Describe How The Graph Of The Following Function Can Be Obtained From One Of The Basic Graphs:${ G(x) = -\frac{1}{3}(x-3)^2 }$1. Start With The Graph Of { Y = X^2 $}$.2. Shift It Horizontally By 3 Units To The Right.3. Vertically

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Introduction

In mathematics, graphing functions is an essential skill that helps us visualize and understand the behavior of functions. One way to graph a function is by transforming a basic graph. In this article, we will describe how to obtain the graph of the function g(x)=βˆ’13(xβˆ’3)2g(x) = -\frac{1}{3}(x-3)^2 from the basic graph of y=x2y = x^2.

Step 1: Start with the Graph of y=x2y = x^2

The graph of y=x2y = x^2 is a parabola that opens upwards. It has a minimum point at (0,0)(0, 0) and is symmetric about the y-axis. To start with this graph, we need to understand its shape and position.

Step 2: Shift the Graph Horizontally by 3 Units to the Right

To shift the graph of y=x2y = x^2 horizontally by 3 units to the right, we need to replace xx with (xβˆ’3)(x-3). This means that for every point (x,y)(x, y) on the original graph, the corresponding point on the new graph will be (xβˆ’3,y)(x-3, y). This shift will move the graph to the right by 3 units.

Step 3: Vertically Stretch the Graph

The function g(x)=βˆ’13(xβˆ’3)2g(x) = -\frac{1}{3}(x-3)^2 has a coefficient of βˆ’13-\frac{1}{3} in front of the squared term. This means that the graph will be vertically stretched by a factor of βˆ’13-\frac{1}{3}. To achieve this, we need to multiply the y-coordinate of each point on the graph by βˆ’13-\frac{1}{3}.

Combining the Transformations

Now that we have described the individual transformations, let's combine them to obtain the final graph. First, we shift the graph of y=x2y = x^2 horizontally by 3 units to the right. Then, we vertically stretch the graph by a factor of βˆ’13-\frac{1}{3}. The resulting graph will be the graph of g(x)=βˆ’13(xβˆ’3)2g(x) = -\frac{1}{3}(x-3)^2.

Visualizing the Graph

To visualize the graph of g(x)=βˆ’13(xβˆ’3)2g(x) = -\frac{1}{3}(x-3)^2, we can use a graphing calculator or software. The graph will be a parabola that opens downwards, with a maximum point at (3,0)(3, 0). The graph will be symmetric about the vertical line x=3x = 3.

Conclusion

In this article, we described how to obtain the graph of the function g(x)=βˆ’13(xβˆ’3)2g(x) = -\frac{1}{3}(x-3)^2 from the basic graph of y=x2y = x^2. We applied three transformations: shifting the graph horizontally by 3 units to the right, and vertically stretching the graph by a factor of βˆ’13-\frac{1}{3}. The resulting graph is a parabola that opens downwards, with a maximum point at (3,0)(3, 0). This example illustrates the importance of understanding the properties of basic graphs and how to transform them to obtain new graphs.

Key Takeaways

  • To graph a function, we can start with a basic graph and apply transformations.
  • Shifting a graph horizontally by cc units to the right involves replacing xx with (xβˆ’c)(x-c).
  • Vertically stretching a graph by a factor of kk involves multiplying the y-coordinate of each point by kk.
  • Combining multiple transformations can help us obtain the graph of a complex function.

Further Exploration

  • Experiment with different basic graphs and transformations to see how they can be combined to obtain new graphs.
  • Use graphing software or calculators to visualize the graphs of different functions.
  • Practice applying transformations to different functions to develop your skills in graphing.
    Frequently Asked Questions (FAQs) about Graphing Functions =============================================================

Q: What is the basic graph of y=x2y = x^2?

A: The basic graph of y=x2y = x^2 is a parabola that opens upwards. It has a minimum point at (0,0)(0, 0) and is symmetric about the y-axis.

Q: How do I shift the graph of y=x2y = x^2 horizontally by 3 units to the right?

A: To shift the graph of y=x2y = x^2 horizontally by 3 units to the right, you need to replace xx with (xβˆ’3)(x-3). This means that for every point (x,y)(x, y) on the original graph, the corresponding point on the new graph will be (xβˆ’3,y)(x-3, y).

Q: What is the effect of vertically stretching the graph of y=x2y = x^2 by a factor of βˆ’13-\frac{1}{3}?

A: Vertically stretching the graph of y=x2y = x^2 by a factor of βˆ’13-\frac{1}{3} involves multiplying the y-coordinate of each point on the graph by βˆ’13-\frac{1}{3}. This will result in a graph that is vertically compressed by a factor of βˆ’13-\frac{1}{3}.

Q: How do I combine multiple transformations to obtain the graph of a complex function?

A: To combine multiple transformations, you need to apply each transformation in the correct order. For example, if you want to shift the graph of y=x2y = x^2 horizontally by 3 units to the right and then vertically stretch it by a factor of βˆ’13-\frac{1}{3}, you need to first replace xx with (xβˆ’3)(x-3) and then multiply the y-coordinate of each point by βˆ’13-\frac{1}{3}.

Q: What is the resulting graph of g(x)=βˆ’13(xβˆ’3)2g(x) = -\frac{1}{3}(x-3)^2?

A: The resulting graph of g(x)=βˆ’13(xβˆ’3)2g(x) = -\frac{1}{3}(x-3)^2 is a parabola that opens downwards, with a maximum point at (3,0)(3, 0). The graph is symmetric about the vertical line x=3x = 3.

Q: How can I visualize the graph of a function?

A: You can visualize the graph of a function using a graphing calculator or software. These tools allow you to enter the function and see the resulting graph.

Q: What are some common transformations that can be applied to a graph?

A: Some common transformations that can be applied to a graph include:

  • Shifting the graph horizontally by cc units to the right or left
  • Shifting the graph vertically by kk units up or down
  • Rotating the graph by 90∘90^\circ clockwise or counterclockwise
  • Reflecting the graph across the x-axis or y-axis
  • Vertically stretching or compressing the graph by a factor of kk

Q: How can I practice graphing functions?

A: You can practice graphing functions by:

  • Using graphing software or calculators to visualize the graphs of different functions
  • Creating your own functions and graphing them
  • Working with a partner or tutor to practice graphing functions
  • Using online resources and tutorials to learn more about graphing functions

Q: What are some real-world applications of graphing functions?

A: Graphing functions has many real-world applications, including:

  • Modeling population growth or decline
  • Analyzing the behavior of physical systems, such as springs or pendulums
  • Optimizing business processes or supply chains
  • Predicting the behavior of complex systems, such as weather patterns or financial markets

Conclusion

Graphing functions is an essential skill that has many real-world applications. By understanding the properties of basic graphs and how to transform them, you can create complex graphs that model real-world phenomena. Whether you're working in science, engineering, or business, graphing functions is an important tool that can help you analyze and understand complex systems.