Evaluate The Following Expression:$\[ \cot \left(-\frac{23 \pi}{6}\right) = \\]

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Introduction


Trigonometry is a branch of mathematics that deals with the relationships between the sides and angles of triangles. It is a fundamental subject that has numerous applications in various fields, including physics, engineering, and navigation. In this article, we will focus on evaluating trigonometric expressions, specifically the cotangent function.

Understanding the Cotangent Function


The cotangent function, denoted by cot⁑x\cot x, is the reciprocal of the tangent function. It is defined as:

cot⁑x=cos⁑xsin⁑x\cot x = \frac{\cos x}{\sin x}

The cotangent function has a periodicity of Ο€\pi, which means that the value of cot⁑x\cot x repeats every Ο€\pi radians.

Evaluating the Expression


The given expression is cot⁑(βˆ’23Ο€6)\cot \left(-\frac{23 \pi}{6}\right). To evaluate this expression, we need to first simplify the angle βˆ’23Ο€6-\frac{23 \pi}{6}.

Simplifying the Angle


We can simplify the angle βˆ’23Ο€6-\frac{23 \pi}{6} by adding or subtracting multiples of Ο€\pi.

βˆ’23Ο€6=βˆ’22Ο€6βˆ’Ο€6=βˆ’11Ο€3βˆ’Ο€6-\frac{23 \pi}{6} = -\frac{22 \pi}{6} - \frac{\pi}{6} = -\frac{11 \pi}{3} - \frac{\pi}{6}

Since the cotangent function has a periodicity of Ο€\pi, we can further simplify the angle by adding or subtracting multiples of Ο€\pi.

βˆ’11Ο€3βˆ’Ο€6=βˆ’11Ο€3+5Ο€6=βˆ’6Ο€6βˆ’5Ο€6=βˆ’11Ο€6-\frac{11 \pi}{3} - \frac{\pi}{6} = -\frac{11 \pi}{3} + \frac{5 \pi}{6} = -\frac{6 \pi}{6} - \frac{5 \pi}{6} = -\frac{11 \pi}{6}

However, we can simplify it further by using the fact that cot⁑(βˆ’x)=βˆ’cot⁑x\cot (-x) = -\cot x.

cot⁑(βˆ’23Ο€6)=cot⁑(βˆ’22Ο€6βˆ’Ο€6)=cot⁑(βˆ’11Ο€3βˆ’Ο€6)\cot \left(-\frac{23 \pi}{6}\right) = \cot \left(-\frac{22 \pi}{6} - \frac{\pi}{6}\right) = \cot \left(-\frac{11 \pi}{3} - \frac{\pi}{6}\right)

Using the identity cot⁑(βˆ’x)=βˆ’cot⁑x\cot (-x) = -\cot x, we get:

cot⁑(βˆ’23Ο€6)=βˆ’cot⁑(11Ο€3+Ο€6)\cot \left(-\frac{23 \pi}{6}\right) = -\cot \left(\frac{11 \pi}{3} + \frac{\pi}{6}\right)

Now, we can use the fact that cot⁑(x+Ο€)=cot⁑x\cot (x + \pi) = \cot x to simplify the expression.

cot⁑(11Ο€3+Ο€6)=cot⁑(11Ο€3+2Ο€6)=cot⁑(11Ο€3+Ο€3)\cot \left(\frac{11 \pi}{3} + \frac{\pi}{6}\right) = \cot \left(\frac{11 \pi}{3} + \frac{2 \pi}{6}\right) = \cot \left(\frac{11 \pi}{3} + \frac{\pi}{3}\right)

Using the identity cot⁑(x+Ο€)=cot⁑x\cot (x + \pi) = \cot x, we get:

cot⁑(11Ο€3+Ο€3)=cot⁑(12Ο€3)=cot⁑(4Ο€)\cot \left(\frac{11 \pi}{3} + \frac{\pi}{3}\right) = \cot \left(\frac{12 \pi}{3}\right) = \cot (4 \pi)

Since the cotangent function has a periodicity of Ο€\pi, we can simplify the expression further.

cot⁑(4Ο€)=cot⁑(0)\cot (4 \pi) = \cot (0)

Using the fact that cot⁑0=0\cot 0 = 0, we get:

cot⁑(βˆ’23Ο€6)=βˆ’cot⁑(0)=βˆ’0=0\cot \left(-\frac{23 \pi}{6}\right) = -\cot (0) = -0 = 0

Conclusion


In this article, we evaluated the expression cot⁑(βˆ’23Ο€6)\cot \left(-\frac{23 \pi}{6}\right). We simplified the angle βˆ’23Ο€6-\frac{23 \pi}{6} by adding or subtracting multiples of Ο€\pi, and then used the identities cot⁑(βˆ’x)=βˆ’cot⁑x\cot (-x) = -\cot x and cot⁑(x+Ο€)=cot⁑x\cot (x + \pi) = \cot x to simplify the expression. Finally, we used the fact that cot⁑0=0\cot 0 = 0 to evaluate the expression.

Frequently Asked Questions


Q: What is the cotangent function?

A: The cotangent function is the reciprocal of the tangent function, defined as cot⁑x=cos⁑xsin⁑x\cot x = \frac{\cos x}{\sin x}.

Q: What is the periodicity of the cotangent function?

A: The cotangent function has a periodicity of Ο€\pi, which means that the value of cot⁑x\cot x repeats every Ο€\pi radians.

Q: How do you simplify the angle βˆ’23Ο€6-\frac{23 \pi}{6}?

A: You can simplify the angle βˆ’23Ο€6-\frac{23 \pi}{6} by adding or subtracting multiples of Ο€\pi.

Q: What is the value of cot⁑(βˆ’23Ο€6)\cot \left(-\frac{23 \pi}{6}\right)?

A: The value of cot⁑(βˆ’23Ο€6)\cot \left(-\frac{23 \pi}{6}\right) is 00.

References


  • [1] "Trigonometry" by Michael Corral, 2015.
  • [2] "Calculus" by Michael Spivak, 2008.
  • [3] "Mathematics for the Nonmathematician" by Morris Kline, 1967.

Further Reading


  • [1] "Trigonometry for Dummies" by Mary Jane Sterling, 2015.
  • [2] "Calculus for Dummies" by Mark Ryan, 2013.
  • [3] "Mathematics for the Nonmathematician" by Morris Kline, 1967.

Glossary


  • Cotangent: The reciprocal of the tangent function, defined as cot⁑x=cos⁑xsin⁑x\cot x = \frac{\cos x}{\sin x}.
  • Periodicity: The property of a function that repeats its values at regular intervals.
  • Simplifying an angle: The process of expressing an angle in a simpler form by adding or subtracting multiples of Ο€\pi.

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Q&A: Evaluating Trigonometric Expressions


Q: What is the cotangent function?

A: The cotangent function is the reciprocal of the tangent function, defined as cot⁑x=cos⁑xsin⁑x\cot x = \frac{\cos x}{\sin x}.

Q: What is the periodicity of the cotangent function?

A: The cotangent function has a periodicity of Ο€\pi, which means that the value of cot⁑x\cot x repeats every Ο€\pi radians.

Q: How do you simplify the angle βˆ’23Ο€6-\frac{23 \pi}{6}?

A: You can simplify the angle βˆ’23Ο€6-\frac{23 \pi}{6} by adding or subtracting multiples of Ο€\pi.

Q: What is the value of cot⁑(βˆ’23Ο€6)\cot \left(-\frac{23 \pi}{6}\right)?

A: The value of cot⁑(βˆ’23Ο€6)\cot \left(-\frac{23 \pi}{6}\right) is 00.

Q: What is the difference between the cotangent and tangent functions?

A: The cotangent function is the reciprocal of the tangent function. This means that cot⁑x=1tan⁑x\cot x = \frac{1}{\tan x}.

Q: How do you evaluate the expression cot⁑(Ο€4)\cot \left(\frac{\pi}{4}\right)?

A: To evaluate the expression cot⁑(Ο€4)\cot \left(\frac{\pi}{4}\right), we need to use the fact that cot⁑(Ο€4)=cos⁑(Ο€4)sin⁑(Ο€4)\cot \left(\frac{\pi}{4}\right) = \frac{\cos \left(\frac{\pi}{4}\right)}{\sin \left(\frac{\pi}{4}\right)}. Since cos⁑(Ο€4)=sin⁑(Ο€4)=12\cos \left(\frac{\pi}{4}\right) = \sin \left(\frac{\pi}{4}\right) = \frac{1}{\sqrt{2}}, we get cot⁑(Ο€4)=1212=1\cot \left(\frac{\pi}{4}\right) = \frac{\frac{1}{\sqrt{2}}}{\frac{1}{\sqrt{2}}} = 1.

Q: How do you evaluate the expression cot⁑(βˆ’Ο€4)\cot \left(-\frac{\pi}{4}\right)?

A: To evaluate the expression cot⁑(βˆ’Ο€4)\cot \left(-\frac{\pi}{4}\right), we need to use the fact that cot⁑(βˆ’x)=βˆ’cot⁑x\cot \left(-x\right) = -\cot x. Since cot⁑(Ο€4)=1\cot \left(\frac{\pi}{4}\right) = 1, we get cot⁑(βˆ’Ο€4)=βˆ’cot⁑(Ο€4)=βˆ’1\cot \left(-\frac{\pi}{4}\right) = -\cot \left(\frac{\pi}{4}\right) = -1.

Q: What is the relationship between the cotangent and cosine functions?

A: The cotangent function is the reciprocal of the tangent function, which is defined as tan⁑x=sin⁑xcos⁑x\tan x = \frac{\sin x}{\cos x}. This means that cot⁑x=1tan⁑x=cos⁑xsin⁑x\cot x = \frac{1}{\tan x} = \frac{\cos x}{\sin x}.

Q: How do you evaluate the expression cot⁑(Ο€3)\cot \left(\frac{\pi}{3}\right)?

A: To evaluate the expression cot⁑(Ο€3)\cot \left(\frac{\pi}{3}\right), we need to use the fact that cot⁑x=cos⁑xsin⁑x\cot x = \frac{\cos x}{\sin x}. Since cos⁑(Ο€3)=12\cos \left(\frac{\pi}{3}\right) = \frac{1}{2} and sin⁑(Ο€3)=32\sin \left(\frac{\pi}{3}\right) = \frac{\sqrt{3}}{2}, we get cot⁑(Ο€3)=1232=13\cot \left(\frac{\pi}{3}\right) = \frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}} = \frac{1}{\sqrt{3}}.

Q: How do you evaluate the expression cot⁑(βˆ’Ο€3)\cot \left(-\frac{\pi}{3}\right)?

A: To evaluate the expression cot⁑(βˆ’Ο€3)\cot \left(-\frac{\pi}{3}\right), we need to use the fact that cot⁑(βˆ’x)=βˆ’cot⁑x\cot \left(-x\right) = -\cot x. Since cot⁑(Ο€3)=13\cot \left(\frac{\pi}{3}\right) = \frac{1}{\sqrt{3}}, we get cot⁑(βˆ’Ο€3)=βˆ’cot⁑(Ο€3)=βˆ’13\cot \left(-\frac{\pi}{3}\right) = -\cot \left(\frac{\pi}{3}\right) = -\frac{1}{\sqrt{3}}.

Conclusion


In this article, we have evaluated various trigonometric expressions using the cotangent function. We have also discussed the periodicity of the cotangent function and how to simplify angles. Additionally, we have provided answers to frequently asked questions about the cotangent function.

Frequently Asked Questions


Q: What is the cotangent function?

A: The cotangent function is the reciprocal of the tangent function, defined as cot⁑x=cos⁑xsin⁑x\cot x = \frac{\cos x}{\sin x}.

Q: What is the periodicity of the cotangent function?

A: The cotangent function has a periodicity of Ο€\pi, which means that the value of cot⁑x\cot x repeats every Ο€\pi radians.

Q: How do you simplify the angle βˆ’23Ο€6-\frac{23 \pi}{6}?

A: You can simplify the angle βˆ’23Ο€6-\frac{23 \pi}{6} by adding or subtracting multiples of Ο€\pi.

Q: What is the value of cot⁑(βˆ’23Ο€6)\cot \left(-\frac{23 \pi}{6}\right)?

A: The value of cot⁑(βˆ’23Ο€6)\cot \left(-\frac{23 \pi}{6}\right) is 00.

References


  • [1] "Trigonometry" by Michael Corral, 2015.
  • [2] "Calculus" by Michael Spivak, 2008.
  • [3] "Mathematics for the Nonmathematician" by Morris Kline, 1967.

Further Reading


  • [1] "Trigonometry for Dummies" by Mary Jane Sterling, 2015.
  • [2] "Calculus for Dummies" by Mark Ryan, 2013.
  • [3] "Mathematics for the Nonmathematician" by Morris Kline, 1967.

Glossary


  • Cotangent: The reciprocal of the tangent function, defined as cot⁑x=cos⁑xsin⁑x\cot x = \frac{\cos x}{\sin x}.
  • Periodicity: The property of a function that repeats its values at regular intervals.
  • Simplifying an angle: The process of expressing an angle in a simpler form by adding or subtracting multiples of Ο€\pi.