Calculate How Much Of 0.8 M Working Solution Could Be Made From 12 Ml Of 6 M Glucose Solution
Introduction
In chemistry, diluting a solution involves mixing a concentrated solution with a solvent to achieve a desired concentration. This process is crucial in various applications, including laboratory experiments, pharmaceuticals, and food processing. In this article, we will explore how to calculate the amount of a working solution that can be made from a concentrated glucose solution.
Understanding Concentration
Concentration is a measure of the amount of solute present in a solution. It can be expressed in various units, including molarity (M), molality (m), and percentage (%). In this article, we will focus on molarity, which is defined as the number of moles of solute per liter of solution.
Given Information
We are given a 6 M glucose solution, which means that there are 6 moles of glucose per liter of solution. We want to dilute this solution to a working solution with a concentration of 0.8 M. We are also given a volume of 12 ml of the 6 M glucose solution.
Calculating the Number of Moles
To calculate the number of moles of glucose in the 12 ml of 6 M solution, we can use the formula:
Number of moles = Molarity x Volume (in liters)
In this case, the volume is 12 ml, which is equivalent to 0.012 liters (since 1 liter = 1000 ml).
Number of moles = 6 M x 0.012 L = 0.072 moles
Calculating the Volume of the Working Solution
Now that we know the number of moles of glucose, we can calculate the volume of the working solution that can be made. We want to achieve a concentration of 0.8 M, which means that the number of moles of glucose per liter of solution should be 0.8.
Let's call the volume of the working solution "V" liters. We can set up the following equation:
Number of moles = Molarity x Volume
In this case, the number of moles is 0.072 moles (which we calculated earlier), and the molarity is 0.8 M.
0.072 moles = 0.8 M x V
To solve for V, we can divide both sides of the equation by 0.8 M:
V = 0.072 moles / 0.8 M
V = 0.09 liters
Converting the Volume to Milliliters
Since we are working with a volume of 0.09 liters, we can convert this to milliliters by multiplying by 1000 (since 1 liter = 1000 ml):
0.09 L x 1000 ml/L = 90 ml
Conclusion
In this article, we calculated the amount of a working solution that can be made from 12 ml of a 6 M glucose solution. We first calculated the number of moles of glucose in the 12 ml of 6 M solution, and then used this value to calculate the volume of the working solution that can be made. The result is a working solution with a concentration of 0.8 M and a volume of 90 ml.
Understanding Concentration
Concentration is a measure of the amount of solute present in a solution. It can be expressed in various units, including molarity (M), molality (m), and percentage (%). In this article, we will focus on molarity, which is defined as the number of moles of solute per liter of solution.
Calculating Concentration
To calculate the concentration of a solution, we can use the following formula:
Concentration = Number of moles / Volume (in liters)
For example, if we have a solution with 2 moles of glucose and a volume of 1 liter, the concentration would be:
Concentration = 2 moles / 1 L = 2 M
Calculating the Number of Moles
To calculate the number of moles of glucose in the 12 ml of 6 M solution, we can use the formula:
Number of moles = Molarity x Volume (in liters)
In this case, the volume is 12 ml, which is equivalent to 0.012 liters (since 1 liter = 1000 ml).
Number of moles = 6 M x 0.012 L = 0.072 moles
Calculating the Volume of the Working Solution
Now that we know the number of moles of glucose, we can calculate the volume of the working solution that can be made. We want to achieve a concentration of 0.8 M, which means that the number of moles of glucose per liter of solution should be 0.8.
Let's call the volume of the working solution "V" liters. We can set up the following equation:
Number of moles = Molarity x Volume
In this case, the number of moles is 0.072 moles (which we calculated earlier), and the molarity is 0.8 M.
0.072 moles = 0.8 M x V
To solve for V, we can divide both sides of the equation by 0.8 M:
V = 0.072 moles / 0.8 M
V = 0.09 liters
Converting the Volume to Milliliters
Since we are working with a volume of 0.09 liters, we can convert this to milliliters by multiplying by 1000 (since 1 liter = 1000 ml):
0.09 L x 1000 ml/L = 90 ml
Conclusion
In this article, we calculated the amount of a working solution that can be made from 12 ml of a 6 M glucose solution. We first calculated the number of moles of glucose in the 12 ml of 6 M solution, and then used this value to calculate the volume of the working solution that can be made. The result is a working solution with a concentration of 0.8 M and a volume of 90 ml.
Calculating Concentration: A Step-by-Step Guide to Diluting a Glucose Solution
Understanding Concentration
Concentration is a measure of the amount of solute present in a solution. It can be expressed in various units, including molarity (M), molality (m), and percentage (%). In this article, we will focus on molarity, which is defined as the number of moles of solute per liter of solution.
Calculating Concentration
To calculate the concentration of a solution, we can use the following formula:
Concentration = Number of moles / Volume (in liters)
For example, if we have a solution with 2 moles of glucose and a volume of 1 liter, the concentration would be:
Concentration = 2 moles / 1 L = 2 M
Calculating the Number of Moles
To calculate the number of moles of glucose in the 12 ml of 6 M solution, we can use the formula:
Number of moles = Molarity x Volume (in liters)
In this case, the volume is 12 ml, which is equivalent to 0.012 liters (since 1 liter = 1000 ml).
Number of moles = 6 M x 0.012 L = 0.072 moles
Calculating the Volume of the Working Solution
Now that we know the number of moles of glucose, we can calculate the volume of the working solution that can be made. We want to achieve a concentration of 0.8 M, which means that the number of moles of glucose per liter of solution should be 0.8.
Let's call the volume of the working solution "V" liters. We can set up the following equation:
Number of moles = Molarity x Volume
In this case, the number of moles is 0.072 moles (which we calculated earlier), and the molarity is 0.8 M.
0.072 moles = 0.8 M x V
To solve for V, we can divide both sides of the equation by 0.8 M:
V = 0.072 moles / 0.8 M
V = 0.09 liters
Converting the Volume to Milliliters
Since we are working with a volume of 0.09 liters, we can convert this to milliliters by multiplying by 1000 (since 1 liter = 1000 ml):
0.09 L x 1000 ml/L = 90 ml
Conclusion
Q&A: Calculating Concentration
Q: What is concentration, and why is it important in chemistry? A: Concentration is a measure of the amount of solute present in a solution. It is an important concept in chemistry because it helps us understand the properties and behavior of solutions. Concentration is crucial in various applications, including laboratory experiments, pharmaceuticals, and food processing.
Q: What are the different units of concentration, and how are they related? A: The different units of concentration are molarity (M), molality (m), and percentage (%). Molarity is defined as the number of moles of solute per liter of solution. Molality is defined as the number of moles of solute per kilogram of solvent. Percentage is defined as the mass of solute per 100 grams of solution.
Q: How do I calculate the concentration of a solution? A: To calculate the concentration of a solution, you can use the following formula:
Concentration = Number of moles / Volume (in liters)
For example, if you have a solution with 2 moles of glucose and a volume of 1 liter, the concentration would be:
Concentration = 2 moles / 1 L = 2 M
Q: What is the difference between molarity and molality? A: Molarity is defined as the number of moles of solute per liter of solution, while molality is defined as the number of moles of solute per kilogram of solvent. Molarity is typically used for solutions with a small amount of solute, while molality is typically used for solutions with a large amount of solute.
Q: How do I calculate the number of moles of a solute in a solution? A: To calculate the number of moles of a solute in a solution, you can use the following formula:
Number of moles = Molarity x Volume (in liters)
For example, if you have a solution with a molarity of 6 M and a volume of 0.012 liters, the number of moles of solute would be:
Number of moles = 6 M x 0.012 L = 0.072 moles
Q: How do I calculate the volume of a working solution that can be made from a concentrated solution? A: To calculate the volume of a working solution that can be made from a concentrated solution, you can use the following formula:
Volume = Number of moles / Molarity
For example, if you have a concentrated solution with a molarity of 6 M and a number of moles of 0.072 moles, the volume of the working solution would be:
Volume = 0.072 moles / 6 M = 0.012 L
Q: What is the importance of diluting a solution? A: Diluting a solution is an important process in chemistry because it helps to achieve a desired concentration of a solute. Diluting a solution can also help to reduce the risk of contamination and improve the accuracy of laboratory experiments.
Q: How do I dilute a solution? A: To dilute a solution, you can add a solvent to the concentrated solution. The amount of solvent added will depend on the desired concentration of the working solution. You can use the following formula to calculate the amount of solvent needed:
Amount of solvent = (Molarity of working solution x Volume of working solution) / Molarity of concentrated solution
For example, if you want to dilute a concentrated solution with a molarity of 6 M to a working solution with a molarity of 0.8 M, and a volume of 0.012 L, the amount of solvent needed would be:
Amount of solvent = (0.8 M x 0.012 L) / 6 M = 0.0024 L
Conclusion
In this article, we have discussed the importance of concentration in chemistry and how to calculate the concentration of a solution. We have also discussed the different units of concentration, including molarity, molality, and percentage. Additionally, we have provided a step-by-step guide on how to dilute a solution and calculate the volume of a working solution that can be made from a concentrated solution.