}{4} x + 2, & \text{if } x \ \textless \ 4 \\ \frac{3}{2} x - 1, & \text{if } x \geq 4 \end{cases} }

at x=4x = 4. In this article, we will provide a comprehensive Q&A guide to help you understand piecewise functions and how to evaluate them.

Q: What is a piecewise function?

A: A piecewise function is a function that is defined by multiple sub-functions, each applied to a specific interval of the domain.

Q: How do I determine which sub-function is applicable?

A: To determine which sub-function is applicable, you need to check the value of xx and see which interval it falls into. If xx is in the first interval, use the first sub-function. If xx is in the second interval, use the second sub-function, and so on.

Q: How do I evaluate a piecewise function?

A: To evaluate a piecewise function, you need to follow these steps:

  1. Determine which sub-function is applicable based on the value of xx.
  2. Substitute the value of xx into the applicable sub-function.
  3. Simplify the expression to get the final answer.

Q: What if I have multiple sub-functions with the same interval?

A: If you have multiple sub-functions with the same interval, you need to use the first sub-function that is applicable. For example, if you have:

f(x)={2x+1,if x \textless 3x2−1,if x≥3x3−1,if x≥3{ f(x) = \begin{cases} 2x + 1, & \text{if } x \ \textless \ 3 \\ x^2 - 1, & \text{if } x \geq 3 \\ x^3 - 1, & \text{if } x \geq 3 \end{cases} }

You would use the first sub-function that is applicable, which is 2x+12x + 1.

Q: Can I have a piecewise function with more than two sub-functions?

A: Yes, you can have a piecewise function with more than two sub-functions. For example:

f(x)={2x+1,if x \textless 1x2−1,if 1≤x≤3x3−1,if x≥3{ f(x) = \begin{cases} 2x + 1, & \text{if } x \ \textless \ 1 \\ x^2 - 1, & \text{if } 1 \leq x \leq 3 \\ x^3 - 1, & \text{if } x \geq 3 \end{cases} }

Q: How do I graph a piecewise function?

A: To graph a piecewise function, you need to graph each sub-function separately and then combine them. You can use a graphing calculator or software to help you graph the function.

Q: Can I have a piecewise function with a single sub-function?

A: Yes, you can have a piecewise function with a single sub-function. For example:

f(x)={2x+1,if x \textless 32x+1,if x≥3{ f(x) = \begin{cases} 2x + 1, & \text{if } x \ \textless \ 3 \\ 2x + 1, & \text{if } x \geq 3 \end{cases} }

This is equivalent to the function f(x)=2x+1f(x) = 2x + 1.

Conclusion

In this article, we provided a comprehensive Q&A guide to help you understand piecewise functions and how to evaluate them. We covered topics such as determining which sub-function is applicable, evaluating a piecewise function, and graphing a piecewise function.

Key Takeaways

  • A piecewise function is a function that is defined by multiple sub-functions, each applied to a specific interval of the domain.
  • To determine which sub-function is applicable, you need to check the value of xx and see which interval it falls into.
  • To evaluate a piecewise function, you need to follow the steps of determining which sub-function is applicable, substituting the value of xx into the applicable sub-function, and simplifying the expression.

Further Reading

For more information on piecewise functions, we recommend the following resources:

  • Khan Academy: Piecewise Functions
  • Mathway: Piecewise Functions
  • Wolfram MathWorld: Piecewise Functions

Practice Problems

  1. Evaluate the function f(x)={2x+1,if x \textless 3x2−1,if x≥3{ f(x) = \begin{cases} 2x + 1, & \text{if } x \ \textless \ 3 \\ x^2 - 1, & \text{if } x \geq 3 \end{cases} } at x=3x = 3.
  2. Evaluate the function f(x)={x2+1,if x \textless 22x−1,if x≥2{ f(x) = \begin{cases} x^2 + 1, & \text{if } x \ \textless \ 2 \\ 2x - 1, & \text{if } x \geq 2 \end{cases} } at x=2x = 2.

Solutions

  1. To evaluate the function at x=3x = 3, we need to determine which sub-function is applicable. Since x=3x = 3 is greater than or equal to 3, we use the second sub-function:

f(3)=x2−1=9−1=8{ f(3) = x^2 - 1 = 9 - 1 = 8 }

  1. To evaluate the function at x=2x = 2, we need to determine which sub-function is applicable. Since x=2x = 2 is less than 2, we use the first sub-function:

f(2)=x2+1=4+1=5{ f(2) = x^2 + 1 = 4 + 1 = 5 }