Differentiate The Following Function.${ F(x) = X^5 E^{7x} }$ { F^{\prime}(x) = \}

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Introduction

In this article, we will differentiate the given function f(x)=x5e7xf(x) = x^5 e^{7x} using the product rule of differentiation. The product rule states that if we have a function of the form f(x)=u(x)v(x)f(x) = u(x)v(x), then the derivative of f(x)f(x) is given by f(x)=u(x)v(x)+u(x)v(x)f^{\prime}(x) = u^{\prime}(x)v(x) + u(x)v^{\prime}(x).

Step 1: Identify the Functions u(x)u(x) and v(x)v(x)

In the given function f(x)=x5e7xf(x) = x^5 e^{7x}, we can identify u(x)=x5u(x) = x^5 and v(x)=e7xv(x) = e^{7x}.

Step 2: Find the Derivatives of u(x)u(x) and v(x)v(x)

To find the derivative of u(x)=x5u(x) = x^5, we use the power rule of differentiation, which states that if f(x)=xnf(x) = x^n, then f(x)=nxn1f^{\prime}(x) = nx^{n-1}. Therefore, the derivative of u(x)=x5u(x) = x^5 is u(x)=5x4u^{\prime}(x) = 5x^4.

To find the derivative of v(x)=e7xv(x) = e^{7x}, we use the chain rule of differentiation, which states that if f(x)=eu(x)f(x) = e^{u(x)}, then f(x)=eu(x)u(x)f^{\prime}(x) = e^{u(x)}u^{\prime}(x). In this case, u(x)=7xu(x) = 7x, so the derivative of v(x)=e7xv(x) = e^{7x} is v(x)=7e7xv^{\prime}(x) = 7e^{7x}.

Step 3: Apply the Product Rule

Now that we have found the derivatives of u(x)u(x) and v(x)v(x), we can apply the product rule to find the derivative of f(x)=x5e7xf(x) = x^5 e^{7x}. The product rule states that if f(x)=u(x)v(x)f(x) = u(x)v(x), then f(x)=u(x)v(x)+u(x)v(x)f^{\prime}(x) = u^{\prime}(x)v(x) + u(x)v^{\prime}(x). Therefore, the derivative of f(x)=x5e7xf(x) = x^5 e^{7x} is:

f(x)=u(x)v(x)+u(x)v(x)f^{\prime}(x) = u^{\prime}(x)v(x) + u(x)v^{\prime}(x)

f(x)=5x4e7x+x57e7xf^{\prime}(x) = 5x^4 e^{7x} + x^5 7e^{7x}

Simplifying the Derivative

We can simplify the derivative by combining like terms:

f(x)=5x4e7x+7x5e7xf^{\prime}(x) = 5x^4 e^{7x} + 7x^5 e^{7x}

f(x)=(5x4+7x5)e7xf^{\prime}(x) = (5x^4 + 7x^5) e^{7x}

Conclusion

In this article, we have differentiated the function f(x)=x5e7xf(x) = x^5 e^{7x} using the product rule of differentiation. We identified the functions u(x)u(x) and v(x)v(x), found their derivatives, and applied the product rule to find the derivative of f(x)f(x). The final derivative is f(x)=(5x4+7x5)e7xf^{\prime}(x) = (5x^4 + 7x^5) e^{7x}.

Example Use Case

The derivative of f(x)=x5e7xf(x) = x^5 e^{7x} can be used to find the maximum or minimum of the function. For example, if we want to find the maximum of f(x)f(x), we can set f(x)=0f^{\prime}(x) = 0 and solve for xx. This will give us the critical points of the function, which can be used to determine the maximum or minimum.

Code Implementation

The derivative of f(x)=x5e7xf(x) = x^5 e^{7x} can be implemented in code using a programming language such as Python or MATLAB. For example, in Python, we can use the sympy library to define the function and its derivative:

import sympy as sp

x = sp.symbols('x')

f = x**5 * sp.exp(7*x) f_prime = sp.diff(f, x)

print(f_prime)

This code will output the derivative of f(x)=x5e7xf(x) = x^5 e^{7x}, which is (5x4+7x5)e7x(5x^4 + 7x^5) e^{7x}.

Conclusion

Q: What is the product rule of differentiation?

A: The product rule of differentiation states that if we have a function of the form f(x)=u(x)v(x)f(x) = u(x)v(x), then the derivative of f(x)f(x) is given by f(x)=u(x)v(x)+u(x)v(x)f^{\prime}(x) = u^{\prime}(x)v(x) + u(x)v^{\prime}(x).

Q: How do I apply the product rule to find the derivative of f(x)=x5e7xf(x) = x^5 e^{7x}?

A: To apply the product rule, we need to identify the functions u(x)u(x) and v(x)v(x), find their derivatives, and then use the product rule formula to find the derivative of f(x)f(x). In this case, we have u(x)=x5u(x) = x^5 and v(x)=e7xv(x) = e^{7x}. We can find their derivatives using the power rule and chain rule, respectively.

Q: What is the derivative of u(x)=x5u(x) = x^5?

A: The derivative of u(x)=x5u(x) = x^5 is u(x)=5x4u^{\prime}(x) = 5x^4.

Q: What is the derivative of v(x)=e7xv(x) = e^{7x}?

A: The derivative of v(x)=e7xv(x) = e^{7x} is v(x)=7e7xv^{\prime}(x) = 7e^{7x}.

Q: How do I use the product rule to find the derivative of f(x)=x5e7xf(x) = x^5 e^{7x}?

A: To use the product rule, we need to plug in the derivatives of u(x)u(x) and v(x)v(x) into the product rule formula:

f(x)=u(x)v(x)+u(x)v(x)f^{\prime}(x) = u^{\prime}(x)v(x) + u(x)v^{\prime}(x)

f(x)=5x4e7x+x57e7xf^{\prime}(x) = 5x^4 e^{7x} + x^5 7e^{7x}

Q: Can I simplify the derivative of f(x)=x5e7xf(x) = x^5 e^{7x}?

A: Yes, we can simplify the derivative by combining like terms:

f(x)=5x4e7x+7x5e7xf^{\prime}(x) = 5x^4 e^{7x} + 7x^5 e^{7x}

f(x)=(5x4+7x5)e7xf^{\prime}(x) = (5x^4 + 7x^5) e^{7x}

Q: What is the final derivative of f(x)=x5e7xf(x) = x^5 e^{7x}?

A: The final derivative of f(x)=x5e7xf(x) = x^5 e^{7x} is f(x)=(5x4+7x5)e7xf^{\prime}(x) = (5x^4 + 7x^5) e^{7x}.

Q: How can I use the derivative of f(x)=x5e7xf(x) = x^5 e^{7x} in real-world applications?

A: The derivative of f(x)=x5e7xf(x) = x^5 e^{7x} can be used to find the maximum or minimum of the function. For example, if we want to find the maximum of f(x)f(x), we can set f(x)=0f^{\prime}(x) = 0 and solve for xx. This will give us the critical points of the function, which can be used to determine the maximum or minimum.

Q: Can I implement the derivative of f(x)=x5e7xf(x) = x^5 e^{7x} in code?

A: Yes, we can implement the derivative of f(x)=x5e7xf(x) = x^5 e^{7x} in code using a programming language such as Python or MATLAB. For example, in Python, we can use the sympy library to define the function and its derivative:

import sympy as sp

x = sp.symbols('x')

f = x**5 * sp.exp(7*x) f_prime = sp.diff(f, x)

print(f_prime)

This code will output the derivative of f(x)=x5e7xf(x) = x^5 e^{7x}, which is (5x4+7x5)e7x(5x^4 + 7x^5) e^{7x}.

Conclusion

In this Q&A article, we have discussed the product rule of differentiation and how to apply it to find the derivative of f(x)=x5e7xf(x) = x^5 e^{7x}. We have also provided examples and code implementations to illustrate the concept.