Calculate The Molar Concentration Of O H − OH^{-} O H − Ions In A 0.583 M Solution Of Hypobromite Ion ( B R O − ; K B = 4.0 × 10 − 6 (BrO^{-}; \, K_{b}=4.0 \times 10^{-6} ( B R O − ; K B ​ = 4.0 × 1 0 − 6 ].Express The Molarity To Two Significant Figures. [ O H − ] = □ M \left[ OH^{-} \right]= \square \, M [ O H − ] = □ M

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Introduction

In chemistry, understanding the molar concentration of ions in a solution is crucial for various applications, including chemical reactions and equilibrium calculations. In this article, we will calculate the molar concentration of OHOH^{-} ions in a 0.583 M solution of hypobromite ion (BrO)(BrO^{-}) with a given base dissociation constant (KbK_{b}) of 4.0×1064.0 \times 10^{-6}.

Understanding the Problem

The hypobromite ion (BrO)(BrO^{-}) is a weak base that partially dissociates in water to produce OHOH^{-} ions and BrO2BrO_{2}^{-} ions. The base dissociation constant (KbK_{b}) is a measure of the strength of the base and is given by the equation:

Kb=[BrO2][OH][BrO]K_{b} = \frac{[BrO_{2}^{-}][OH^{-}]}{[BrO^{-}]}

We are given the initial concentration of hypobromite ion (BrO)(BrO^{-}) as 0.583 M and the base dissociation constant (KbK_{b}) as 4.0×1064.0 \times 10^{-6}. We need to calculate the molar concentration of OHOH^{-} ions in the solution.

Calculating the Molar Concentration of OHOH^{-} Ions

To calculate the molar concentration of OHOH^{-} ions, we can use the base dissociation constant (KbK_{b}) equation. Since the hypobromite ion (BrO)(BrO^{-}) is a weak base, we can assume that the concentration of BrO2BrO_{2}^{-} ions is equal to the concentration of OHOH^{-} ions. Let's denote the concentration of OHOH^{-} ions as xx.

We can rewrite the base dissociation constant (KbK_{b}) equation as:

4.0×106=x20.5834.0 \times 10^{-6} = \frac{x^{2}}{0.583}

Simplifying the equation, we get:

x2=2.32×106x^{2} = 2.32 \times 10^{-6}

Taking the square root of both sides, we get:

x=2.32×106x = \sqrt{2.32 \times 10^{-6}}

Evaluating the square root, we get:

x=1.53×103x = 1.53 \times 10^{-3}

Therefore, the molar concentration of OHOH^{-} ions in the solution is 1.53×1031.53 \times 10^{-3} M.

Expressing the Molarity to Two Significant Figures

To express the molarity to two significant figures, we can round the value to the nearest hundredth. Therefore, the molar concentration of OHOH^{-} ions in the solution is approximately 1.5×1031.5 \times 10^{-3} M.

Conclusion

In this article, we calculated the molar concentration of OHOH^{-} ions in a 0.583 M solution of hypobromite ion (BrO)(BrO^{-}) with a given base dissociation constant (KbK_{b}) of 4.0×1064.0 \times 10^{-6}. We used the base dissociation constant (KbK_{b}) equation to calculate the molar concentration of OHOH^{-} ions and expressed the molarity to two significant figures. The molar concentration of OHOH^{-} ions in the solution is approximately 1.5×1031.5 \times 10^{-3} M.

References

  • [1] Atkins, P. W., & De Paula, J. (2010). Physical chemistry (9th ed.). Oxford University Press.
  • [2] Brown, T. L., LeMay, H. E., Bursten, B. E., & Murphy, C. (2012). Chemistry: The Central Science (13th ed.). Pearson Education.

Additional Resources

Table of Contents

  1. Introduction
  2. Understanding the Problem
  3. Calculating the Molar Concentration of OHOH^{-} Ions
  4. Expressing the Molarity to Two Significant Figures
  5. Conclusion
  6. References
  7. Additional Resources
  8. Table of Contents
    Q&A: Calculating Molar Concentration of OHOH^{-} Ions in a Hypobromite Solution ====================================================================================

Introduction

In our previous article, we calculated the molar concentration of OHOH^{-} ions in a 0.583 M solution of hypobromite ion (BrO)(BrO^{-}) with a given base dissociation constant (KbK_{b}) of 4.0×1064.0 \times 10^{-6}. In this article, we will answer some frequently asked questions related to the calculation of molar concentration of OHOH^{-} ions in a hypobromite solution.

Q: What is the base dissociation constant (KbK_{b}) and how is it related to the molar concentration of OHOH^{-} ions?

A: The base dissociation constant (KbK_{b}) is a measure of the strength of a base and is related to the molar concentration of OHOH^{-} ions. It is defined as the ratio of the concentrations of the conjugate base and the hydroxide ion to the concentration of the base.

Q: How do I calculate the molar concentration of OHOH^{-} ions in a hypobromite solution?

A: To calculate the molar concentration of OHOH^{-} ions in a hypobromite solution, you can use the base dissociation constant (KbK_{b}) equation. The equation is:

Kb=[BrO2][OH][BrO]K_{b} = \frac{[BrO_{2}^{-}][OH^{-}]}{[BrO^{-}]}

You can rearrange the equation to solve for the molar concentration of OHOH^{-} ions.

Q: What is the significance of expressing the molarity to two significant figures?

A: Expressing the molarity to two significant figures is important because it provides a more accurate representation of the molar concentration of OHOH^{-} ions. It also helps to avoid rounding errors and ensures that the calculated value is consistent with the given data.

Q: Can I use the base dissociation constant (KbK_{b}) equation to calculate the molar concentration of OHOH^{-} ions in any base?

A: Yes, you can use the base dissociation constant (KbK_{b}) equation to calculate the molar concentration of OHOH^{-} ions in any base. However, you need to ensure that the base dissociation constant (KbK_{b}) is given and that the equation is applicable to the specific base.

Q: What are some common sources of error when calculating the molar concentration of OHOH^{-} ions?

A: Some common sources of error when calculating the molar concentration of OHOH^{-} ions include:

  • Incorrect values for the base dissociation constant (KbK_{b})
  • Incorrect values for the initial concentration of the base
  • Incorrect units for the concentrations
  • Rounding errors

Q: How can I verify the accuracy of my calculated value for the molar concentration of OHOH^{-} ions?

A: You can verify the accuracy of your calculated value for the molar concentration of OHOH^{-} ions by:

  • Checking the units of the concentrations
  • Verifying that the base dissociation constant (KbK_{b}) is given and applicable to the specific base
  • Using a calculator or computer program to perform the calculations
  • Comparing your calculated value with the expected value

Conclusion

In this article, we answered some frequently asked questions related to the calculation of molar concentration of OHOH^{-} ions in a hypobromite solution. We provided explanations and examples to help clarify the concepts and procedures involved in calculating the molar concentration of OHOH^{-} ions.

References

  • [1] Atkins, P. W., & De Paula, J. (2010). Physical chemistry (9th ed.). Oxford University Press.
  • [2] Brown, T. L., LeMay, H. E., Bursten, B. E., & Murphy, C. (2012). Chemistry: The Central Science (13th ed.). Pearson Education.

Additional Resources

Table of Contents

  1. Introduction
  2. Q: What is the base dissociation constant (KbK_{b}) and how is it related to the molar concentration of OHOH^{-} ions?
  3. Q: How do I calculate the molar concentration of OHOH^{-} ions in a hypobromite solution?
  4. Q: What is the significance of expressing the molarity to two significant figures?
  5. Q: Can I use the base dissociation constant (KbK_{b}) equation to calculate the molar concentration of OHOH^{-} ions in any base?
  6. Q: What are some common sources of error when calculating the molar concentration of OHOH^{-} ions?
  7. Q: How can I verify the accuracy of my calculated value for the molar concentration of OHOH^{-} ions?
  8. Conclusion
  9. References
  10. Additional Resources
  11. Table of Contents