A Sequence Has A Common Ratio Of 3 2 \frac{3}{2} 2 3 ​ And F ( 5 ) = 81 F(5) = 81 F ( 5 ) = 81 . Which Explicit Formula Represents The Sequence?A. F ( X ) = 24 ( 3 2 ) X − 1 F(x) = 24\left(\frac{3}{2}\right)^{x-1} F ( X ) = 24 ( 2 3 ​ ) X − 1 B. F ( X ) = 16 ( 3 2 ) X − 2 F(x) = 16\left(\frac{3}{2}\right)^{x-2} F ( X ) = 16 ( 2 3 ​ ) X − 2 C. $f(x)

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Understanding the Problem

When dealing with sequences, it's essential to understand the concept of a common ratio and how it affects the terms of the sequence. In this problem, we're given a sequence with a common ratio of 32\frac{3}{2} and the value of the fifth term, f(5)=81f(5) = 81. Our goal is to find the explicit formula that represents this sequence.

The Formula for a Geometric Sequence

A geometric sequence is a sequence of numbers where each term after the first is found by multiplying the previous term by a fixed, non-zero number called the common ratio. The general formula for a geometric sequence is:

f(x)=arx1f(x) = a \cdot r^{x-1}

where aa is the first term, rr is the common ratio, and xx is the term number.

Finding the First Term

We're given that the common ratio is 32\frac{3}{2} and the value of the fifth term is 8181. We can use this information to find the first term, aa. Plugging in the values we know, we get:

f(5)=a(32)51=81f(5) = a \cdot \left(\frac{3}{2}\right)^{5-1} = 81

Simplifying the equation, we get:

a(32)4=81a \cdot \left(\frac{3}{2}\right)^{4} = 81

Solving for the First Term

To solve for the first term, aa, we need to isolate it on one side of the equation. We can do this by dividing both sides of the equation by (32)4\left(\frac{3}{2}\right)^{4}:

a=81(32)4a = \frac{81}{\left(\frac{3}{2}\right)^{4}}

Simplifying the expression, we get:

a=818116=16a = \frac{81}{\frac{81}{16}} = 16

Finding the Explicit Formula

Now that we have the first term, aa, we can plug it into the general formula for a geometric sequence:

f(x)=arx1f(x) = a \cdot r^{x-1}

Substituting the values we know, we get:

f(x)=16(32)x1f(x) = 16 \cdot \left(\frac{3}{2}\right)^{x-1}

Conclusion

The explicit formula that represents the sequence is:

f(x)=16(32)x1f(x) = 16 \cdot \left(\frac{3}{2}\right)^{x-1}

This formula represents the sequence with a common ratio of 32\frac{3}{2} and the value of the fifth term, f(5)=81f(5) = 81.

Comparison with Other Options

Let's compare our answer with the other options:

  • Option A: f(x)=24(32)x1f(x) = 24\left(\frac{3}{2}\right)^{x-1}
  • Option B: f(x)=16(32)x2f(x) = 16\left(\frac{3}{2}\right)^{x-2}
  • Option C: f(x)=32(32)x1f(x) = 32\left(\frac{3}{2}\right)^{x-1}

Our answer, f(x)=16(32)x1f(x) = 16 \cdot \left(\frac{3}{2}\right)^{x-1}, matches option A.

Final Answer

The explicit formula that represents the sequence is:

f(x)=16(32)x1f(x) = 16 \cdot \left(\frac{3}{2}\right)^{x-1}

This formula represents the sequence with a common ratio of 32\frac{3}{2} and the value of the fifth term, f(5)=81f(5) = 81.

Understanding the Problem

When dealing with sequences, it's essential to understand the concept of a common ratio and how it affects the terms of the sequence. In this problem, we're given a sequence with a common ratio of 32\frac{3}{2} and the value of the fifth term, f(5)=81f(5) = 81. Our goal is to find the explicit formula that represents this sequence.

Q&A

Q: What is a geometric sequence?

A: A geometric sequence is a sequence of numbers where each term after the first is found by multiplying the previous term by a fixed, non-zero number called the common ratio.

Q: What is the general formula for a geometric sequence?

A: The general formula for a geometric sequence is:

f(x)=arx1f(x) = a \cdot r^{x-1}

where aa is the first term, rr is the common ratio, and xx is the term number.

Q: How do we find the first term, aa, in a geometric sequence?

A: To find the first term, aa, we can use the formula:

a=f(x)rx1a = \frac{f(x)}{r^{x-1}}

where f(x)f(x) is the value of the term, rr is the common ratio, and xx is the term number.

Q: What is the common ratio, rr, in this problem?

A: The common ratio, rr, is 32\frac{3}{2}.

Q: What is the value of the fifth term, f(5)f(5), in this problem?

A: The value of the fifth term, f(5)f(5), is 8181.

Q: How do we find the explicit formula for the sequence?

A: To find the explicit formula for the sequence, we can plug the values we know into the general formula for a geometric sequence:

f(x)=arx1f(x) = a \cdot r^{x-1}

Substituting the values we know, we get:

f(x)=16(32)x1f(x) = 16 \cdot \left(\frac{3}{2}\right)^{x-1}

Q: What is the explicit formula for the sequence?

A: The explicit formula for the sequence is:

f(x)=16(32)x1f(x) = 16 \cdot \left(\frac{3}{2}\right)^{x-1}

Q: How do we compare the explicit formula with other options?

A: To compare the explicit formula with other options, we can plug the values we know into the other options and see if they match the explicit formula.

Q: What are the other options?

A: The other options are:

  • Option A: f(x)=24(32)x1f(x) = 24\left(\frac{3}{2}\right)^{x-1}
  • Option B: f(x)=16(32)x2f(x) = 16\left(\frac{3}{2}\right)^{x-2}
  • Option C: f(x)=32(32)x1f(x) = 32\left(\frac{3}{2}\right)^{x-1}

Q: Which option matches the explicit formula?

A: Option A matches the explicit formula.

Conclusion

The explicit formula that represents the sequence is:

f(x)=16(32)x1f(x) = 16 \cdot \left(\frac{3}{2}\right)^{x-1}

This formula represents the sequence with a common ratio of 32\frac{3}{2} and the value of the fifth term, f(5)=81f(5) = 81.