Analyze The Function $f(x)=\frac{\sqrt{2}(x-2)^2}{2}$ And Sketch The Graph.Hint: When $x$ Is Approaching Zero, $\frac{\sqrt{2}(x-2)^2}{2} \sim 2^2 \sqrt{x} / 2$. Otherwise, The Parabola $\sqrt{2}(x-2)^2 / 2$

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Introduction

In this article, we will delve into the analysis of the given function f(x)=2(x2)22f(x)=\frac{\sqrt{2}(x-2)^2}{2} and sketch its graph. The function appears to be a quadratic function, but with a twist. We will explore its behavior as xx approaches zero and its general behavior otherwise.

Understanding the Function

The given function is f(x)=2(x2)22f(x)=\frac{\sqrt{2}(x-2)^2}{2}. At first glance, it seems like a quadratic function, but with a square root term. Let's break it down further.

  • Quadratic Term: The term (x2)2(x-2)^2 is a quadratic term, which is a polynomial of degree 2. It represents a parabola that opens upwards or downwards.
  • Square Root Term: The term 2\sqrt{2} is a square root term, which is a non-polynomial term. It represents a non-polynomial function that grows or decays exponentially.
  • Constant Term: The term 12\frac{1}{2} is a constant term, which is a polynomial of degree 0. It represents a horizontal line.

Behavior as xx Approaches Zero

As xx approaches zero, the function f(x)f(x) behaves differently. We can use the hint provided to analyze its behavior.

  • Approximation: When xx is approaching zero, we can approximate the function f(x)f(x) as 2(x2)2222x/2\frac{\sqrt{2}(x-2)^2}{2} \sim 2^2 \sqrt{x} / 2.
  • Behavior: As xx approaches zero, the function f(x)f(x) approaches zero as well. This is because the quadratic term (x2)2(x-2)^2 approaches zero, and the square root term 2\sqrt{2} remains constant.

General Behavior

As xx moves away from zero, the function f(x)f(x) behaves differently. We can analyze its behavior by considering the general form of the function.

  • Parabola: The function f(x)f(x) is a parabola that opens upwards. This is because the quadratic term (x2)2(x-2)^2 is always positive, and the square root term 2\sqrt{2} is always positive.
  • Vertex: The vertex of the parabola is at x=2x=2. This is because the quadratic term (x2)2(x-2)^2 is zero at x=2x=2, and the square root term 2\sqrt{2} remains constant.

Sketching the Graph

To sketch the graph of the function f(x)f(x), we can use the following steps:

  1. Plot the Vertex: Plot the vertex of the parabola at x=2x=2.
  2. Plot the Asymptote: Plot the asymptote of the parabola, which is the horizontal line y=0y=0.
  3. Plot the Parabola: Plot the parabola that opens upwards, using the general form of the function.

Conclusion

In conclusion, the function f(x)=2(x2)22f(x)=\frac{\sqrt{2}(x-2)^2}{2} is a quadratic function with a twist. As xx approaches zero, the function behaves differently, and as xx moves away from zero, the function behaves like a parabola that opens upwards. We can sketch the graph of the function by plotting the vertex, asymptote, and parabola.

References

  • [1] "Calculus" by Michael Spivak
  • [2] "Algebra" by Michael Artin

Further Reading

For further reading on the topic of quadratic functions and their graphs, we recommend the following resources:

  • [1] "Quadratic Functions" by Khan Academy
  • [2] "Graphing Quadratic Functions" by Math Open Reference

Glossary

  • Quadratic Function: A polynomial function of degree 2.
  • Square Root Term: A non-polynomial term that grows or decays exponentially.
  • Constant Term: A polynomial of degree 0.
  • Vertex: The point on the graph of a parabola where the function changes from increasing to decreasing or vice versa.
  • Asymptote: A horizontal or vertical line that the graph of a function approaches but never touches.
    Q&A: Analyzing the Function f(x)=2(x2)22f(x)=\frac{\sqrt{2}(x-2)^2}{2} and Sketching the Graph =====================================================================================

Introduction

In our previous article, we analyzed the function f(x)=2(x2)22f(x)=\frac{\sqrt{2}(x-2)^2}{2} and sketched its graph. In this article, we will answer some frequently asked questions about the function and its graph.

Q: What is the domain of the function f(x)=2(x2)22f(x)=\frac{\sqrt{2}(x-2)^2}{2}?

A: The domain of the function f(x)=2(x2)22f(x)=\frac{\sqrt{2}(x-2)^2}{2} is all real numbers, except for x=2x=2. This is because the function is undefined at x=2x=2, where the denominator is zero.

Q: What is the range of the function f(x)=2(x2)22f(x)=\frac{\sqrt{2}(x-2)^2}{2}?

A: The range of the function f(x)=2(x2)22f(x)=\frac{\sqrt{2}(x-2)^2}{2} is all non-negative real numbers. This is because the function is always non-negative, and it approaches zero as xx approaches infinity.

Q: What is the vertex of the parabola represented by the function f(x)=2(x2)22f(x)=\frac{\sqrt{2}(x-2)^2}{2}?

A: The vertex of the parabola represented by the function f(x)=2(x2)22f(x)=\frac{\sqrt{2}(x-2)^2}{2} is at x=2x=2. This is because the quadratic term (x2)2(x-2)^2 is zero at x=2x=2, and the square root term 2\sqrt{2} remains constant.

Q: What is the asymptote of the parabola represented by the function f(x)=2(x2)22f(x)=\frac{\sqrt{2}(x-2)^2}{2}?

A: The asymptote of the parabola represented by the function f(x)=2(x2)22f(x)=\frac{\sqrt{2}(x-2)^2}{2} is the horizontal line y=0y=0. This is because the function approaches zero as xx approaches infinity.

Q: How does the function f(x)=2(x2)22f(x)=\frac{\sqrt{2}(x-2)^2}{2} behave as xx approaches zero?

A: As xx approaches zero, the function f(x)=2(x2)22f(x)=\frac{\sqrt{2}(x-2)^2}{2} approaches zero as well. This is because the quadratic term (x2)2(x-2)^2 approaches zero, and the square root term 2\sqrt{2} remains constant.

Q: How does the function f(x)=2(x2)22f(x)=\frac{\sqrt{2}(x-2)^2}{2} behave as xx approaches infinity?

A: As xx approaches infinity, the function f(x)=2(x2)22f(x)=\frac{\sqrt{2}(x-2)^2}{2} approaches infinity as well. This is because the quadratic term (x2)2(x-2)^2 approaches infinity, and the square root term 2\sqrt{2} remains constant.

Conclusion

In conclusion, the function f(x)=2(x2)22f(x)=\frac{\sqrt{2}(x-2)^2}{2} is a quadratic function with a twist. We have answered some frequently asked questions about the function and its graph, and we hope that this article has been helpful in understanding the function and its behavior.

References

  • [1] "Calculus" by Michael Spivak
  • [2] "Algebra" by Michael Artin

Further Reading

For further reading on the topic of quadratic functions and their graphs, we recommend the following resources:

  • [1] "Quadratic Functions" by Khan Academy
  • [2] "Graphing Quadratic Functions" by Math Open Reference

Glossary

  • Quadratic Function: A polynomial function of degree 2.
  • Square Root Term: A non-polynomial term that grows or decays exponentially.
  • Constant Term: A polynomial of degree 0.
  • Vertex: The point on the graph of a parabola where the function changes from increasing to decreasing or vice versa.
  • Asymptote: A horizontal or vertical line that the graph of a function approaches but never touches.