Enter The Values For $m, N$, And $p$ That Complete The Difference:$\[ \frac{7}{x} - \frac{3}{2} = \frac{n - M X}{p X} \\]$\[ \begin{array}{l} m = \square \\ n = \square \\ p = \square \\ \end{array} \\]

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Introduction

In this article, we will delve into the world of algebra and focus on solving a specific equation involving fractions. The given equation is 7xβˆ’32=nβˆ’mxpx\frac{7}{x} - \frac{3}{2} = \frac{n - m x}{p x}. Our goal is to find the values of mm, nn, and pp that complete the difference. This involves manipulating the equation to isolate the variables and solve for their respective values.

Understanding the Equation

The given equation is a rational equation, which means it involves fractions with variables in the numerator and denominator. To solve this equation, we need to first simplify it by finding a common denominator for the fractions. Once we have a common denominator, we can combine the fractions and then proceed to solve for the variables.

Simplifying the Equation

To simplify the equation, we need to find a common denominator for the fractions. The common denominator for the fractions 7x\frac{7}{x} and 32\frac{3}{2} is 2x2x. We can rewrite the equation as follows:

7xβˆ’32=nβˆ’mxpx\frac{7}{x} - \frac{3}{2} = \frac{n - m x}{p x}

142xβˆ’3x2x=nβˆ’mxpx\frac{14}{2x} - \frac{3x}{2x} = \frac{n - m x}{p x}

14βˆ’3x22x=nβˆ’mxpx\frac{14 - 3x^2}{2x} = \frac{n - m x}{p x}

Combining the Fractions

Now that we have a common denominator, we can combine the fractions on the left-hand side of the equation:

14βˆ’3x22x=nβˆ’mxpx\frac{14 - 3x^2}{2x} = \frac{n - m x}{p x}

14βˆ’3x22x=nβˆ’mxpx\frac{14 - 3x^2}{2x} = \frac{n - m x}{p x}

Solving for the Variables

To solve for the variables, we need to isolate them on one side of the equation. We can start by multiplying both sides of the equation by 2xp2xp to eliminate the fractions:

2xpβ‹…14βˆ’3x22x=2xpβ‹…nβˆ’mxpx2xp \cdot \frac{14 - 3x^2}{2x} = 2xp \cdot \frac{n - m x}{p x}

2p(14βˆ’3x2)=2nβˆ’2mx2p(14 - 3x^2) = 2n - 2mx

Expanding and Simplifying

Now that we have eliminated the fractions, we can expand and simplify the equation:

28pβˆ’6px2=2nβˆ’2mx28p - 6px^2 = 2n - 2mx

Rearranging the Terms

To isolate the variables, we need to rearrange the terms in the equation. We can start by moving all the terms involving xx to one side of the equation:

28pβˆ’2n=2mxβˆ’6px228p - 2n = 2mx - 6px^2

Factoring Out the Common Term

Now that we have isolated the variables, we can factor out the common term xx from the right-hand side of the equation:

28pβˆ’2n=x(2mβˆ’6px)28p - 2n = x(2m - 6px)

Solving for the Variables

To solve for the variables, we need to set the equation equal to zero. We can do this by setting the left-hand side of the equation equal to zero:

28pβˆ’2n=028p - 2n = 0

Solving for mm

Now that we have isolated the variables, we can solve for mm. We can start by dividing both sides of the equation by 2x2x:

m=28pβˆ’2n2xm = \frac{28p - 2n}{2x}

Solving for nn

To solve for nn, we can start by multiplying both sides of the equation by 2x2x:

2n=28pβˆ’2mx2n = 28p - 2mx

Solving for pp

To solve for pp, we can start by multiplying both sides of the equation by 2x2x:

2p=2nβˆ’2mx282p = \frac{2n - 2mx}{28}

Conclusion

In this article, we have solved the equation 7xβˆ’32=nβˆ’mxpx\frac{7}{x} - \frac{3}{2} = \frac{n - m x}{p x} and found the values of mm, nn, and pp that complete the difference. We have used algebraic manipulation to simplify the equation and isolate the variables. The final values of mm, nn, and pp are:

m=28pβˆ’2n2xm = \frac{28p - 2n}{2x}

n=28pβˆ’2mx2n = \frac{28p - 2mx}{2}

p=2nβˆ’2mx56p = \frac{2n - 2mx}{56}

These values can be used to complete the difference in the given equation.

Discussion

The equation 7xβˆ’32=nβˆ’mxpx\frac{7}{x} - \frac{3}{2} = \frac{n - m x}{p x} is a rational equation that involves fractions with variables in the numerator and denominator. To solve this equation, we need to simplify it by finding a common denominator for the fractions and then proceed to solve for the variables. The final values of mm, nn, and pp are:

m=28pβˆ’2n2xm = \frac{28p - 2n}{2x}

n=28pβˆ’2mx2n = \frac{28p - 2mx}{2}

p=2nβˆ’2mx56p = \frac{2n - 2mx}{56}

These values can be used to complete the difference in the given equation.

References

  • [1] Algebra, 2nd ed. by Michael Artin
  • [2] Calculus, 3rd ed. by Michael Spivak
  • [3] Linear Algebra and Its Applications, 4th ed. by Gilbert Strang

Glossary

  • Rational Equation: An equation that involves fractions with variables in the numerator and denominator.
  • Common Denominator: A common multiple of the denominators of two or more fractions.
  • Algebraic Manipulation: The process of simplifying and rearranging an equation to isolate the variables.
  • Variables: The unknown values in an equation that need to be solved for.

Introduction

In our previous article, we solved the equation 7xβˆ’32=nβˆ’mxpx\frac{7}{x} - \frac{3}{2} = \frac{n - m x}{p x} and found the values of mm, nn, and pp that complete the difference. In this article, we will answer some frequently asked questions related to solving the equation.

Q: What is the common denominator for the fractions in the equation?

A: The common denominator for the fractions in the equation is 2x2x.

Q: How do I simplify the equation to isolate the variables?

A: To simplify the equation, you need to find a common denominator for the fractions and then combine them. Once you have a common denominator, you can multiply both sides of the equation by the common denominator to eliminate the fractions.

Q: How do I solve for the variables mm, nn, and pp?

A: To solve for the variables mm, nn, and pp, you need to isolate them on one side of the equation. You can do this by multiplying both sides of the equation by 2xp2xp to eliminate the fractions, and then rearranging the terms to isolate the variables.

Q: What are the final values of mm, nn, and pp?

A: The final values of mm, nn, and pp are:

m=28pβˆ’2n2xm = \frac{28p - 2n}{2x}

n=28pβˆ’2mx2n = \frac{28p - 2mx}{2}

p=2nβˆ’2mx56p = \frac{2n - 2mx}{56}

Q: How do I use the values of mm, nn, and pp to complete the difference in the equation?

A: To use the values of mm, nn, and pp to complete the difference in the equation, you can substitute the values into the equation and simplify. This will give you the final solution to the equation.

Q: What are some common mistakes to avoid when solving the equation?

A: Some common mistakes to avoid when solving the equation include:

  • Not finding a common denominator for the fractions
  • Not multiplying both sides of the equation by the common denominator to eliminate the fractions
  • Not isolating the variables on one side of the equation
  • Not simplifying the equation to its simplest form

Q: How do I check my solution to the equation?

A: To check your solution to the equation, you can substitute the values of mm, nn, and pp back into the original equation and simplify. If the equation is true, then your solution is correct.

Conclusion

In this article, we have answered some frequently asked questions related to solving the equation 7xβˆ’32=nβˆ’mxpx\frac{7}{x} - \frac{3}{2} = \frac{n - m x}{p x}. We have provided step-by-step instructions on how to simplify the equation, isolate the variables, and solve for the values of mm, nn, and pp. We have also provided some common mistakes to avoid and tips on how to check your solution to the equation.

Discussion

Solving the equation 7xβˆ’32=nβˆ’mxpx\frac{7}{x} - \frac{3}{2} = \frac{n - m x}{p x} requires careful attention to detail and a thorough understanding of algebraic manipulation. By following the steps outlined in this article, you can solve the equation and find the values of mm, nn, and pp that complete the difference.

References

  • [1] Algebra, 2nd ed. by Michael Artin
  • [2] Calculus, 3rd ed. by Michael Spivak
  • [3] Linear Algebra and Its Applications, 4th ed. by Gilbert Strang

Glossary

  • Rational Equation: An equation that involves fractions with variables in the numerator and denominator.
  • Common Denominator: A common multiple of the denominators of two or more fractions.
  • Algebraic Manipulation: The process of simplifying and rearranging an equation to isolate the variables.
  • Variables: The unknown values in an equation that need to be solved for.