Consider The System Of Equations, Where \[$ K \$\] Is A Constant:$\[ \begin{aligned} \frac{6}{5} P + K Q & = \frac{4}{5} \\ q & = \frac{3}{5} P - \frac{2}{5} \end{aligned} \\]For Which Value Of \[$ K \$\] Is There No \[$( P

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Introduction

In mathematics, a system of equations is a set of two or more equations that are solved simultaneously to find the values of the variables. In this article, we will consider a system of two equations with two variables, p and q, and a constant k. Our goal is to find the value of k for which there is no solution to the system of equations.

The System of Equations

The system of equations is given by:

{ \begin{aligned} \frac{6}{5} p + k q & = \frac{4}{5} \\ q & = \frac{3}{5} p - \frac{2}{5} \end{aligned} \}

We can see that the second equation is already solved for q, so we can substitute this expression for q into the first equation.

Substitution Method

Substituting the expression for q into the first equation, we get:

{ \begin{aligned} \frac{6}{5} p + k \left( \frac{3}{5} p - \frac{2}{5} \right) & = \frac{4}{5} \\ \frac{6}{5} p + \frac{3k}{5} p - \frac{2k}{5} & = \frac{4}{5} \end{aligned} \}

Combining like terms, we get:

{ \begin{aligned} \left( \frac{6}{5} + \frac{3k}{5} \right) p - \frac{2k}{5} & = \frac{4}{5} \end{aligned} \}

Simplifying the Equation

We can simplify the equation by combining the fractions:

{ \begin{aligned} \frac{6 + 3k}{5} p - \frac{2k}{5} & = \frac{4}{5} \end{aligned} \}

Multiplying both sides of the equation by 5 to eliminate the fraction, we get:

{ \begin{aligned} (6 + 3k) p - 2k & = 4 \end{aligned} \}

Rearranging the Equation

We can rearrange the equation to isolate the term with p:

{ \begin{aligned} (6 + 3k) p & = 4 + 2k \end{aligned} \}

Dividing both sides of the equation by (6 + 3k), we get:

{ \begin{aligned} p & = \frac{4 + 2k}{6 + 3k} \end{aligned} \}

Finding the Value of k

Our goal is to find the value of k for which there is no solution to the system of equations. In other words, we want to find the value of k for which the equation has no solution.

To do this, we can set the denominator of the expression for p equal to zero:

{ \begin{aligned} 6 + 3k & = 0 \end{aligned} \}

Solving for k, we get:

{ \begin{aligned} 3k & = -6 \\ k & = -2 \end{aligned} \}

Conclusion

In this article, we considered a system of two equations with two variables, p and q, and a constant k. We used the substitution method to solve the system of equations and found the value of k for which there is no solution. The value of k is -2.

Final Answer

Introduction

In our previous article, we explored a system of two equations with two variables, p and q, and a constant k. We used the substitution method to solve the system of equations and found the value of k for which there is no solution. In this article, we will answer some frequently asked questions about solving systems of equations.

Q: What is a system of equations?

A system of equations is a set of two or more equations that are solved simultaneously to find the values of the variables.

Q: How do I know if a system of equations has a solution?

To determine if a system of equations has a solution, you can use the following methods:

  • Substitution method: Substitute the expression for one variable into the other equation.
  • Elimination method: Add or subtract the equations to eliminate one of the variables.
  • Graphing method: Graph the equations on a coordinate plane and find the point of intersection.

Q: What is the difference between a dependent and independent system of equations?

A dependent system of equations has an infinite number of solutions, while an independent system of equations has a unique solution.

Q: How do I find the value of k for which there is no solution to the system of equations?

To find the value of k for which there is no solution to the system of equations, you can set the denominator of the expression for one of the variables equal to zero and solve for k.

Q: What is the importance of solving systems of equations?

Solving systems of equations is an essential skill in mathematics and has numerous applications in various fields, including:

  • Science: Solving systems of equations is used to model real-world problems, such as the motion of objects, the behavior of populations, and the flow of fluids.
  • Engineering: Solving systems of equations is used to design and optimize systems, such as electrical circuits, mechanical systems, and computer networks.
  • Economics: Solving systems of equations is used to model economic systems, such as supply and demand, and to make predictions about economic trends.

Q: What are some common mistakes to avoid when solving systems of equations?

Some common mistakes to avoid when solving systems of equations include:

  • Not checking for extraneous solutions: Make sure to check if the solution satisfies both equations.
  • Not using the correct method: Choose the correct method for solving the system of equations, such as substitution or elimination.
  • Not simplifying the equations: Simplify the equations before solving them to avoid unnecessary complications.

Conclusion

Solving systems of equations is a fundamental skill in mathematics that has numerous applications in various fields. By understanding the concepts and methods of solving systems of equations, you can tackle complex problems and make predictions about real-world phenomena.

Final Tips

  • Practice, practice, practice: The more you practice solving systems of equations, the more comfortable you will become with the concepts and methods.
  • Use technology: Use graphing calculators or computer software to visualize and solve systems of equations.
  • Seek help: Don't hesitate to ask for help if you are struggling with a problem or concept.