A Freight Train Is Traveling At An Average Rate Of 45 Miles Per Hour. Which Equation Represents The Situation?Let $h$ Represent The Hours Traveled. Let $m$ Represent The Miles Traveled.$\begin{array}{l} M = 45h \\ H = 45m \\ M =

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Introduction

In physics and mathematics, the relationship between speed, time, and distance is a fundamental concept that is often represented by a simple equation. In this article, we will explore the equation that represents the situation of a freight train traveling at an average rate of 45 miles per hour.

The Equation

Let's start by defining the variables:

  • hh represents the hours traveled
  • mm represents the miles traveled

The equation that represents the situation is:

m=45hm = 45h

Explanation

This equation states that the distance traveled (mm) is equal to the speed of the train (45 miles per hour) multiplied by the time traveled (hh). In other words, if the train travels for hh hours, it will cover a distance of mm miles.

Why This Equation?

This equation is a direct application of the formula:

Distance=Speed×Time\text{Distance} = \text{Speed} \times \text{Time}

In this case, the speed is 45 miles per hour, and the time is hh hours. Therefore, the distance traveled is equal to the speed multiplied by the time.

Alternative Equations

Some readers may be wondering why the equation is not:

h=45mh = 45m

or

m=45h−1m = 45h^{-1}

The reason is that the first equation is not a correct representation of the situation. The second equation is also not correct, as it implies that the time traveled is inversely proportional to the distance traveled, which is not the case.

Conclusion

In conclusion, the equation that represents the situation of a freight train traveling at an average rate of 45 miles per hour is:

m=45hm = 45h

This equation is a direct application of the formula:

Distance=Speed×Time\text{Distance} = \text{Speed} \times \text{Time}

Example Problems

Here are a few example problems to illustrate the use of this equation:

  • If the freight train travels for 2 hours, how many miles will it cover?
  • If the freight train covers a distance of 90 miles, how many hours will it take to travel that distance?

Solution to Example Problems

  • If the freight train travels for 2 hours, the distance traveled will be:

m=45hm = 45h

m=45×2m = 45 \times 2

m=90m = 90

Therefore, the freight train will cover a distance of 90 miles in 2 hours.

  • If the freight train covers a distance of 90 miles, the time taken will be:

m=45hm = 45h

90=45h90 = 45h

h=2h = 2

Therefore, the freight train will take 2 hours to cover a distance of 90 miles.

Real-World Applications

The equation m=45hm = 45h has many real-world applications, including:

  • Calculating the distance traveled by a vehicle
  • Determining the time taken to travel a certain distance
  • Planning routes for transportation

Conclusion

In conclusion, the equation m=45hm = 45h represents the situation of a freight train traveling at an average rate of 45 miles per hour. This equation is a direct application of the formula:

Distance=Speed×Time\text{Distance} = \text{Speed} \times \text{Time}

Q: What is the equation m=45hm = 45h used for?

A: The equation m=45hm = 45h is used to calculate the distance traveled by a vehicle, given its speed and time traveled. It is a direct application of the formula:

Distance=Speed×Time\text{Distance} = \text{Speed} \times \text{Time}

Q: What are the variables in the equation m=45hm = 45h?

A: The variables in the equation m=45hm = 45h are:

  • hh: the hours traveled
  • mm: the miles traveled

Q: What is the speed in the equation m=45hm = 45h?

A: The speed in the equation m=45hm = 45h is 45 miles per hour.

Q: Can I use the equation m=45hm = 45h for any speed?

A: No, the equation m=45hm = 45h is specific to a speed of 45 miles per hour. If you want to calculate the distance traveled for a different speed, you will need to use a different equation.

Q: How do I use the equation m=45hm = 45h to calculate the distance traveled?

A: To use the equation m=45hm = 45h to calculate the distance traveled, simply plug in the values for hh and mm. For example, if the freight train travels for 2 hours, the distance traveled will be:

m=45hm = 45h

m=45×2m = 45 \times 2

m=90m = 90

Therefore, the freight train will cover a distance of 90 miles in 2 hours.

Q: Can I use the equation m=45hm = 45h to calculate the time taken to travel a certain distance?

A: Yes, you can use the equation m=45hm = 45h to calculate the time taken to travel a certain distance. To do this, simply rearrange the equation to solve for hh:

h=m45h = \frac{m}{45}

For example, if the freight train covers a distance of 90 miles, the time taken will be:

h=m45h = \frac{m}{45}

h=9045h = \frac{90}{45}

h=2h = 2

Therefore, the freight train will take 2 hours to cover a distance of 90 miles.

Q: What are some real-world applications of the equation m=45hm = 45h?

A: Some real-world applications of the equation m=45hm = 45h include:

  • Calculating the distance traveled by a vehicle
  • Determining the time taken to travel a certain distance
  • Planning routes for transportation
  • Estimating the fuel consumption of a vehicle
  • Calculating the cost of transportation

Q: Can I use the equation m=45hm = 45h for other types of transportation?

A: Yes, the equation m=45hm = 45h can be used for other types of transportation, such as airplanes, boats, and bicycles. Simply plug in the speed and time values for the specific type of transportation.

Q: What are some common mistakes to avoid when using the equation m=45hm = 45h?

A: Some common mistakes to avoid when using the equation m=45hm = 45h include:

  • Using the wrong units (e.g. miles per hour instead of kilometers per hour)
  • Forgetting to plug in the correct values for hh and mm
  • Not checking the units of the answer
  • Not considering the limitations of the equation (e.g. it assumes a constant speed)

Conclusion

In conclusion, the equation m=45hm = 45h is a simple and powerful tool for calculating the distance traveled by a vehicle, given its speed and time traveled. By understanding the variables and limitations of the equation, you can use it to solve a wide range of problems in physics, engineering, and everyday life.