A Current Of Electron Passes Through Two Cells In Series . One Contains Sliver Nitrate And The Other Contains Lead Nitrate. In The First, 0.54 Gram Of Sliver Are Deposited On The Cathode. What Mass Of Lead Is Deposited In The Second Cell
Introduction
In the realm of electrochemistry, the passage of an electric current through a solution containing ions can lead to the deposition of metals on the cathode. This phenomenon is a fundamental concept in the field of chemistry, and understanding the relationship between different ions and their corresponding metals is crucial for various applications. In this article, we will delve into the world of electrochemistry and explore the concept of two cells in series, one containing silver nitrate and the other containing lead nitrate. We will also examine the relationship between the mass of silver deposited in the first cell and the mass of lead deposited in the second cell.
The Electrochemical Cell
An electrochemical cell is a device that consists of two electrodes, an anode and a cathode, separated by an electrolyte. The anode is the electrode where oxidation occurs, and the cathode is the electrode where reduction occurs. In the case of a cell containing silver nitrate, the anode is typically made of silver, and the cathode is made of a different material. When an electric current is passed through the cell, silver ions (Ag+) are reduced at the cathode, resulting in the deposition of silver metal.
The Relationship Between Silver and Lead Nitrate
In the second cell, lead nitrate is the electrolyte, and the anode is typically made of lead. When an electric current is passed through this cell, lead ions (Pb2+) are reduced at the cathode, resulting in the deposition of lead metal. The key to understanding the relationship between silver and lead nitrate lies in the fact that both cells are connected in series. This means that the electric current flowing through the first cell is the same as the electric current flowing through the second cell.
The Concept of Equivalent Weight
To determine the mass of lead deposited in the second cell, we need to understand the concept of equivalent weight. The equivalent weight of a substance is the mass of that substance that will react with or be reduced by one mole of electrons. In the case of silver nitrate, the equivalent weight of silver is 107.87 g/equiv. This means that 107.87 grams of silver will react with or be reduced by one mole of electrons.
Calculating the Mass of Lead Deposited
Given that 0.54 grams of silver are deposited in the first cell, we can calculate the mass of lead deposited in the second cell using the concept of equivalent weight. Since the electric current flowing through both cells is the same, the number of moles of electrons passing through both cells is also the same. Therefore, the mass of lead deposited in the second cell is directly proportional to the mass of silver deposited in the first cell.
The Formula for Calculating the Mass of Lead Deposited
The formula for calculating the mass of lead deposited in the second cell is as follows:
m(Pb) = m(Ag) x (Equiv. wt. of Pb / Equiv. wt. of Ag)
where m(Pb) is the mass of lead deposited, m(Ag) is the mass of silver deposited, and Equiv. wt. of Pb and Equiv. wt. of Ag are the equivalent weights of lead and silver, respectively.
Substituting the Values
Substituting the values given in the problem, we get:
m(Pb) = 0.54 g x (207.2 g/equiv / 107.87 g/equiv)
Calculating the Mass of Lead Deposited
Simplifying the expression, we get:
m(Pb) = 0.54 g x 1.92
m(Pb) = 1.0344 g
Conclusion
In conclusion, the mass of lead deposited in the second cell can be calculated using the concept of equivalent weight and the formula m(Pb) = m(Ag) x (Equiv. wt. of Pb / Equiv. wt. of Ag). By substituting the values given in the problem, we can determine the mass of lead deposited in the second cell. This calculation demonstrates the relationship between the mass of silver deposited in the first cell and the mass of lead deposited in the second cell, highlighting the importance of understanding the concept of equivalent weight in electrochemistry.
References
- Atkins, P. W., & De Paula, J. (2010). Physical chemistry. Oxford University Press.
- Brown, T. E., & LeMay, H. E. (2014). Chemistry: The Central Science. Pearson Education.
- Petrucci, R. H., Harwood, W. S., & Herring, F. G. (2016). General chemistry: Principles and modern applications. Pearson Education.
Introduction
In our previous article, we explored the concept of two cells in series, one containing silver nitrate and the other containing lead nitrate. We also examined the relationship between the mass of silver deposited in the first cell and the mass of lead deposited in the second cell. In this Q&A article, we will address some of the most frequently asked questions related to this topic.
Q: What is the significance of equivalent weight in electrochemistry?
A: Equivalent weight is a fundamental concept in electrochemistry that represents the mass of a substance that will react with or be reduced by one mole of electrons. Understanding equivalent weight is crucial for calculating the mass of a substance deposited in an electrochemical cell.
Q: How do I calculate the mass of lead deposited in the second cell?
A: To calculate the mass of lead deposited in the second cell, you need to use the formula m(Pb) = m(Ag) x (Equiv. wt. of Pb / Equiv. wt. of Ag), where m(Pb) is the mass of lead deposited, m(Ag) is the mass of silver deposited, and Equiv. wt. of Pb and Equiv. wt. of Ag are the equivalent weights of lead and silver, respectively.
Q: What is the relationship between the mass of silver deposited in the first cell and the mass of lead deposited in the second cell?
A: The mass of lead deposited in the second cell is directly proportional to the mass of silver deposited in the first cell. This is because the electric current flowing through both cells is the same, and the number of moles of electrons passing through both cells is also the same.
Q: Can I use this concept to calculate the mass of other metals deposited in an electrochemical cell?
A: Yes, you can use this concept to calculate the mass of other metals deposited in an electrochemical cell. However, you need to know the equivalent weight of the metal you are interested in and the mass of the metal deposited in the first cell.
Q: What are some common applications of electrochemistry in everyday life?
A: Electrochemistry has numerous applications in everyday life, including:
- Batteries: Electrochemistry is used to develop batteries that power our devices.
- Corrosion protection: Electrochemistry is used to develop coatings that protect metals from corrosion.
- Water treatment: Electrochemistry is used to remove impurities from water.
- Medical devices: Electrochemistry is used to develop medical devices such as pacemakers and implantable cardioverter-defibrillators.
Q: What are some common mistakes to avoid when working with electrochemical cells?
A: Some common mistakes to avoid when working with electrochemical cells include:
- Not calibrating the cell properly
- Not using the correct electrolyte
- Not monitoring the cell's temperature and pressure
- Not following proper safety protocols
Q: Can I use this concept to calculate the mass of a substance deposited in a non-electrochemical cell?
A: No, this concept is specific to electrochemical cells. In a non-electrochemical cell, the mass of a substance deposited is not directly related to the mass of another substance deposited.
Conclusion
In conclusion, understanding the relationship between the mass of silver deposited in the first cell and the mass of lead deposited in the second cell is crucial for various applications in electrochemistry. By using the concept of equivalent weight and the formula m(Pb) = m(Ag) x (Equiv. wt. of Pb / Equiv. wt. of Ag), you can calculate the mass of lead deposited in the second cell. We hope this Q&A article has provided you with a better understanding of this concept and its applications.
References
- Atkins, P. W., & De Paula, J. (2010). Physical chemistry. Oxford University Press.
- Brown, T. E., & LeMay, H. E. (2014). Chemistry: The Central Science. Pearson Education.
- Petrucci, R. H., Harwood, W. S., & Herring, F. G. (2016). General chemistry: Principles and modern applications. Pearson Education.