Consider A Circle Whose Equation Is X 2 + Y 2 − 2 X − 8 = 0 X^2 + Y^2 - 2x - 8 = 0 X 2 + Y 2 − 2 X − 8 = 0 . Which Statements Are True? Select Three Options.A. The Radius Of The Circle Is 3 Units. B. The Center Of The Circle Lies On The X X X -axis. C. The Center Of The Circle Lies

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In mathematics, the equation of a circle is a fundamental concept that is used to describe the shape and position of a circle in a two-dimensional plane. The general equation of a circle is given by (xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2, where (h,k)(h, k) represents the coordinates of the center of the circle and rr represents the radius of the circle.

Given Equation: x2+y22x8=0x^2 + y^2 - 2x - 8 = 0

The given equation is x2+y22x8=0x^2 + y^2 - 2x - 8 = 0. To understand the properties of this circle, we need to rewrite the equation in the standard form of a circle. We can do this by completing the square for both the xx and yy terms.

Completing the Square

To complete the square for the xx term, we need to add (2/2)2=1(2/2)^2 = 1 to both sides of the equation. Similarly, to complete the square for the yy term, we need to add (0/2)2=0(0/2)^2 = 0 to both sides of the equation.

x^2 - 2x + 1 + y^2 - 8 = 1

Now, we can rewrite the equation as:

(x - 1)^2 + y^2 = 9

Understanding the Standard Form

The standard form of a circle is (xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2, where (h,k)(h, k) represents the coordinates of the center of the circle and rr represents the radius of the circle. Comparing this with the given equation, we can see that the center of the circle is at (1,0)(1, 0) and the radius of the circle is 9=3\sqrt{9} = 3 units.

Analyzing the Options

Now, let's analyze the given options:

A. The radius of the circle is 3 units.

This statement is true, as we have already determined that the radius of the circle is 3 units.

B. The center of the circle lies on the xx-axis.

This statement is false, as the center of the circle is at (1,0)(1, 0), which lies on the yy-axis, not the xx-axis.

C. The center of the circle lies on the yy-axis.

This statement is false, as the center of the circle is at (1,0)(1, 0), which lies on the xx-axis, not the yy-axis.

Conclusion

In conclusion, the correct statements are:

  • The radius of the circle is 3 units.
  • The center of the circle lies on the xx-axis (this is incorrect, the center lies on the y-axis).

In the previous article, we discussed the equation of a circle and how to rewrite it in the standard form. We also analyzed the given options and determined that the radius of the circle is 3 units. In this article, we will answer some frequently asked questions about the equation of a circle.

Q: What is the general equation of a circle?

A: The general equation of a circle is given by (xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2, where (h,k)(h, k) represents the coordinates of the center of the circle and rr represents the radius of the circle.

Q: How do I rewrite the equation of a circle in the standard form?

A: To rewrite the equation of a circle in the standard form, you need to complete the square for both the xx and yy terms. This involves adding and subtracting the same value to both sides of the equation.

Q: What is the significance of the center of the circle?

A: The center of the circle is the point around which the circle is centered. It is represented by the coordinates (h,k)(h, k) in the general equation of a circle.

Q: How do I find the radius of the circle?

A: To find the radius of the circle, you need to take the square root of the value on the right-hand side of the equation. In the standard form of a circle, the radius is represented by rr.

Q: Can a circle have a negative radius?

A: No, a circle cannot have a negative radius. The radius of a circle is always a positive value.

Q: Can a circle have a zero radius?

A: No, a circle cannot have a zero radius. A circle with a zero radius would be a point, not a circle.

Q: How do I graph a circle?

A: To graph a circle, you need to plot the center of the circle and then draw a circle with the given radius.

Q: What is the equation of a circle with a center at (0,0)(0, 0) and a radius of 5 units?

A: The equation of a circle with a center at (0,0)(0, 0) and a radius of 5 units is x2+y2=25x^2 + y^2 = 25.

Q: What is the equation of a circle with a center at (3,4)(3, 4) and a radius of 2 units?

A: The equation of a circle with a center at (3,4)(3, 4) and a radius of 2 units is (x3)2+(y4)2=4(x - 3)^2 + (y - 4)^2 = 4.

Conclusion

In conclusion, the equation of a circle is a fundamental concept in mathematics that is used to describe the shape and position of a circle in a two-dimensional plane. We have discussed the general equation of a circle, how to rewrite it in the standard form, and answered some frequently asked questions about the equation of a circle.