Evaluate Each Expression Without A Calculator.4) ${ 2 \cos 2\left(67.5 {\circ}\right) - 1 = \square }$5) ${ 2 \sin\left(112.5^{\circ}\right) \cos\left(112.5^{\circ}\right) = \square }$6) $[ \frac{2

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Introduction

Trigonometry is a branch of mathematics that deals with the relationships between the sides and angles of triangles. It is a fundamental subject that has numerous applications in various fields, including physics, engineering, and navigation. In this article, we will evaluate three trigonometric expressions without the use of a calculator.

Expression 1: 2cos⁑2(67.5∘)βˆ’12 \cos^2\left(67.5^{\circ}\right) - 1

To evaluate this expression, we can use the Pythagorean identity, which states that sin⁑2(x)+cos⁑2(x)=1\sin^2(x) + \cos^2(x) = 1. Since we are given cos⁑2(67.5∘)\cos^2(67.5^{\circ}), we can rewrite the expression as follows:

2cos⁑2(67.5∘)βˆ’1=2(1βˆ’sin⁑2(67.5∘))βˆ’12 \cos^2\left(67.5^{\circ}\right) - 1 = 2 \left(1 - \sin^2\left(67.5^{\circ}\right)\right) - 1

Using the Pythagorean identity, we can simplify the expression further:

2(1βˆ’sin⁑2(67.5∘))βˆ’1=2βˆ’2sin⁑2(67.5∘)βˆ’12 \left(1 - \sin^2\left(67.5^{\circ}\right)\right) - 1 = 2 - 2 \sin^2\left(67.5^{\circ}\right) - 1

2βˆ’2sin⁑2(67.5∘)βˆ’1=1βˆ’2sin⁑2(67.5∘)2 - 2 \sin^2\left(67.5^{\circ}\right) - 1 = 1 - 2 \sin^2\left(67.5^{\circ}\right)

Now, we need to find the value of sin⁑(67.5∘)\sin(67.5^{\circ}). Since 67.5∘67.5^{\circ} is not a standard angle, we can use the fact that sin⁑(67.5∘)=cos⁑(22.5∘)\sin(67.5^{\circ}) = \cos(22.5^{\circ}). Using the unit circle or a trigonometric table, we can find that cos⁑(22.5∘)=2+64\cos(22.5^{\circ}) = \frac{\sqrt{2} + \sqrt{6}}{4}.

Substituting this value into the expression, we get:

1βˆ’2sin⁑2(67.5∘)=1βˆ’2(2+64)21 - 2 \sin^2\left(67.5^{\circ}\right) = 1 - 2 \left(\frac{\sqrt{2} + \sqrt{6}}{4}\right)^2

Simplifying the expression further, we get:

1βˆ’2(2+64)2=1βˆ’2(2+6)2161 - 2 \left(\frac{\sqrt{2} + \sqrt{6}}{4}\right)^2 = 1 - \frac{2\left(\sqrt{2} + \sqrt{6}\right)^2}{16}

1βˆ’2(2+6)216=1βˆ’2(2+23+6)161 - \frac{2\left(\sqrt{2} + \sqrt{6}\right)^2}{16} = 1 - \frac{2\left(2 + 2\sqrt{3} + 6\right)}{16}

1βˆ’2(2+23+6)16=1βˆ’2(8+23)161 - \frac{2\left(2 + 2\sqrt{3} + 6\right)}{16} = 1 - \frac{2\left(8 + 2\sqrt{3}\right)}{16}

1βˆ’2(8+23)16=1βˆ’16+43161 - \frac{2\left(8 + 2\sqrt{3}\right)}{16} = 1 - \frac{16 + 4\sqrt{3}}{16}

1βˆ’16+4316=16βˆ’16βˆ’43161 - \frac{16 + 4\sqrt{3}}{16} = \frac{16 - 16 - 4\sqrt{3}}{16}

16βˆ’16βˆ’4316=βˆ’4316\frac{16 - 16 - 4\sqrt{3}}{16} = \frac{-4\sqrt{3}}{16}

βˆ’4316=βˆ’34\frac{-4\sqrt{3}}{16} = \frac{-\sqrt{3}}{4}

Therefore, the value of the expression 2cos⁑2(67.5∘)βˆ’12 \cos^2\left(67.5^{\circ}\right) - 1 is βˆ’34\frac{-\sqrt{3}}{4}.

Expression 2: 2sin⁑(112.5∘)cos⁑(112.5∘)2 \sin\left(112.5^{\circ}\right) \cos\left(112.5^{\circ}\right)

To evaluate this expression, we can use the angle addition formula, which states that sin⁑(a+b)=sin⁑(a)cos⁑(b)+cos⁑(a)sin⁑(b)\sin(a + b) = \sin(a) \cos(b) + \cos(a) \sin(b). Since we are given sin⁑(112.5∘)\sin(112.5^{\circ}) and cos⁑(112.5∘)\cos(112.5^{\circ}), we can rewrite the expression as follows:

2sin⁑(112.5∘)cos⁑(112.5∘)=2sin⁑(45∘+67.5∘)2 \sin\left(112.5^{\circ}\right) \cos\left(112.5^{\circ}\right) = 2 \sin\left(45^{\circ} + 67.5^{\circ}\right)

Using the angle addition formula, we can simplify the expression further:

2sin⁑(45∘+67.5∘)=2(sin⁑(45∘)cos⁑(67.5∘)+cos⁑(45∘)sin⁑(67.5∘))2 \sin\left(45^{\circ} + 67.5^{\circ}\right) = 2 \left(\sin(45^{\circ}) \cos(67.5^{\circ}) + \cos(45^{\circ}) \sin(67.5^{\circ})\right)

Using the unit circle or a trigonometric table, we can find that sin⁑(45∘)=22\sin(45^{\circ}) = \frac{\sqrt{2}}{2}, cos⁑(45∘)=22\cos(45^{\circ}) = \frac{\sqrt{2}}{2}, sin⁑(67.5∘)=2+64\sin(67.5^{\circ}) = \frac{\sqrt{2} + \sqrt{6}}{4}, and cos⁑(67.5∘)=2βˆ’64\cos(67.5^{\circ}) = \frac{\sqrt{2} - \sqrt{6}}{4}.

Substituting these values into the expression, we get:

2(sin⁑(45∘)cos⁑(67.5∘)+cos⁑(45∘)sin⁑(67.5∘))=2(222βˆ’64+222+64)2 \left(\sin(45^{\circ}) \cos(67.5^{\circ}) + \cos(45^{\circ}) \sin(67.5^{\circ})\right) = 2 \left(\frac{\sqrt{2}}{2} \frac{\sqrt{2} - \sqrt{6}}{4} + \frac{\sqrt{2}}{2} \frac{\sqrt{2} + \sqrt{6}}{4}\right)

Simplifying the expression further, we get:

2(222βˆ’64+222+64)=2(2(2βˆ’6)+2(2+6)8)2 \left(\frac{\sqrt{2}}{2} \frac{\sqrt{2} - \sqrt{6}}{4} + \frac{\sqrt{2}}{2} \frac{\sqrt{2} + \sqrt{6}}{4}\right) = 2 \left(\frac{\sqrt{2}(\sqrt{2} - \sqrt{6}) + \sqrt{2}(\sqrt{2} + \sqrt{6})}{8}\right)

2(2(2βˆ’6)+2(2+6)8)=2(22βˆ’26+22+268)2 \left(\frac{\sqrt{2}(\sqrt{2} - \sqrt{6}) + \sqrt{2}(\sqrt{2} + \sqrt{6})}{8}\right) = 2 \left(\frac{2\sqrt{2} - 2\sqrt{6} + 2\sqrt{2} + 2\sqrt{6}}{8}\right)

2(22βˆ’26+22+268)=2(428)2 \left(\frac{2\sqrt{2} - 2\sqrt{6} + 2\sqrt{2} + 2\sqrt{6}}{8}\right) = 2 \left(\frac{4\sqrt{2}}{8}\right)

2(428)=4242 \left(\frac{4\sqrt{2}}{8}\right) = \frac{4\sqrt{2}}{4}

424=2\frac{4\sqrt{2}}{4} = \sqrt{2}

Therefore, the value of the expression 2sin⁑(112.5∘)cos⁑(112.5∘)2 \sin\left(112.5^{\circ}\right) \cos\left(112.5^{\circ}\right) is 2\sqrt{2}.

Expression 3: 2sin⁑(67.5∘)cos⁑(67.5∘)sin⁑(112.5∘)\frac{2 \sin\left(67.5^{\circ}\right) \cos\left(67.5^{\circ}\right)}{\sin\left(112.5^{\circ}\right)}

To evaluate this expression, we can use the angle addition formula, which states that sin⁑(a+b)=sin⁑(a)cos⁑(b)+cos⁑(a)sin⁑(b)\sin(a + b) = \sin(a) \cos(b) + \cos(a) \sin(b). Since we are given sin⁑(67.5∘)\sin(67.5^{\circ}), cos⁑(67.5∘)\cos(67.5^{\circ}), and sin⁑(112.5∘)\sin(112.5^{\circ}), we can rewrite the expression as follows:

2sin⁑(67.5∘)cos⁑(67.5∘)sin⁑(112.5∘)=2sin⁑(45∘+22.5∘)sin⁑(45∘+67.5∘)\frac{2 \sin\left(67.5^{\circ}\right) \cos\left(67.5^{\circ}\right)}{\sin\left(112.5^{\circ}\right)} = \frac{2 \sin\left(45^{\circ} + 22.5^{\circ}\right)}{\sin\left(45^{\circ} + 67.5^{\circ}\right)}

Using the angle addition formula, we can simplify the expression further:

\frac{2 \sin\left(45^{\circ} + 22.5^{\circ}\right)}{\sin\left(45^{\circ} + 67.5^{\circ}\right)} = \frac{2 \left(\sin(45^{\circ}) \cos(22.5^{\circ}) + \cos<br/> **Evaluating Trigonometric Expressions without a Calculator: Q&A** ===========================================================

Introduction

In our previous article, we evaluated three trigonometric expressions without the use of a calculator. In this article, we will answer some common questions related to these expressions and provide additional insights.

Q: What is the value of 2cos⁑2(67.5∘)βˆ’12 \cos^2\left(67.5^{\circ}\right) - 1?

A: The value of 2cos⁑2(67.5∘)βˆ’12 \cos^2\left(67.5^{\circ}\right) - 1 is βˆ’34\frac{-\sqrt{3}}{4}.

Q: How did you simplify the expression 2cos⁑2(67.5∘)βˆ’12 \cos^2\left(67.5^{\circ}\right) - 1?

A: We used the Pythagorean identity, which states that sin⁑2(x)+cos⁑2(x)=1\sin^2(x) + \cos^2(x) = 1. We rewrote the expression as 2(1βˆ’sin⁑2(67.5∘))βˆ’12 \left(1 - \sin^2\left(67.5^{\circ}\right)\right) - 1 and simplified it further using the Pythagorean identity.

Q: What is the value of 2sin⁑(112.5∘)cos⁑(112.5∘)2 \sin\left(112.5^{\circ}\right) \cos\left(112.5^{\circ}\right)?

A: The value of 2sin⁑(112.5∘)cos⁑(112.5∘)2 \sin\left(112.5^{\circ}\right) \cos\left(112.5^{\circ}\right) is 2\sqrt{2}.

Q: How did you simplify the expression 2sin⁑(112.5∘)cos⁑(112.5∘)2 \sin\left(112.5^{\circ}\right) \cos\left(112.5^{\circ}\right)?

A: We used the angle addition formula, which states that sin⁑(a+b)=sin⁑(a)cos⁑(b)+cos⁑(a)sin⁑(b)\sin(a + b) = \sin(a) \cos(b) + \cos(a) \sin(b). We rewrote the expression as 2sin⁑(45∘+67.5∘)2 \sin\left(45^{\circ} + 67.5^{\circ}\right) and simplified it further using the angle addition formula.

Q: What is the value of 2sin⁑(67.5∘)cos⁑(67.5∘)sin⁑(112.5∘)\frac{2 \sin\left(67.5^{\circ}\right) \cos\left(67.5^{\circ}\right)}{\sin\left(112.5^{\circ}\right)}?

A: The value of 2sin⁑(67.5∘)cos⁑(67.5∘)sin⁑(112.5∘)\frac{2 \sin\left(67.5^{\circ}\right) \cos\left(67.5^{\circ}\right)}{\sin\left(112.5^{\circ}\right)} is 2\sqrt{2}.

Q: How did you simplify the expression 2sin⁑(67.5∘)cos⁑(67.5∘)sin⁑(112.5∘)\frac{2 \sin\left(67.5^{\circ}\right) \cos\left(67.5^{\circ}\right)}{\sin\left(112.5^{\circ}\right)}?

A: We used the angle addition formula, which states that sin⁑(a+b)=sin⁑(a)cos⁑(b)+cos⁑(a)sin⁑(b)\sin(a + b) = \sin(a) \cos(b) + \cos(a) \sin(b). We rewrote the expression as 2sin⁑(45∘+22.5∘)sin⁑(45∘+67.5∘)\frac{2 \sin\left(45^{\circ} + 22.5^{\circ}\right)}{\sin\left(45^{\circ} + 67.5^{\circ}\right)} and simplified it further using the angle addition formula.

Conclusion

In this article, we answered some common questions related to the evaluation of trigonometric expressions without a calculator. We provided additional insights and simplified expressions using various trigonometric identities. We hope that this article has been helpful in understanding the concepts of trigonometry and how to evaluate expressions without a calculator.

Additional Resources

For more information on trigonometry and how to evaluate expressions without a calculator, please refer to the following resources:

  • Trigonometry textbooks and online resources
  • Online calculators and trigonometric software
  • Math forums and discussion groups

Final Thoughts

Evaluating trigonometric expressions without a calculator requires a deep understanding of trigonometric identities and formulas. By practicing and simplifying expressions using various identities, you can become proficient in evaluating trigonometric expressions without a calculator. We hope that this article has been helpful in your journey to learn trigonometry and how to evaluate expressions without a calculator.