Evaluate ∑ N = 1 12 ( 2 N + 5 \sum_{n=1}^{12} (2n+5 ∑ N = 1 12 ​ ( 2 N + 5 ]A. 29 B. 36 36 36 C. 216 D. 432

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Introduction

In mathematics, summation is a fundamental concept used to represent the sum of a series of numbers. It is denoted by the symbol \sum and is used to calculate the total value of a sequence of numbers. In this article, we will evaluate the summation n=112(2n+5)\sum_{n=1}^{12} (2n+5), which represents the sum of the expression (2n+5)(2n+5) for nn ranging from 11 to 1212.

Understanding the Summation Notation

The summation notation n=112(2n+5)\sum_{n=1}^{12} (2n+5) can be broken down into two parts:

  • The lower limit of the summation, which is 11, indicates that the summation starts from n=1n=1.
  • The upper limit of the summation, which is 1212, indicates that the summation ends at n=12n=12.
  • The expression (2n+5)(2n+5) is the term that is being summed.

Evaluating the Summation

To evaluate the summation, we need to substitute the values of nn from 11 to 1212 into the expression (2n+5)(2n+5) and calculate the sum.

Step 1: Substitute n=1n=1 into the expression (2n+5)(2n+5)

When n=1n=1, the expression becomes (2(1)+5)=7(2(1)+5) = 7.

Step 2: Substitute n=2n=2 into the expression (2n+5)(2n+5)

When n=2n=2, the expression becomes (2(2)+5)=9(2(2)+5) = 9.

Step 3: Substitute n=3n=3 into the expression (2n+5)(2n+5)

When n=3n=3, the expression becomes (2(3)+5)=11(2(3)+5) = 11.

Step 4: Substitute n=4n=4 into the expression (2n+5)(2n+5)

When n=4n=4, the expression becomes (2(4)+5)=13(2(4)+5) = 13.

Step 5: Substitute n=5n=5 into the expression (2n+5)(2n+5)

When n=5n=5, the expression becomes (2(5)+5)=15(2(5)+5) = 15.

Step 6: Substitute n=6n=6 into the expression (2n+5)(2n+5)

When n=6n=6, the expression becomes (2(6)+5)=17(2(6)+5) = 17.

Step 7: Substitute n=7n=7 into the expression (2n+5)(2n+5)

When n=7n=7, the expression becomes (2(7)+5)=19(2(7)+5) = 19.

Step 8: Substitute n=8n=8 into the expression (2n+5)(2n+5)

When n=8n=8, the expression becomes (2(8)+5)=21(2(8)+5) = 21.

Step 9: Substitute n=9n=9 into the expression (2n+5)(2n+5)

When n=9n=9, the expression becomes (2(9)+5)=23(2(9)+5) = 23.

Step 10: Substitute n=10n=10 into the expression (2n+5)(2n+5)

When n=10n=10, the expression becomes (2(10)+5)=25(2(10)+5) = 25.

Step 11: Substitute n=11n=11 into the expression (2n+5)(2n+5)

When n=11n=11, the expression becomes (2(11)+5)=27(2(11)+5) = 27.

Step 12: Substitute n=12n=12 into the expression (2n+5)(2n+5)

When n=12n=12, the expression becomes (2(12)+5)=29(2(12)+5) = 29.

Calculating the Sum

Now that we have calculated the value of the expression (2n+5)(2n+5) for each value of nn from 11 to 1212, we can calculate the sum:

7+9+11+13+15+17+19+21+23+25+27+29=2167 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23 + 25 + 27 + 29 = 216

Conclusion

In this article, we evaluated the summation n=112(2n+5)\sum_{n=1}^{12} (2n+5), which represents the sum of the expression (2n+5)(2n+5) for nn ranging from 11 to 1212. We broke down the summation notation, substituted the values of nn into the expression, and calculated the sum. The final answer is 216\boxed{216}.

Final Answer

The final answer is 216\boxed{216}.

Introduction

In our previous article, we evaluated the summation n=112(2n+5)\sum_{n=1}^{12} (2n+5), which represents the sum of the expression (2n+5)(2n+5) for nn ranging from 11 to 1212. In this article, we will answer some frequently asked questions related to the evaluation of this summation.

Q1: What is the formula for the summation n=112(2n+5)\sum_{n=1}^{12} (2n+5)?

A1: The formula for the summation n=112(2n+5)\sum_{n=1}^{12} (2n+5) is (2n+5)(2n+5), where nn ranges from 11 to 1212.

Q2: How do I evaluate the summation n=112(2n+5)\sum_{n=1}^{12} (2n+5)?

A2: To evaluate the summation n=112(2n+5)\sum_{n=1}^{12} (2n+5), you need to substitute the values of nn from 11 to 1212 into the expression (2n+5)(2n+5) and calculate the sum.

Q3: What is the value of the expression (2n+5)(2n+5) when n=1n=1?

A3: When n=1n=1, the expression (2n+5)(2n+5) becomes (2(1)+5)=7(2(1)+5) = 7.

Q4: What is the value of the expression (2n+5)(2n+5) when n=12n=12?

A4: When n=12n=12, the expression (2n+5)(2n+5) becomes (2(12)+5)=29(2(12)+5) = 29.

Q5: How do I calculate the sum of the expression (2n+5)(2n+5) for nn ranging from 11 to 1212?

A5: To calculate the sum of the expression (2n+5)(2n+5) for nn ranging from 11 to 1212, you need to add up the values of the expression for each value of nn from 11 to 1212.

Q6: What is the final answer to the summation n=112(2n+5)\sum_{n=1}^{12} (2n+5)?

A6: The final answer to the summation n=112(2n+5)\sum_{n=1}^{12} (2n+5) is 216\boxed{216}.

Q7: Can I use a formula to calculate the sum of the expression (2n+5)(2n+5) for nn ranging from 11 to 1212?

A7: Yes, you can use the formula for the sum of an arithmetic series to calculate the sum of the expression (2n+5)(2n+5) for nn ranging from 11 to 1212. The formula is:

n=1n(2n+5)=n2(a1+an)\sum_{n=1}^{n} (2n+5) = \frac{n}{2} (a_1 + a_n)

where a1a_1 is the first term and ana_n is the last term.

Q8: How do I apply the formula for the sum of an arithmetic series to the summation n=112(2n+5)\sum_{n=1}^{12} (2n+5)?

A8: To apply the formula for the sum of an arithmetic series to the summation n=112(2n+5)\sum_{n=1}^{12} (2n+5), you need to identify the first term and the last term of the series. The first term is a1=(2(1)+5)=7a_1 = (2(1)+5) = 7 and the last term is an=(2(12)+5)=29a_n = (2(12)+5) = 29. Then, you can plug these values into the formula:

n=112(2n+5)=122(7+29)\sum_{n=1}^{12} (2n+5) = \frac{12}{2} (7 + 29)

n=112(2n+5)=6(36)\sum_{n=1}^{12} (2n+5) = 6 (36)

n=112(2n+5)=216\sum_{n=1}^{12} (2n+5) = 216

Conclusion

In this article, we answered some frequently asked questions related to the evaluation of the summation n=112(2n+5)\sum_{n=1}^{12} (2n+5). We provided step-by-step solutions to each question and explained the concepts and formulas used to evaluate the summation.

Final Answer

The final answer to the summation n=112(2n+5)\sum_{n=1}^{12} (2n+5) is 216\boxed{216}.