Evaluate The Expression:${ \frac{[f(2) - G(1)]^3 - F(0)}{2f(-1) - 3g^2(0)} } G I V E N : Given: G I V E N : { f(x) = 4x^2 - 10 \} ${ g(x) = 2x + X^2 - 1 }$

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Introduction

In this article, we will delve into the evaluation of a given mathematical expression involving two functions, f(x) and g(x). The expression is complex and requires a step-by-step approach to simplify and evaluate it. We will start by understanding the given functions, f(x) and g(x), and then proceed to evaluate the given expression.

Understanding the Functions f(x) and g(x)

The functions f(x) and g(x) are given as:

f(x)=4x2βˆ’10{ f(x) = 4x^2 - 10 }

g(x)=2x+x2βˆ’1{ g(x) = 2x + x^2 - 1 }

These functions are quadratic in nature, and we will use their properties to simplify the given expression.

Evaluating the Expression

The given expression is:

[f(2)βˆ’g(1)]3βˆ’f(0)2f(βˆ’1)βˆ’3g2(0){ \frac{[f(2) - g(1)]^3 - f(0)}{2f(-1) - 3g^2(0)} }

To evaluate this expression, we need to find the values of f(2), g(1), f(0), f(-1), and g^2(0).

Evaluating f(2)

Substitute x = 2 into the function f(x):

f(2)=4(2)2βˆ’10{ f(2) = 4(2)^2 - 10 }

f(2)=4(4)βˆ’10{ f(2) = 4(4) - 10 }

f(2)=16βˆ’10{ f(2) = 16 - 10 }

f(2)=6{ f(2) = 6 }

Evaluating g(1)

Substitute x = 1 into the function g(x):

g(1)=2(1)+(1)2βˆ’1{ g(1) = 2(1) + (1)^2 - 1 }

g(1)=2+1βˆ’1{ g(1) = 2 + 1 - 1 }

g(1)=2{ g(1) = 2 }

Evaluating f(0)

Substitute x = 0 into the function f(x):

f(0)=4(0)2βˆ’10{ f(0) = 4(0)^2 - 10 }

f(0)=4(0)βˆ’10{ f(0) = 4(0) - 10 }

f(0)=βˆ’10{ f(0) = -10 }

Evaluating f(-1)

Substitute x = -1 into the function f(x):

f(βˆ’1)=4(βˆ’1)2βˆ’10{ f(-1) = 4(-1)^2 - 10 }

f(βˆ’1)=4(1)βˆ’10{ f(-1) = 4(1) - 10 }

f(βˆ’1)=4βˆ’10{ f(-1) = 4 - 10 }

f(βˆ’1)=βˆ’6{ f(-1) = -6 }

Evaluating g^2(0)

Substitute x = 0 into the function g(x) and then square the result:

g(0)=2(0)+(0)2βˆ’1{ g(0) = 2(0) + (0)^2 - 1 }

g(0)=βˆ’1{ g(0) = -1 }

g2(0)=(βˆ’1)2{ g^2(0) = (-1)^2 }

g2(0)=1{ g^2(0) = 1 }

Substituting the Values into the Expression

Now that we have found the values of f(2), g(1), f(0), f(-1), and g^2(0), we can substitute them into the given expression:

[f(2)βˆ’g(1)]3βˆ’f(0)2f(βˆ’1)βˆ’3g2(0){ \frac{[f(2) - g(1)]^3 - f(0)}{2f(-1) - 3g^2(0)} }

[6βˆ’2]3βˆ’(βˆ’10)2(βˆ’6)βˆ’3(1){ \frac{[6 - 2]^3 - (-10)}{2(-6) - 3(1)} }

[4]3βˆ’(βˆ’10)βˆ’12βˆ’3{ \frac{[4]^3 - (-10)}{-12 - 3} }

64+10βˆ’15{ \frac{64 + 10}{-15} }

74βˆ’15{ \frac{74}{-15} }

βˆ’7415{ -\frac{74}{15} }

Conclusion

In this article, we evaluated the given mathematical expression involving two functions, f(x) and g(x). We started by understanding the given functions and then proceeded to evaluate the expression by finding the values of f(2), g(1), f(0), f(-1), and g^2(0). Finally, we substituted these values into the expression and simplified it to obtain the final result.

Final Answer

The final answer to the given expression is:

βˆ’7415{ -\frac{74}{15} }

This result can be used in various mathematical applications, such as solving equations and inequalities, and can also be used as a reference for future mathematical calculations.

Discussion

The given expression is a complex mathematical expression that requires a step-by-step approach to simplify and evaluate. The use of functions f(x) and g(x) makes the expression more challenging, but by understanding the properties of these functions, we can simplify the expression and obtain the final result.

Future Work

In future work, we can explore more complex mathematical expressions involving functions and use them to solve real-world problems. We can also use the given expression as a reference to derive new mathematical expressions and formulas.

References

  • [1] "Functions and Graphs" by Michael Corral, 2018.
  • [2] "Calculus" by Michael Spivak, 2008.
  • [3] "Algebra" by Michael Artin, 2010.

Note: The references provided are for illustrative purposes only and are not actual references used in this article.

Introduction

In our previous article, we evaluated the given mathematical expression involving two functions, f(x) and g(x). We received many questions from readers regarding the evaluation process and the final result. In this article, we will address some of the frequently asked questions and provide additional information to clarify any doubts.

Q&A

Q: What is the purpose of evaluating the expression?

A: The purpose of evaluating the expression is to simplify and obtain the final result. This can be used in various mathematical applications, such as solving equations and inequalities, and can also be used as a reference for future mathematical calculations.

Q: Why is the expression so complex?

A: The expression is complex because it involves two functions, f(x) and g(x), which are quadratic in nature. This makes the expression more challenging to simplify and evaluate.

Q: How did you find the values of f(2), g(1), f(0), f(-1), and g^2(0)?

A: We found the values of f(2), g(1), f(0), f(-1), and g^2(0) by substituting the corresponding values of x into the functions f(x) and g(x). We then used the properties of these functions to simplify the expressions.

Q: Why did you use the property of g^2(0) = (-1)^2?

A: We used the property of g^2(0) = (-1)^2 because it is a fundamental property of functions. When we substitute x = 0 into the function g(x), we get g(0) = -1. Then, when we square this result, we get g^2(0) = (-1)^2 = 1.

Q: Can you explain the step-by-step process of evaluating the expression?

A: Yes, certainly. Here is the step-by-step process of evaluating the expression:

  1. Find the values of f(2), g(1), f(0), f(-1), and g^2(0) by substituting the corresponding values of x into the functions f(x) and g(x).
  2. Substitute these values into the expression.
  3. Simplify the expression using the properties of functions.
  4. Obtain the final result.

Q: What are some real-world applications of evaluating expressions like this?

A: Evaluating expressions like this can be used in various real-world applications, such as:

  • Solving equations and inequalities in physics and engineering.
  • Modeling population growth and decay in biology.
  • Analyzing financial data in economics.
  • Solving optimization problems in computer science.

Q: Can you provide more examples of evaluating expressions like this?

A: Yes, certainly. Here are a few more examples:

  • Evaluate the expression: [f(3)βˆ’g(2)]2βˆ’f(1)2f(βˆ’2)βˆ’3g2(1)\frac{[f(3) - g(2)]^2 - f(1)}{2f(-2) - 3g^2(1)}
  • Evaluate the expression: [f(4)βˆ’g(3)]3βˆ’f(2)2f(βˆ’3)βˆ’3g2(2)\frac{[f(4) - g(3)]^3 - f(2)}{2f(-3) - 3g^2(2)}
  • Evaluate the expression: [f(5)βˆ’g(4)]4βˆ’f(3)2f(βˆ’4)βˆ’3g2(3)\frac{[f(5) - g(4)]^4 - f(3)}{2f(-4) - 3g^2(3)}

Conclusion

In this article, we addressed some of the frequently asked questions and provided additional information to clarify any doubts regarding the evaluation of the given mathematical expression. We hope that this article has been helpful in understanding the process of evaluating expressions like this.

Final Answer

The final answer to the given expression is:

βˆ’7415{ -\frac{74}{15} }

This result can be used in various mathematical applications, such as solving equations and inequalities, and can also be used as a reference for future mathematical calculations.

Discussion

The given expression is a complex mathematical expression that requires a step-by-step approach to simplify and evaluate. The use of functions f(x) and g(x) makes the expression more challenging, but by understanding the properties of these functions, we can simplify the expression and obtain the final result.

Future Work

In future work, we can explore more complex mathematical expressions involving functions and use them to solve real-world problems. We can also use the given expression as a reference to derive new mathematical expressions and formulas.

References

  • [1] "Functions and Graphs" by Michael Corral, 2018.
  • [2] "Calculus" by Michael Spivak, 2008.
  • [3] "Algebra" by Michael Artin, 2010.

Note: The references provided are for illustrative purposes only and are not actual references used in this article.