Bethany, Who Weighs 560 N, Lies In A Hammock Suspended By Ropes Tied To Two Trees. The Left Rope Makes An Angle Of $45^{\circ}$ With The Ground; The Right One Makes An Angle Of $30^{\circ}$.Part AFind The Tension In The Left Rope.

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Resolving Tensions in a Suspended Hammock: A Physics Problem

In this article, we will delve into a physics problem involving a hammock suspended by ropes tied to two trees. The problem requires us to find the tension in the left rope, given the weight of the person lying in the hammock and the angles at which the ropes are tied to the ground. We will use the principles of trigonometry and physics to resolve the tensions in the ropes and find the required value.

Bethany, who weighs 560 N, lies in a hammock suspended by ropes tied to two trees. The left rope makes an angle of 45∘45^{\circ} with the ground; the right one makes an angle of 30∘30^{\circ}. We are required to find the tension in the left rope.

To solve this problem, we need to resolve the forces acting on the hammock. The forces acting on the hammock are the weight of Bethany (W) and the tensions in the two ropes (T1 and T2). We can resolve these forces into their horizontal and vertical components.

Vertical Components

The vertical component of the weight of Bethany is equal to the weight itself, which is 560 N. The vertical component of the tension in the left rope (T1) is given by:

T1 sin(45°) = 560 N

We can solve for T1 by rearranging the equation:

T1 = 560 N / sin(45°)

Horizontal Components

The horizontal component of the tension in the left rope (T1) is given by:

T1 cos(45°) = T2 cos(30°)

We can solve for T1 by rearranging the equation:

T1 = T2 cos(30°) / cos(45°)

Equating Vertical and Horizontal Components

We can equate the vertical and horizontal components of the forces acting on the hammock. This gives us:

T1 sin(45°) = T2 sin(30°)

We can substitute the expression for T1 from the vertical component equation:

(560 N / sin(45°)) sin(45°) = T2 sin(30°)

Simplifying the equation, we get:

560 N = T2 sin(30°)

Solving for T2

We can solve for T2 by rearranging the equation:

T2 = 560 N / sin(30°)

Finding the Tension in the Left Rope

Now that we have found the value of T2, we can substitute it into the equation for T1:

T1 = T2 cos(30°) / cos(45°)

Substituting the value of T2, we get:

T1 = (560 N / sin(30°)) cos(30°) / cos(45°)

Simplifying the equation, we get:

T1 = 784.3 N

In this article, we have used the principles of trigonometry and physics to resolve the tensions in a suspended hammock. We have found the tension in the left rope, given the weight of the person lying in the hammock and the angles at which the ropes are tied to the ground. The tension in the left rope is 784.3 N.

  • [1] Halliday, D., Resnick, R., & Walker, J. (2013). Fundamentals of Physics. John Wiley & Sons.
  • [2] Serway, R. A., & Jewett, J. W. (2018). Physics for Scientists and Engineers. Cengage Learning.

In our previous article, we explored a physics problem involving a hammock suspended by ropes tied to two trees. We used the principles of trigonometry and physics to resolve the tensions in the ropes and find the required value. In this article, we will address some of the most frequently asked questions related to this problem.

Q: What is the weight of the person lying in the hammock?

A: The weight of the person lying in the hammock is 560 N.

Q: What are the angles at which the ropes are tied to the ground?

A: The left rope makes an angle of 45∘45^{\circ} with the ground, and the right rope makes an angle of 30∘30^{\circ} with the ground.

Q: How do we resolve the forces acting on the hammock?

A: We resolve the forces acting on the hammock by breaking them down into their horizontal and vertical components.

Q: What is the vertical component of the weight of the person lying in the hammock?

A: The vertical component of the weight of the person lying in the hammock is equal to the weight itself, which is 560 N.

Q: How do we find the tension in the left rope?

A: We find the tension in the left rope by using the equation:

T1 sin(45°) = 560 N

We can solve for T1 by rearranging the equation:

T1 = 560 N / sin(45°)

Q: What is the horizontal component of the tension in the left rope?

A: The horizontal component of the tension in the left rope is given by:

T1 cos(45°) = T2 cos(30°)

We can solve for T1 by rearranging the equation:

T1 = T2 cos(30°) / cos(45°)

Q: How do we equate the vertical and horizontal components of the forces acting on the hammock?

A: We equate the vertical and horizontal components of the forces acting on the hammock by setting them equal to each other:

T1 sin(45°) = T2 sin(30°)

Q: What is the tension in the right rope?

A: We can find the tension in the right rope by rearranging the equation:

T2 = 560 N / sin(30°)

Q: What is the tension in the left rope?

A: We can find the tension in the left rope by substituting the value of T2 into the equation:

T1 = T2 cos(30°) / cos(45°)

Substituting the value of T2, we get:

T1 = (560 N / sin(30°)) cos(30°) / cos(45°)

Simplifying the equation, we get:

T1 = 784.3 N

In this article, we have addressed some of the most frequently asked questions related to the problem of resolving tensions in a suspended hammock. We have provided detailed explanations and equations to help clarify the concepts and procedures involved.

  • [1] Halliday, D., Resnick, R., & Walker, J. (2013). Fundamentals of Physics. John Wiley & Sons.
  • [2] Serway, R. A., & Jewett, J. W. (2018). Physics for Scientists and Engineers. Cengage Learning.