Evaluate $\sqrt[3]{(x-y)(x+y)}$ When $x=76$ And $y=49$.

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Introduction

In this article, we will evaluate the expression (xβˆ’y)(x+y)3\sqrt[3]{(x-y)(x+y)} when x=76x=76 and y=49y=49. This involves substituting the given values of xx and yy into the expression and simplifying it to obtain the final result.

Understanding the Expression

The given expression is (xβˆ’y)(x+y)3\sqrt[3]{(x-y)(x+y)}. This expression involves the difference of squares, which can be simplified using the formula (aβˆ’b)(a+b)=a2βˆ’b2(a-b)(a+b) = a^2 - b^2. In this case, we have (xβˆ’y)(x+y)=x2βˆ’y2(x-y)(x+y) = x^2 - y^2.

Substituting the Values of xx and yy

We are given that x=76x=76 and y=49y=49. We can substitute these values into the expression x2βˆ’y2x^2 - y^2 to obtain:

762βˆ’49276^2 - 49^2

Evaluating the Expression

To evaluate the expression 762βˆ’49276^2 - 49^2, we can use the formula for the difference of squares:

(a2βˆ’b2)=(a+b)(aβˆ’b)(a^2 - b^2) = (a+b)(a-b)

In this case, we have:

(762βˆ’492)=(76+49)(76βˆ’49)(76^2 - 49^2) = (76+49)(76-49)

Simplifying the Expression

We can simplify the expression (76+49)(76βˆ’49)(76+49)(76-49) by evaluating the products:

(76+49)=125(76+49) = 125

(76βˆ’49)=27(76-49) = 27

Evaluating the Final Expression

Now that we have simplified the expression, we can evaluate the final expression:

(xβˆ’y)(x+y)3=(125)(27)3\sqrt[3]{(x-y)(x+y)} = \sqrt[3]{(125)(27)}

Evaluating the Cube Root

To evaluate the cube root of (125)(27)(125)(27), we can use the property of cube roots that states:

a33=a\sqrt[3]{a^3} = a

In this case, we have:

(125)(27)3=(53)(33)3\sqrt[3]{(125)(27)} = \sqrt[3]{(5^3)(3^3)}

Simplifying the Cube Root

We can simplify the cube root of (53)(33)(5^3)(3^3) by using the property of cube roots:

(53)(33)3=5β‹…3\sqrt[3]{(5^3)(3^3)} = 5 \cdot 3

Evaluating the Final Result

Now that we have simplified the cube root, we can evaluate the final result:

(xβˆ’y)(x+y)3=5β‹…3=15\sqrt[3]{(x-y)(x+y)} = 5 \cdot 3 = 15

Conclusion

In this article, we evaluated the expression (xβˆ’y)(x+y)3\sqrt[3]{(x-y)(x+y)} when x=76x=76 and y=49y=49. We substituted the given values of xx and yy into the expression, simplified it using the formula for the difference of squares, and evaluated the final result to obtain the final answer of 1515.

Frequently Asked Questions

  • What is the value of (xβˆ’y)(x+y)3\sqrt[3]{(x-y)(x+y)} when x=76x=76 and y=49y=49?
  • How do you simplify the expression (xβˆ’y)(x+y)3\sqrt[3]{(x-y)(x+y)}?
  • What is the final result of evaluating the expression (xβˆ’y)(x+y)3\sqrt[3]{(x-y)(x+y)} when x=76x=76 and y=49y=49?

References

  • [1] "Algebra" by Michael Artin
  • [2] "Calculus" by Michael Spivak
  • [3] "Mathematics for Computer Science" by Eric Lehman and Tom Leighton

Further Reading

  • [1] "Introduction to Algebra" by Richard Rusczyk
  • [2] "Calculus for Dummies" by Mark Ryan
  • [3] "Mathematics for Computer Science" by Eric Lehman and Tom Leighton

Related Topics

  • [1] "Evaluating Expressions with Exponents"
  • [2] "Simplifying Expressions with Fractions"
  • [3] "Evaluating Expressions with Variables"

Introduction

In our previous article, we evaluated the expression (xβˆ’y)(x+y)3\sqrt[3]{(x-y)(x+y)} when x=76x=76 and y=49y=49. In this article, we will answer some frequently asked questions related to this topic.

Q&A

Q: What is the value of (xβˆ’y)(x+y)3\sqrt[3]{(x-y)(x+y)} when x=76x=76 and y=49y=49?

A: The value of (xβˆ’y)(x+y)3\sqrt[3]{(x-y)(x+y)} when x=76x=76 and y=49y=49 is 1515.

Q: How do you simplify the expression (xβˆ’y)(x+y)3\sqrt[3]{(x-y)(x+y)}?

A: To simplify the expression (xβˆ’y)(x+y)3\sqrt[3]{(x-y)(x+y)}, we can use the formula for the difference of squares: (aβˆ’b)(a+b)=a2βˆ’b2(a-b)(a+b) = a^2 - b^2. We can then substitute the values of xx and yy into the expression and simplify it.

Q: What is the final result of evaluating the expression (xβˆ’y)(x+y)3\sqrt[3]{(x-y)(x+y)} when x=76x=76 and y=49y=49?

A: The final result of evaluating the expression (xβˆ’y)(x+y)3\sqrt[3]{(x-y)(x+y)} when x=76x=76 and y=49y=49 is 1515.

Q: Can you explain the steps involved in evaluating the expression (xβˆ’y)(x+y)3\sqrt[3]{(x-y)(x+y)}?

A: Yes, the steps involved in evaluating the expression (xβˆ’y)(x+y)3\sqrt[3]{(x-y)(x+y)} are as follows:

  1. Substitute the values of xx and yy into the expression.
  2. Simplify the expression using the formula for the difference of squares.
  3. Evaluate the cube root of the simplified expression.

Q: What is the significance of the cube root in this expression?

A: The cube root is used to evaluate the expression (xβˆ’y)(x+y)3\sqrt[3]{(x-y)(x+y)} because it allows us to find the value of the expression when x=76x=76 and y=49y=49.

Q: Can you provide more examples of evaluating expressions with cube roots?

A: Yes, here are a few more examples:

  • Evaluate (2xβˆ’3)(2x+3)3\sqrt[3]{(2x-3)(2x+3)} when x=4x=4.
  • Evaluate (x+2)(xβˆ’2)3\sqrt[3]{(x+2)(x-2)} when x=5x=5.
  • Evaluate (3xβˆ’2)(3x+2)3\sqrt[3]{(3x-2)(3x+2)} when x=3x=3.

Conclusion

In this article, we answered some frequently asked questions related to evaluating the expression (xβˆ’y)(x+y)3\sqrt[3]{(x-y)(x+y)} when x=76x=76 and y=49y=49. We provided step-by-step instructions on how to simplify the expression and evaluate the final result.

Frequently Asked Questions

  • What is the value of (xβˆ’y)(x+y)3\sqrt[3]{(x-y)(x+y)} when x=76x=76 and y=49y=49?
  • How do you simplify the expression (xβˆ’y)(x+y)3\sqrt[3]{(x-y)(x+y)}?
  • What is the final result of evaluating the expression (xβˆ’y)(x+y)3\sqrt[3]{(x-y)(x+y)} when x=76x=76 and y=49y=49?
  • Can you explain the steps involved in evaluating the expression (xβˆ’y)(x+y)3\sqrt[3]{(x-y)(x+y)}?
  • What is the significance of the cube root in this expression?
  • Can you provide more examples of evaluating expressions with cube roots?

References

  • [1] "Algebra" by Michael Artin
  • [2] "Calculus" by Michael Spivak
  • [3] "Mathematics for Computer Science" by Eric Lehman and Tom Leighton

Further Reading

  • [1] "Introduction to Algebra" by Richard Rusczyk
  • [2] "Calculus for Dummies" by Mark Ryan
  • [3] "Mathematics for Computer Science" by Eric Lehman and Tom Leighton

Related Topics

  • [1] "Evaluating Expressions with Exponents"
  • [2] "Simplifying Expressions with Fractions"
  • [3] "Evaluating Expressions with Variables"