Consider The Following Equation:$\[ 7x - 9y^2 = 8 \\]1. Find Two Distinct Values Of \[$ Y \$\] That Satisfy The Equation For The Same Value Of \[$ X \$\]. Enter Your Answers As A Comma-separated List. If No Such Values Exist,

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Solving the Equation: Finding Distinct Values of y for the Same Value of x

In this article, we will explore the given equation 7x−9y2=87x - 9y^2 = 8 and find two distinct values of yy that satisfy the equation for the same value of xx. This problem involves solving a quadratic equation and understanding the relationship between the variables xx and yy.

Understanding the Equation

The given equation is a quadratic equation in terms of yy, where xx is a constant. The equation can be rewritten as −9y2+7x=8-9y^2 + 7x = 8. To find the values of yy that satisfy the equation, we need to isolate yy and solve for its possible values.

Isolating y

To isolate yy, we can rearrange the equation to get −9y2=−7x+8-9y^2 = -7x + 8. Dividing both sides by −9-9, we get y2=7x−89y^2 = \frac{7x - 8}{9}.

Finding the Values of y

Now that we have isolated yy, we can find its possible values by taking the square root of both sides of the equation. This gives us y=±7x−89y = \pm \sqrt{\frac{7x - 8}{9}}.

Finding Two Distinct Values of y for the Same Value of x

To find two distinct values of yy for the same value of xx, we need to find a value of xx that satisfies the equation and has two distinct solutions for yy. Let's choose a value of xx that makes the expression inside the square root positive and equal to a perfect square.

Choosing a Value of x

Let's choose x=3x = 3. Substituting this value into the equation, we get y2=7(3)−89=21−89=139y^2 = \frac{7(3) - 8}{9} = \frac{21 - 8}{9} = \frac{13}{9}. This is not a perfect square, so we need to choose a different value of xx.

Choosing Another Value of x

Let's choose x=4x = 4. Substituting this value into the equation, we get y2=7(4)−89=28−89=209y^2 = \frac{7(4) - 8}{9} = \frac{28 - 8}{9} = \frac{20}{9}. This is also not a perfect square, so we need to choose another value of xx.

Choosing a Value of x that Makes the Expression Inside the Square Root a Perfect Square

Let's choose x=5x = 5. Substituting this value into the equation, we get y2=7(5)−89=35−89=279=3y^2 = \frac{7(5) - 8}{9} = \frac{35 - 8}{9} = \frac{27}{9} = 3. This is a perfect square, so we have found a value of xx that satisfies the equation and has two distinct solutions for yy.

Finding the Values of y for x = 5

Now that we have found a value of xx that satisfies the equation and has two distinct solutions for yy, we can find the values of yy by taking the square root of both sides of the equation. This gives us y=±3y = \pm \sqrt{3}.

Conclusion

In this article, we have explored the given equation 7x−9y2=87x - 9y^2 = 8 and found two distinct values of yy that satisfy the equation for the same value of xx. We have chosen a value of xx that makes the expression inside the square root a perfect square and found the values of yy by taking the square root of both sides of the equation. The two distinct values of yy are 3\sqrt{3} and −3-\sqrt{3}.

Final Answer

In our previous article, we explored the equation 7x−9y2=87x - 9y^2 = 8 and found two distinct values of yy that satisfy the equation for the same value of xx. In this article, we will answer some frequently asked questions about the equation and provide additional insights into solving quadratic equations.

Q: What is the main difference between this equation and a standard quadratic equation? A: The main difference between this equation and a standard quadratic equation is that this equation has a variable xx that is not squared. In a standard quadratic equation, both variables are squared.

Q: How do I choose a value of xx that makes the expression inside the square root a perfect square? A: To choose a value of xx that makes the expression inside the square root a perfect square, you need to find a value of xx that makes the numerator of the expression a perfect square. You can do this by trial and error or by using algebraic manipulations.

Q: What if I choose a value of xx that does not make the expression inside the square root a perfect square? A: If you choose a value of xx that does not make the expression inside the square root a perfect square, you will not be able to find two distinct values of yy that satisfy the equation for the same value of xx. In this case, you need to choose a different value of xx.

Q: Can I use the quadratic formula to solve this equation? A: Yes, you can use the quadratic formula to solve this equation. The quadratic formula is y=−b±b2−4ac2ay = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}. In this case, a=−9a = -9, b=0b = 0, and c=7x−8c = 7x - 8. Plugging these values into the quadratic formula, you get y=0±0−4(−9)(7x−8)2(−9)=0±252−288x−18y = \frac{0 \pm \sqrt{0 - 4(-9)(7x - 8)}}{2(-9)} = \frac{0 \pm \sqrt{252 - 288x}}{-18}.

Q: How do I simplify the expression inside the square root? A: To simplify the expression inside the square root, you need to find a value of xx that makes the expression a perfect square. You can do this by trial and error or by using algebraic manipulations.

Q: Can I use a calculator to solve this equation? A: Yes, you can use a calculator to solve this equation. However, you need to be careful when using a calculator to solve quadratic equations, as it may not always give you the correct solution.

Conclusion

In this article, we have answered some frequently asked questions about the equation 7x−9y2=87x - 9y^2 = 8 and provided additional insights into solving quadratic equations. We have also discussed how to choose a value of xx that makes the expression inside the square root a perfect square and how to simplify the expression inside the square root.

Final Tips

  • When solving quadratic equations, make sure to choose a value of xx that makes the expression inside the square root a perfect square.
  • Use algebraic manipulations to simplify the expression inside the square root.
  • Be careful when using a calculator to solve quadratic equations, as it may not always give you the correct solution.

Additional Resources

  • For more information on solving quadratic equations, see our previous article on the topic.
  • For more information on algebraic manipulations, see our article on algebraic manipulations.
  • For more information on using calculators to solve quadratic equations, see our article on using calculators to solve quadratic equations.