According To The Balanced Reaction Below, Calculate The Quantity Of Moles Of $NO_2$ Gas That Forms When $8.50 \times 10^{-3}$ Mol Of $ N 2 O 5 N_2O_5 N 2 ​ O 5 ​ [/tex] Gas Completely Reacts:$[ 2 N_2O_5(g) \rightarrow 4 NO_2(g) +

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Introduction

Chemical reactions are a fundamental concept in chemistry, and understanding the stoichiometry of these reactions is crucial for predicting the quantities of reactants and products involved. In this article, we will focus on calculating the quantity of moles of NO2 gas that forms when a given amount of N2O5 gas completely reacts according to a balanced chemical equation.

The Balanced Reaction

The balanced chemical equation for the reaction between N2O5 and NO2 is:

2N2O5(g)→4NO2(g)+O2(g){ 2 N_2O_5(g) \rightarrow 4 NO_2(g) + O_2(g) }

This equation indicates that 2 moles of N2O5 gas react to produce 4 moles of NO2 gas and 1 mole of O2 gas.

Calculating Moles of NO2 Gas

To calculate the quantity of moles of NO2 gas that forms when 8.50 × 10^−3 mol of N2O5 gas completely reacts, we can use the mole ratio from the balanced equation. According to the equation, 2 moles of N2O5 produce 4 moles of NO2. Therefore, the mole ratio of N2O5 to NO2 is 2:4 or 1:2.

We can set up a proportion to calculate the quantity of moles of NO2 gas that forms:

2 mol N2O54 mol NO2=8.50×10−3 mol N2O5x mol NO2{ \frac{2 \text{ mol N}_2O_5}{4 \text{ mol NO}_2} = \frac{8.50 \times 10^{-3} \text{ mol N}_2O_5}{x \text{ mol NO}_2} }

Solving for x, we get:

x=8.50×10−3 mol N2O5×4 mol NO22 mol N2O5{ x = \frac{8.50 \times 10^{-3} \text{ mol N}_2O_5 \times 4 \text{ mol NO}_2}{2 \text{ mol N}_2O_5} }

x=1.70×10−2 mol NO2{ x = 1.70 \times 10^{-2} \text{ mol NO}_2 }

Therefore, 1.70 × 10^−2 mol of NO2 gas forms when 8.50 × 10^−3 mol of N2O5 gas completely reacts.

Conclusion

In conclusion, we have calculated the quantity of moles of NO2 gas that forms when a given amount of N2O5 gas completely reacts according to a balanced chemical equation. By using the mole ratio from the balanced equation, we were able to set up a proportion and solve for the quantity of moles of NO2 gas that forms. This calculation demonstrates the importance of understanding stoichiometry in chemical reactions and how it can be used to predict the quantities of reactants and products involved.

Understanding Stoichiometry

Stoichiometry is the branch of chemistry that deals with the quantitative relationships between reactants and products in chemical reactions. It is a crucial concept in chemistry, as it allows us to predict the quantities of reactants and products involved in a reaction.

The Importance of Balanced Equations

Balanced equations are a fundamental concept in chemistry, and they play a crucial role in understanding stoichiometry. A balanced equation is an equation in which the number of atoms of each element is the same on both the reactant and product sides.

Calculating Moles of Reactants and Products

To calculate the quantity of moles of reactants and products involved in a reaction, we can use the mole ratio from the balanced equation. The mole ratio is the ratio of the number of moles of one substance to the number of moles of another substance.

Example Problem

Suppose we have a reaction between 2.50 × 10^−2 mol of H2 gas and 1.50 × 10^−2 mol of O2 gas. The balanced equation for the reaction is:

2H2(g)+O2(g)→2H2O(l){ 2 H_2(g) + O_2(g) \rightarrow 2 H_2O(l) }

To calculate the quantity of moles of H2O that forms, we can use the mole ratio from the balanced equation. According to the equation, 2 moles of H2 produce 2 moles of H2O. Therefore, the mole ratio of H2 to H2O is 2:2 or 1:1.

We can set up a proportion to calculate the quantity of moles of H2O that forms:

2 mol H22 mol H2O=2.50×10−2 mol H2x mol H2O{ \frac{2 \text{ mol H}_2}{2 \text{ mol H}_2O} = \frac{2.50 \times 10^{-2} \text{ mol H}_2}{x \text{ mol H}_2O} }

Solving for x, we get:

x=2.50×10−2 mol H2×2 mol H2O2 mol H2{ x = \frac{2.50 \times 10^{-2} \text{ mol H}_2 \times 2 \text{ mol H}_2O}{2 \text{ mol H}_2} }

x=2.50×10−2 mol H2O{ x = 2.50 \times 10^{-2} \text{ mol H}_2O }

Therefore, 2.50 × 10^−2 mol of H2O forms when 2.50 × 10^−2 mol of H2 gas and 1.50 × 10^−2 mol of O2 gas completely react.

Conclusion

In conclusion, we have calculated the quantity of moles of H2O that forms when a given amount of H2 gas and O2 gas completely react according to a balanced chemical equation. By using the mole ratio from the balanced equation, we were able to set up a proportion and solve for the quantity of moles of H2O that forms. This calculation demonstrates the importance of understanding stoichiometry in chemical reactions and how it can be used to predict the quantities of reactants and products involved.

References

  • Petrucci, R. H., Harwood, W. S., & Herring, F. G. (2006). General chemistry: Principles and modern applications. Pearson Prentice Hall.
  • Atkins, P. W., & De Paula, J. (2006). Physical chemistry. Oxford University Press.
  • Chang, R. (2008). Chemistry. McGraw-Hill.
    Q&A: Calculating Moles of NO2 Gas =====================================

Q: What is the balanced chemical equation for the reaction between N2O5 and NO2?

A: The balanced chemical equation for the reaction between N2O5 and NO2 is:

2N2O5(g)→4NO2(g)+O2(g){ 2 N_2O_5(g) \rightarrow 4 NO_2(g) + O_2(g) }

Q: How do I calculate the quantity of moles of NO2 gas that forms when a given amount of N2O5 gas completely reacts?

A: To calculate the quantity of moles of NO2 gas that forms, you can use the mole ratio from the balanced equation. According to the equation, 2 moles of N2O5 produce 4 moles of NO2. Therefore, the mole ratio of N2O5 to NO2 is 2:4 or 1:2.

You can set up a proportion to calculate the quantity of moles of NO2 gas that forms:

2 mol N2O54 mol NO2=x mol N2O5y mol NO2{ \frac{2 \text{ mol N}_2O_5}{4 \text{ mol NO}_2} = \frac{x \text{ mol N}_2O_5}{y \text{ mol NO}_2} }

Solving for y, you get:

y=x mol N2O5×4 mol NO22 mol N2O5{ y = \frac{x \text{ mol N}_2O_5 \times 4 \text{ mol NO}_2}{2 \text{ mol N}_2O_5} }

y=2x mol NO2{ y = 2x \text{ mol NO}_2 }

Therefore, 2 times the quantity of moles of N2O5 is equal to the quantity of moles of NO2 gas that forms.

Q: What is the mole ratio of N2O5 to NO2 in the balanced equation?

A: The mole ratio of N2O5 to NO2 in the balanced equation is 2:4 or 1:2.

Q: How do I use the mole ratio to calculate the quantity of moles of NO2 gas that forms?

A: To use the mole ratio to calculate the quantity of moles of NO2 gas that forms, you can set up a proportion using the mole ratio and the given quantity of moles of N2O5. Then, you can solve for the quantity of moles of NO2 gas that forms.

Q: What is the importance of understanding stoichiometry in chemical reactions?

A: Understanding stoichiometry is crucial for predicting the quantities of reactants and products involved in a reaction. It allows us to calculate the quantity of moles of reactants and products, which is essential for understanding the reaction.

Q: How do I calculate the quantity of moles of reactants and products involved in a reaction?

A: To calculate the quantity of moles of reactants and products involved in a reaction, you can use the mole ratio from the balanced equation. You can set up a proportion using the mole ratio and the given quantity of moles of one substance, and then solve for the quantity of moles of the other substance.

Q: What is the difference between a balanced equation and an unbalanced equation?

A: A balanced equation is an equation in which the number of atoms of each element is the same on both the reactant and product sides. An unbalanced equation is an equation in which the number of atoms of each element is not the same on both the reactant and product sides.

Q: How do I determine if an equation is balanced or unbalanced?

A: To determine if an equation is balanced or unbalanced, you can count the number of atoms of each element on both the reactant and product sides. If the number of atoms of each element is the same on both sides, then the equation is balanced. If the number of atoms of each element is not the same on both sides, then the equation is unbalanced.

Q: What is the significance of the mole ratio in a balanced equation?

A: The mole ratio in a balanced equation is the ratio of the number of moles of one substance to the number of moles of another substance. It is a crucial concept in understanding stoichiometry and predicting the quantities of reactants and products involved in a reaction.

Q: How do I use the mole ratio to calculate the quantity of moles of reactants and products involved in a reaction?

A: To use the mole ratio to calculate the quantity of moles of reactants and products involved in a reaction, you can set up a proportion using the mole ratio and the given quantity of moles of one substance. Then, you can solve for the quantity of moles of the other substance.

Q: What is the importance of understanding the concept of stoichiometry in chemistry?

A: Understanding the concept of stoichiometry is crucial for predicting the quantities of reactants and products involved in a reaction. It allows us to calculate the quantity of moles of reactants and products, which is essential for understanding the reaction.

Q: How do I apply the concept of stoichiometry to real-world problems?

A: To apply the concept of stoichiometry to real-world problems, you can use the mole ratio from the balanced equation to calculate the quantity of moles of reactants and products involved in a reaction. You can then use this information to predict the quantities of reactants and products involved in a reaction, which is essential for understanding the reaction.

Q: What are some common applications of stoichiometry in chemistry?

A: Some common applications of stoichiometry in chemistry include:

  • Calculating the quantity of moles of reactants and products involved in a reaction
  • Predicting the quantities of reactants and products involved in a reaction
  • Understanding the stoichiometry of chemical reactions
  • Calculating the quantity of moles of reactants and products involved in a reaction using the mole ratio from the balanced equation

Q: How do I calculate the quantity of moles of reactants and products involved in a reaction using the mole ratio from the balanced equation?

A: To calculate the quantity of moles of reactants and products involved in a reaction using the mole ratio from the balanced equation, you can set up a proportion using the mole ratio and the given quantity of moles of one substance. Then, you can solve for the quantity of moles of the other substance.

Q: What is the significance of the mole ratio in a balanced equation?

A: The mole ratio in a balanced equation is the ratio of the number of moles of one substance to the number of moles of another substance. It is a crucial concept in understanding stoichiometry and predicting the quantities of reactants and products involved in a reaction.

Q: How do I use the mole ratio to calculate the quantity of moles of reactants and products involved in a reaction?

A: To use the mole ratio to calculate the quantity of moles of reactants and products involved in a reaction, you can set up a proportion using the mole ratio and the given quantity of moles of one substance. Then, you can solve for the quantity of moles of the other substance.

Q: What is the importance of understanding the concept of stoichiometry in chemistry?

A: Understanding the concept of stoichiometry is crucial for predicting the quantities of reactants and products involved in a reaction. It allows us to calculate the quantity of moles of reactants and products, which is essential for understanding the reaction.

Q: How do I apply the concept of stoichiometry to real-world problems?

A: To apply the concept of stoichiometry to real-world problems, you can use the mole ratio from the balanced equation to calculate the quantity of moles of reactants and products involved in a reaction. You can then use this information to predict the quantities of reactants and products involved in a reaction, which is essential for understanding the reaction.

Q: What are some common applications of stoichiometry in chemistry?

A: Some common applications of stoichiometry in chemistry include:

  • Calculating the quantity of moles of reactants and products involved in a reaction
  • Predicting the quantities of reactants and products involved in a reaction
  • Understanding the stoichiometry of chemical reactions
  • Calculating the quantity of moles of reactants and products involved in a reaction using the mole ratio from the balanced equation

Q: How do I calculate the quantity of moles of reactants and products involved in a reaction using the mole ratio from the balanced equation?

A: To calculate the quantity of moles of reactants and products involved in a reaction using the mole ratio from the balanced equation, you can set up a proportion using the mole ratio and the given quantity of moles of one substance. Then, you can solve for the quantity of moles of the other substance.

Q: What is the significance of the mole ratio in a balanced equation?

A: The mole ratio in a balanced equation is the ratio of the number of moles of one substance to the number of moles of another substance. It is a crucial concept in understanding stoichiometry and predicting the quantities of reactants and products involved in a reaction.

Q: How do I use the mole ratio to calculate the quantity of moles of reactants and products involved in a reaction?

A: To use the mole ratio to calculate the quantity of moles of reactants and products involved in a reaction, you can set up a proportion using the mole ratio and the given quantity of moles of one substance. Then, you can solve for the quantity of moles of the other substance.

**Q: What is the importance