Coefficients Of Powers Of Partial Sums Of The Geometric Series

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Introduction


The geometric series is a fundamental concept in mathematics, and its partial sums have been extensively studied in various fields, including algebraic geometry, combinatorics, and commutative algebra. In this article, we will focus on computing or bounding from above the coefficients of powers of partial sums of the geometric series. This problem has significant implications in various areas of mathematics and computer science.

Background


The geometric series is a well-known infinite series in mathematics, given by the formula:

βˆ‘k=0∞tk=11βˆ’t\sum_{k=0}^{\infty} t^k = \frac{1}{1-t}

This series converges for ∣t∣<1|t| < 1. The partial sums of the geometric series are given by:

βˆ‘k=0dtk=1βˆ’td+11βˆ’t\sum_{k=0}^{d} t^k = \frac{1-t^{d+1}}{1-t}

We are interested in computing or bounding from above the coefficients of powers of partial sums of the geometric series, i.e., the coefficients of the following polynomial:

(βˆ‘k=0dtk)n=(1βˆ’td+1)n(1βˆ’t)n(\sum_{k=0}^{d} t^k)^n = \frac{(1-t^{d+1})^n}{(1-t)^n}

Computing Coefficients


Computing the coefficients of the above polynomial directly is challenging, as it involves expanding the numerator and denominator. However, we can use the following approach to bound the coefficients from above.

Bounding Coefficients


We can use the following inequality to bound the coefficients from above:

(1βˆ’td+1)n≀(1βˆ’t)n+n(1βˆ’t)nβˆ’1td+1(1-t^{d+1})^n \leq (1-t)^n + n(1-t)^{n-1}t^{d+1}

This inequality follows from the binomial theorem. Using this inequality, we can bound the coefficients of the polynomial from above as follows:

(1βˆ’td+1)n(1βˆ’t)n≀1+ntd+11βˆ’t\frac{(1-t^{d+1})^n}{(1-t)^n} \leq 1 + n\frac{t^{d+1}}{1-t}

Simplifying the Bound


We can simplify the bound further by using the following inequality:

td+11βˆ’t≀td+11βˆ’td+1\frac{t^{d+1}}{1-t} \leq \frac{t^{d+1}}{1-t^{d+1}}

This inequality follows from the fact that 1βˆ’td+1≀1βˆ’t1-t^{d+1} \leq 1-t. Using this inequality, we can simplify the bound as follows:

1+ntd+11βˆ’t≀1+ntd+11βˆ’td+11 + n\frac{t^{d+1}}{1-t} \leq 1 + n\frac{t^{d+1}}{1-t^{d+1}}

Conclusion


In this article, we have discussed the problem of computing or bounding from above the coefficients of powers of partial sums of the geometric series. We have used the following approach to bound the coefficients from above:

  1. We have used the binomial theorem to expand the numerator and denominator of the polynomial.
  2. We have used the inequality (1βˆ’td+1)n≀(1βˆ’t)n+n(1βˆ’t)nβˆ’1td+1(1-t^{d+1})^n \leq (1-t)^n + n(1-t)^{n-1}t^{d+1} to bound the coefficients from above.
  3. We have simplified the bound further using the inequality td+11βˆ’t≀td+11βˆ’td+1\frac{t^{d+1}}{1-t} \leq \frac{t^{d+1}}{1-t^{d+1}}.

The bound we have obtained is:

1+ntd+11βˆ’td+11 + n\frac{t^{d+1}}{1-t^{d+1}}

This bound is useful in various areas of mathematics and computer science, including algebraic geometry, combinatorics, and commutative algebra.

Future Work


There are several directions for future work on this problem. Some possible directions include:

  • Improving the bound: We can try to improve the bound by using more sophisticated inequalities or by using different approaches to bound the coefficients.
  • Computing the coefficients: We can try to compute the coefficients of the polynomial directly using different methods, such as generating functions or algebraic geometry.
  • Applying the bound: We can try to apply the bound to specific problems in mathematics and computer science, such as counting the number of solutions to a system of equations or computing the volume of a polytope.

References


  • [1] Stanley, R. P. (1997). Enumerative Combinatorics. Cambridge University Press.
  • [2] Macdonald, I. G. (1995). Symmetric Functions and Hall Polynomials. Oxford University Press.
  • [3] Eisenbud, D. (1995). Commutative Algebra. Springer-Verlag.

Code


The following code can be used to compute the bound:

import sympy as sp

def compute_bound(n, d, t): # Compute the bound bound = 1 + n * (t ** (d + 1)) / (1 - t ** (d + 1)) return bound

n = 5 d = 3 t = sp.symbols('t') bound = compute_bound(n, d, t) print(bound)

This code uses the SymPy library to compute the bound. The compute_bound function takes three arguments: n, d, and t. The function returns the bound, which is a polynomial in t. The example usage shows how to use the function to compute the bound for specific values of n, d, and t.

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Introduction


In our previous article, we discussed the problem of computing or bounding from above the coefficients of powers of partial sums of the geometric series. We used the binomial theorem to expand the numerator and denominator of the polynomial and obtained a bound on the coefficients. In this article, we will answer some frequently asked questions (FAQs) related to this problem.

Q&A


Q: What is the geometric series?

A: The geometric series is a well-known infinite series in mathematics, given by the formula:

βˆ‘k=0∞tk=11βˆ’t\sum_{k=0}^{\infty} t^k = \frac{1}{1-t}

This series converges for ∣t∣<1|t| < 1.

Q: What are the partial sums of the geometric series?

A: The partial sums of the geometric series are given by:

βˆ‘k=0dtk=1βˆ’td+11βˆ’t\sum_{k=0}^{d} t^k = \frac{1-t^{d+1}}{1-t}

Q: How do we compute the coefficients of powers of partial sums of the geometric series?

A: We can use the binomial theorem to expand the numerator and denominator of the polynomial and obtain a bound on the coefficients.

Q: What is the bound on the coefficients?

A: The bound on the coefficients is given by:

1+ntd+11βˆ’td+11 + n\frac{t^{d+1}}{1-t^{d+1}}

Q: How do we simplify the bound?

A: We can simplify the bound further by using the inequality td+11βˆ’t≀td+11βˆ’td+1\frac{t^{d+1}}{1-t} \leq \frac{t^{d+1}}{1-t^{d+1}}.

Q: What are some possible directions for future work on this problem?

A: Some possible directions for future work on this problem include:

  • Improving the bound: We can try to improve the bound by using more sophisticated inequalities or by using different approaches to bound the coefficients.
  • Computing the coefficients: We can try to compute the coefficients of the polynomial directly using different methods, such as generating functions or algebraic geometry.
  • Applying the bound: We can try to apply the bound to specific problems in mathematics and computer science, such as counting the number of solutions to a system of equations or computing the volume of a polytope.

Q: What are some references for further reading on this topic?

A: Some references for further reading on this topic include:

  • [1] Stanley, R. P. (1997). Enumerative Combinatorics. Cambridge University Press.
  • [2] Macdonald, I. G. (1995). Symmetric Functions and Hall Polynomials. Oxford University Press.
  • [3] Eisenbud, D. (1995). Commutative Algebra. Springer-Verlag.

Q: How do we implement the bound in code?

A: The following code can be used to compute the bound:

import sympy as sp

def compute_bound(n, d, t): # Compute the bound bound = 1 + n * (t ** (d + 1)) / (1 - t ** (d + 1)) return bound

n = 5 d = 3 t = sp.symbols('t') bound = compute_bound(n, d, t) print(bound)

This code uses the SymPy library to compute the bound. The compute_bound function takes three arguments: n, d, and t. The function returns the bound, which is a polynomial in t. The example usage shows how to use the function to compute the bound for specific values of n, d, and t.

Conclusion


In this article, we have answered some frequently asked questions related to the problem of computing or bounding from above the coefficients of powers of partial sums of the geometric series. We have used the binomial theorem to expand the numerator and denominator of the polynomial and obtained a bound on the coefficients. We have also provided some possible directions for future work on this problem and some references for further reading on this topic.