Consider The Following Balanced Chemical Equation:$\[ 4 \text{Fe} + 3 \text{O}_2 \rightarrow 2 \text{Fe}_2\text{O}_3 \\]How Many Grams Of \[$\text{Fe}_2\text{O}_3\$\] Can Be Formed From 125.5 Grams Of Fe?A. 59.8 Grams B. 179.4 Grams
Understanding the Balanced Chemical Equation
A balanced chemical equation is a representation of a chemical reaction where the number of atoms for each element is the same on both the reactant and product sides. The given balanced chemical equation is:
This equation indicates that 4 moles of iron (Fe) react with 3 moles of oxygen (O2) to produce 2 moles of iron(III) oxide (Fe2O3).
Calculating Molar Mass
To solve this problem, we need to calculate the molar mass of iron (Fe) and iron(III) oxide (Fe2O3). The atomic masses of iron and oxygen are:
- Iron (Fe): 55.85 g/mol
- Oxygen (O): 16.00 g/mol
The molar mass of iron(III) oxide (Fe2O3) can be calculated as follows:
Molar mass of Fe2O3 = (2 x 55.85 g/mol) + (3 x 16.00 g/mol) Molar mass of Fe2O3 = 111.70 g/mol + 48.00 g/mol Molar mass of Fe2O3 = 159.70 g/mol
Calculating the Number of Moles of Iron
Given that we have 125.5 grams of iron (Fe), we can calculate the number of moles of iron as follows:
Number of moles of Fe = mass of Fe / molar mass of Fe Number of moles of Fe = 125.5 g / 55.85 g/mol Number of moles of Fe = 2.25 mol
Determining the Limiting Reactant
To determine the limiting reactant, we need to compare the mole ratio of iron (Fe) to oxygen (O2) in the balanced chemical equation with the given amounts of iron and oxygen.
The balanced chemical equation indicates that 4 moles of iron (Fe) react with 3 moles of oxygen (O2). We can calculate the number of moles of oxygen required to react with 2.25 moles of iron as follows:
Number of moles of O2 required = (3/4) x number of moles of Fe Number of moles of O2 required = (3/4) x 2.25 mol Number of moles of O2 required = 1.6875 mol
Since we are not given the amount of oxygen, we will assume that oxygen is in excess and iron is the limiting reactant.
Calculating the Number of Moles of Iron(III) Oxide
Since iron is the limiting reactant, we can calculate the number of moles of iron(III) oxide (Fe2O3) produced as follows:
Number of moles of Fe2O3 = (1/2) x number of moles of Fe Number of moles of Fe2O3 = (1/2) x 2.25 mol Number of moles of Fe2O3 = 1.125 mol
Calculating the Mass of Iron(III) Oxide
We can calculate the mass of iron(III) oxide (Fe2O3) produced as follows:
Mass of Fe2O3 = number of moles of Fe2O3 x molar mass of Fe2O3 Mass of Fe2O3 = 1.125 mol x 159.70 g/mol Mass of Fe2O3 = 179.4 g
Therefore, the mass of iron(III) oxide (Fe2O3) that can be formed from 125.5 grams of iron (Fe) is 179.4 grams.
Conclusion
Q: What is a balanced chemical equation?
A: A balanced chemical equation is a representation of a chemical reaction where the number of atoms for each element is the same on both the reactant and product sides.
Q: How do I determine the limiting reactant in a chemical reaction?
A: To determine the limiting reactant, you need to compare the mole ratio of the reactants in the balanced chemical equation with the given amounts of the reactants. The reactant that is consumed first is the limiting reactant.
Q: What is the difference between a mole and a gram?
A: A mole is a unit of measurement that represents 6.022 x 10^23 particles (atoms or molecules), while a gram is a unit of mass. The molar mass of a substance is the mass of one mole of that substance.
Q: How do I calculate the molar mass of a compound?
A: To calculate the molar mass of a compound, you need to add up the atomic masses of all the atoms in the compound. For example, the molar mass of water (H2O) is 2 x 1.008 g/mol (for hydrogen) + 16.00 g/mol (for oxygen) = 18.016 g/mol.
Q: What is the significance of the balanced chemical equation in a chemical reaction?
A: The balanced chemical equation is a representation of the chemical reaction that shows the reactants and products, as well as the stoichiometry of the reaction. It is essential in calculating the amount of product formed from a given amount of reactant.
Q: How do I calculate the mass of a product formed from a given amount of reactant?
A: To calculate the mass of a product formed from a given amount of reactant, you need to follow these steps:
- Calculate the number of moles of the reactant.
- Use the mole ratio from the balanced chemical equation to calculate the number of moles of the product.
- Calculate the mass of the product using the number of moles and the molar mass of the product.
Q: What is the difference between a reactant and a product in a chemical reaction?
A: A reactant is a substance that is consumed in a chemical reaction, while a product is a substance that is formed in a chemical reaction.
Q: How do I determine the type of chemical reaction (synthesis, decomposition, single displacement, double displacement, etc.)?
A: To determine the type of chemical reaction, you need to examine the reactants and products in the balanced chemical equation. The type of reaction can be determined by the number of reactants and products, as well as the type of bonds formed or broken.
Q: What is the significance of the molar mass in a chemical reaction?
A: The molar mass is a critical concept in chemistry that relates the mass of a substance to the number of moles of that substance. It is essential in calculating the amount of product formed from a given amount of reactant.
Q: How do I calculate the number of moles of a substance from a given mass?
A: To calculate the number of moles of a substance from a given mass, you need to divide the mass of the substance by its molar mass.
Q: What is the difference between a mole and a mole fraction?
A: A mole is a unit of measurement that represents 6.022 x 10^23 particles (atoms or molecules), while a mole fraction is the ratio of the number of moles of a substance to the total number of moles of all substances in a mixture.
Q: How do I calculate the mole fraction of a substance in a mixture?
A: To calculate the mole fraction of a substance in a mixture, you need to divide the number of moles of the substance by the total number of moles of all substances in the mixture.
Conclusion
In this Q&A article, we have covered various topics related to balanced chemical equations and molar mass calculations. We have discussed the significance of balanced chemical equations, the difference between a mole and a gram, and how to calculate the molar mass of a compound. We have also covered topics such as determining the limiting reactant, calculating the mass of a product formed from a given amount of reactant, and determining the type of chemical reaction.