A Line Has A Slope Of 0 And A $y$-intercept Of $\frac{8}{5}$. Write Its Equation In Slope-intercept Form.Write Your Answer Using Integers, Proper Fractions, And Improper Fractions In Simplest Form.

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Introduction

In mathematics, the slope-intercept form of a line is a fundamental concept that helps us understand the relationship between the slope and the yy-intercept of a line. The slope-intercept form is given by the equation y=mx+by = mx + b, where mm is the slope and bb is the yy-intercept. In this article, we will explore the equation of a line with a slope of 0 and a yy-intercept of 85\frac{8}{5}.

Understanding the Slope-Intercept Form

The slope-intercept form of a line is a powerful tool that allows us to visualize the relationship between the slope and the yy-intercept of a line. The slope, denoted by mm, represents the rate of change of the line, while the yy-intercept, denoted by bb, represents the point at which the line intersects the yy-axis. In the equation y=mx+by = mx + b, the slope mm is multiplied by the xx-coordinate of a point on the line, and the result is added to the yy-intercept bb.

The Equation of a Line with a Slope of 0

When the slope of a line is 0, it means that the line is horizontal. A horizontal line has the same yy-coordinate at every point on the line. In other words, the yy-coordinate does not change as we move along the line. Since the slope is 0, the equation of the line can be written as y=0x+by = 0x + b, where bb is the yy-intercept.

Finding the Equation of the Line

Given that the yy-intercept of the line is 85\frac{8}{5}, we can substitute this value into the equation y=0x+by = 0x + b to find the equation of the line. The equation becomes y=0x+85y = 0x + \frac{8}{5}.

Simplifying the Equation

To simplify the equation, we can rewrite it as y=85y = \frac{8}{5}. This is because the term 0x0x is equal to 0, and when we add 0 to a number, the result is the same number.

Conclusion

In conclusion, the equation of a line with a slope of 0 and a yy-intercept of 85\frac{8}{5} is y=85y = \frac{8}{5}. This equation represents a horizontal line that intersects the yy-axis at the point (0,85)\left(0, \frac{8}{5}\right). The slope-intercept form of a line is a powerful tool that helps us understand the relationship between the slope and the yy-intercept of a line.

Examples and Applications

Here are a few examples and applications of the equation y=85y = \frac{8}{5}:

  • Graphing the Line: To graph the line, we can plot the point (0,85)\left(0, \frac{8}{5}\right) on the yy-axis and draw a horizontal line through this point.
  • Finding the yy-Coordinate: To find the yy-coordinate of a point on the line, we can substitute the xx-coordinate into the equation y=85y = \frac{8}{5}.
  • Solving for xx: To solve for xx, we can rearrange the equation y=85y = \frac{8}{5} to isolate xx. However, since the equation is in the form y=mx+by = mx + b, where m=0m = 0, we cannot solve for xx.

Exercises and Problems

Here are a few exercises and problems to help you practice working with the equation y=85y = \frac{8}{5}:

  • Exercise 1: Graph the line y=85y = \frac{8}{5} and find the yy-coordinate of the point (2,y)\left(2, y\right).
  • Exercise 2: Find the equation of a line with a slope of 0 and a yy-intercept of 34\frac{3}{4}.
  • Problem: A horizontal line intersects the yy-axis at the point (0,53)\left(0, \frac{5}{3}\right). Find the equation of the line.

Solutions to Exercises and Problems

Here are the solutions to the exercises and problems:

  • Exercise 1: To graph the line, we can plot the point (0,85)\left(0, \frac{8}{5}\right) on the yy-axis and draw a horizontal line through this point. To find the yy-coordinate of the point (2,y)\left(2, y\right), we can substitute x=2x = 2 into the equation y=85y = \frac{8}{5}, which gives us y=85y = \frac{8}{5}.
  • Exercise 2: The equation of a line with a slope of 0 and a yy-intercept of 34\frac{3}{4} is y=34y = \frac{3}{4}.
  • Problem: The equation of the line is y=53y = \frac{5}{3}.

Conclusion

In conclusion, the equation of a line with a slope of 0 and a yy-intercept of 85\frac{8}{5} is y=85y = \frac{8}{5}. This equation represents a horizontal line that intersects the yy-axis at the point (0,85)\left(0, \frac{8}{5}\right). The slope-intercept form of a line is a powerful tool that helps us understand the relationship between the slope and the yy-intercept of a line.

Introduction

In our previous article, we explored the equation of a line with a slope of 0 and a yy-intercept of 85\frac{8}{5}. In this article, we will answer some frequently asked questions about this topic.

Q&A

Q: What is the equation of a line with a slope of 0 and a yy-intercept of 85\frac{8}{5}?

A: The equation of a line with a slope of 0 and a yy-intercept of 85\frac{8}{5} is y=85y = \frac{8}{5}.

Q: What does the slope of 0 mean in the context of a line?

A: The slope of 0 means that the line is horizontal. A horizontal line has the same yy-coordinate at every point on the line.

Q: What is the yy-intercept of a line?

A: The yy-intercept of a line is the point at which the line intersects the yy-axis. In the equation y=mx+by = mx + b, the yy-intercept is represented by the term bb.

Q: How do I graph a line with a slope of 0 and a yy-intercept of 85\frac{8}{5}?

A: To graph a line with a slope of 0 and a yy-intercept of 85\frac{8}{5}, you can plot the point (0,85)\left(0, \frac{8}{5}\right) on the yy-axis and draw a horizontal line through this point.

Q: Can I solve for xx in the equation y=85y = \frac{8}{5}?

A: No, you cannot solve for xx in the equation y=85y = \frac{8}{5} because the equation is in the form y=mx+by = mx + b, where m=0m = 0. Since the slope is 0, the equation does not have a solution for xx.

Q: What is the relationship between the slope and the yy-intercept of a line?

A: The slope and the yy-intercept of a line are related in the equation y=mx+by = mx + b. The slope mm represents the rate of change of the line, while the yy-intercept bb represents the point at which the line intersects the yy-axis.

Q: Can I find the equation of a line with a slope of 0 and a yy-intercept of 34\frac{3}{4}?

A: Yes, you can find the equation of a line with a slope of 0 and a yy-intercept of 34\frac{3}{4} by substituting the values into the equation y=mx+by = mx + b. The equation becomes y=0x+34y = 0x + \frac{3}{4}, which simplifies to y=34y = \frac{3}{4}.

Conclusion

In conclusion, the equation of a line with a slope of 0 and a yy-intercept of 85\frac{8}{5} is y=85y = \frac{8}{5}. This equation represents a horizontal line that intersects the yy-axis at the point (0,85)\left(0, \frac{8}{5}\right). The slope-intercept form of a line is a powerful tool that helps us understand the relationship between the slope and the yy-intercept of a line.

Additional Resources

  • Graphing Lines: To learn more about graphing lines, check out our article on graphing lines.
  • Slope-Intercept Form: To learn more about the slope-intercept form of a line, check out our article on the slope-intercept form.
  • Mathematics: To learn more about mathematics, check out our article on mathematics.

Exercises and Problems

Here are a few exercises and problems to help you practice working with the equation y=85y = \frac{8}{5}:

  • Exercise 1: Graph the line y=85y = \frac{8}{5} and find the yy-coordinate of the point (2,y)\left(2, y\right).
  • Exercise 2: Find the equation of a line with a slope of 0 and a yy-intercept of 34\frac{3}{4}.
  • Problem: A horizontal line intersects the yy-axis at the point (0,53)\left(0, \frac{5}{3}\right). Find the equation of the line.

Solutions to Exercises and Problems

Here are the solutions to the exercises and problems:

  • Exercise 1: To graph the line, you can plot the point (0,85)\left(0, \frac{8}{5}\right) on the yy-axis and draw a horizontal line through this point. To find the yy-coordinate of the point (2,y)\left(2, y\right), you can substitute x=2x = 2 into the equation y=85y = \frac{8}{5}, which gives us y=85y = \frac{8}{5}.
  • Exercise 2: The equation of a line with a slope of 0 and a yy-intercept of 34\frac{3}{4} is y=34y = \frac{3}{4}.
  • Problem: The equation of the line is y=53y = \frac{5}{3}.