Copy And Complete The Table For The Graph 2 X − Y = 8 2x - Y = 8 2 X − Y = 8 .${ \begin{tabular}{c|c|c|c|c|c} x & -2 & -1 & 0 & 1 & 2 \ \hline y & A & -10 & B & -6 & C \ \end{tabular} }$

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Solving Linear Equations: A Step-by-Step Guide to Completing the Table

Linear equations are a fundamental concept in mathematics, and solving them is a crucial skill for students to master. In this article, we will focus on solving the linear equation 2xy=82x - y = 8 by completing a table. This approach will help us visualize the relationship between the variables xx and yy and understand how to find the values of yy for different values of xx.

Understanding the Equation

The given equation is 2xy=82x - y = 8. To solve for yy, we need to isolate the variable yy on one side of the equation. We can do this by adding yy to both sides of the equation, which gives us:

2x=y+82x = y + 8

Next, we can subtract 88 from both sides of the equation to get:

2x8=y2x - 8 = y

This equation tells us that the value of yy is equal to 2x82x - 8.

Completing the Table

Now that we have the equation y=2x8y = 2x - 8, we can use it to complete the table. We will substitute the values of xx from the table into the equation and find the corresponding values of yy.

x -2 -1 0 1 2
y A -10 B -6 C

To find the value of yy for x=2x = -2, we substitute x=2x = -2 into the equation y=2x8y = 2x - 8:

y=2(2)8y = 2(-2) - 8

Simplifying the equation, we get:

y=48y = -4 - 8

y=12y = -12

So, the value of yy for x=2x = -2 is 12-12. We can write this as:

x -2 -1 0 1 2
y -12 A B -6 C

Next, we will find the value of yy for x=1x = -1. We substitute x=1x = -1 into the equation y=2x8y = 2x - 8:

y=2(1)8y = 2(-1) - 8

Simplifying the equation, we get:

y=28y = -2 - 8

y=10y = -10

So, the value of yy for x=1x = -1 is 10-10. We can write this as:

x -2 -1 0 1 2
y -12 -10 B -6 C

Now, we will find the value of yy for x=0x = 0. We substitute x=0x = 0 into the equation y=2x8y = 2x - 8:

y=2(0)8y = 2(0) - 8

Simplifying the equation, we get:

y=08y = 0 - 8

y=8y = -8

So, the value of yy for x=0x = 0 is 8-8. We can write this as:

x -2 -1 0 1 2
y -12 -10 -8 -6 C

Next, we will find the value of yy for x=1x = 1. We substitute x=1x = 1 into the equation y=2x8y = 2x - 8:

y=2(1)8y = 2(1) - 8

Simplifying the equation, we get:

y=28y = 2 - 8

y=6y = -6

So, the value of yy for x=1x = 1 is 6-6. We can write this as:

x -2 -1 0 1 2
y -12 -10 -8 -6 C

Finally, we will find the value of yy for x=2x = 2. We substitute x=2x = 2 into the equation y=2x8y = 2x - 8:

y=2(2)8y = 2(2) - 8

Simplifying the equation, we get:

y=48y = 4 - 8

y=4y = -4

So, the value of yy for x=2x = 2 is 4-4. We can write this as:

x -2 -1 0 1 2
y -12 -10 -8 -6 -4

In this article, we solved the linear equation 2xy=82x - y = 8 by completing a table. We used the equation y=2x8y = 2x - 8 to find the values of yy for different values of xx. By substituting the values of xx into the equation, we were able to find the corresponding values of yy. This approach helped us visualize the relationship between the variables xx and yy and understand how to solve linear equations.

  • When solving linear equations, it's essential to isolate the variable on one side of the equation.
  • Use the equation y=mx+by = mx + b to find the values of yy for different values of xx.
  • Substitute the values of xx into the equation to find the corresponding values of yy.
  • Use a table to organize the values of xx and yy and make it easier to visualize the relationship between the variables.
  • Solve the linear equation x+2y=6x + 2y = 6 by completing a table.
  • Find the values of yy for x=3x = -3, x=2x = -2, x=0x = 0, x=1x = 1, and x=2x = 2.
  • Use the equation y=mx+by = mx + b to find the values of yy for different values of xx.

A: A linear equation is an equation in which the highest power of the variable(s) is 1. In other words, it is an equation that can be written in the form ax+by=cax + by = c, where aa, bb, and cc are constants, and xx and yy are variables.

A: To solve a linear equation, you need to isolate the variable(s) on one side of the equation. You can do this by adding, subtracting, multiplying, or dividing both sides of the equation by the same value.

A: The equation y=mx+by = mx + b is a linear equation in the form of a slope-intercept equation. In this equation, mm is the slope of the line, and bb is the y-intercept.

A: To find the values of yy for different values of xx, you can substitute the values of xx into the equation y=mx+by = mx + b. This will give you the corresponding values of yy.

A: A linear equation is an equation in which the highest power of the variable(s) is 1, while a quadratic equation is an equation in which the highest power of the variable(s) is 2.

A: To solve a system of linear equations, you need to find the values of the variables that satisfy all the equations in the system. You can do this by using substitution or elimination methods.

A: Solving linear equations is an essential skill in mathematics and is used in many real-world applications, such as physics, engineering, economics, and computer science.

A: Yes, here are some examples of linear equations:

  • 2x+3y=52x + 3y = 5
  • x2y=3x - 2y = 3
  • y=2x1y = 2x - 1
  • x+y=4x + y = 4

A: Yes, here are some tips for solving linear equations:

  • Make sure to isolate the variable(s) on one side of the equation.
  • Use the equation y=mx+by = mx + b to find the values of yy for different values of xx.
  • Substitute the values of xx into the equation to find the corresponding values of yy.
  • Use a table to organize the values of xx and yy and make it easier to visualize the relationship between the variables.

A: Yes, here are some practice problems for solving linear equations:

  • Solve the linear equation x+2y=6x + 2y = 6 by completing a table.
  • Find the values of yy for x=3x = -3, x=2x = -2, x=0x = 0, x=1x = 1, and x=2x = 2.
  • Use the equation y=mx+by = mx + b to find the values of yy for different values of xx.

In this article, we have discussed the basics of solving linear equations, including the equation y=mx+by = mx + b, and provided some tips and practice problems for solving linear equations. We hope that this article has been helpful in understanding the concept of solving linear equations and has provided you with the skills and confidence to solve linear equations on your own.